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The Hashable now want to use protocol instead of hashValue but I can't figure it out


NSObject is Hashable but a protocol that adopts NSObject is not?CFString doesn't conform to protocol Hashable?Why can't I call hash() on an apparently hashable method of an unhashable instance?How to handle hash collisions for Dictionaries in SwiftCreating a protocol that represents hashable objects that can be on or offperformance considerations of hashValue in swift protocol HashableHashable protocol for a protocolConforming to Hashable protocol?How to conform custom class with optional properties to “hashable” protocolWhat is the use of hashable protocol in swift4?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I use to have the following code that worked in Swift 4.2 but is now deprecated in Swift 5:



struct xxx: Hashable {
var hashValue: Int return uniqueIdentifier


When I try to use the new hash(into hasher: inout Hasher) I'm not sure what to do. My uniqueIdentifier starts at 0 and keeps incrementing so it's always unique, no need for anything fancy. But it seams to me that I'm now required to have the following code:



func hash(into hasher: inout Hasher) 
hasher.combine(uniqueIdentifier)



Is this true? I don't see why I need to combined my uniqueIdentifier with some seed. Is there a way I can overcome this or I'm I stuck using hasher.combine(uniqueIdentifier)?










share|improve this question






























    2















    I use to have the following code that worked in Swift 4.2 but is now deprecated in Swift 5:



    struct xxx: Hashable {
    var hashValue: Int return uniqueIdentifier


    When I try to use the new hash(into hasher: inout Hasher) I'm not sure what to do. My uniqueIdentifier starts at 0 and keeps incrementing so it's always unique, no need for anything fancy. But it seams to me that I'm now required to have the following code:



    func hash(into hasher: inout Hasher) 
    hasher.combine(uniqueIdentifier)



    Is this true? I don't see why I need to combined my uniqueIdentifier with some seed. Is there a way I can overcome this or I'm I stuck using hasher.combine(uniqueIdentifier)?










    share|improve this question


























      2












      2








      2


      1






      I use to have the following code that worked in Swift 4.2 but is now deprecated in Swift 5:



      struct xxx: Hashable {
      var hashValue: Int return uniqueIdentifier


      When I try to use the new hash(into hasher: inout Hasher) I'm not sure what to do. My uniqueIdentifier starts at 0 and keeps incrementing so it's always unique, no need for anything fancy. But it seams to me that I'm now required to have the following code:



      func hash(into hasher: inout Hasher) 
      hasher.combine(uniqueIdentifier)



      Is this true? I don't see why I need to combined my uniqueIdentifier with some seed. Is there a way I can overcome this or I'm I stuck using hasher.combine(uniqueIdentifier)?










      share|improve this question














      I use to have the following code that worked in Swift 4.2 but is now deprecated in Swift 5:



      struct xxx: Hashable {
      var hashValue: Int return uniqueIdentifier


      When I try to use the new hash(into hasher: inout Hasher) I'm not sure what to do. My uniqueIdentifier starts at 0 and keeps incrementing so it's always unique, no need for anything fancy. But it seams to me that I'm now required to have the following code:



      func hash(into hasher: inout Hasher) 
      hasher.combine(uniqueIdentifier)



      Is this true? I don't see why I need to combined my uniqueIdentifier with some seed. Is there a way I can overcome this or I'm I stuck using hasher.combine(uniqueIdentifier)?







      swift4.2 hashable swift5






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 28 at 2:16









      mretondomretondo

      1087 bronze badges




      1087 bronze badges

























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