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1

I have a method that accepts any number of INTEGER parameters:
pages(int,int...)

This method is to select some pages of PDF file.

Book Pages stored as a string type like this:

String pages = "1,2,3,6,9";

I want to make this string as the parameter of the method to look like:

pages(1,2,3,6,9);

java string

share|improve this question

edited Mar 31 at 12:28

user3133925

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  Possible duplicate of Splitting String and put it on int array
  
  – chris p bacon
  Mar 28 at 11:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Use varargs, or pass in a collection.
  
  – Tim Biegeleisen
  Mar 28 at 11:11
  

  
  
  
  

add a comment
 | 

1

I have a method that accepts any number of INTEGER parameters:
pages(int,int...)

This method is to select some pages of PDF file.

Book Pages stored as a string type like this:

String pages = "1,2,3,6,9";

I want to make this string as the parameter of the method to look like:

pages(1,2,3,6,9);

java string

share|improve this question

edited Mar 31 at 12:28

user3133925

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  Possible duplicate of Splitting String and put it on int array
  
  – chris p bacon
  Mar 28 at 11:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Use varargs, or pass in a collection.
  
  – Tim Biegeleisen
  Mar 28 at 11:11
  

  
  
  
  

add a comment
 | 

I have a method that accepts any number of INTEGER parameters:
pages(int,int...)

This method is to select some pages of PDF file.

Book Pages stored as a string type like this:

String pages = "1,2,3,6,9";

I want to make this string as the parameter of the method to look like:

pages(1,2,3,6,9);

java string

share|improve this question

edited Mar 31 at 12:28

user3133925

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

String pages = "1,2,3,6,9";

pages(1,2,3,6,9);

share|improve this question

edited Mar 31 at 12:28

user3133925

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

share|improve this question

edited Mar 31 at 12:28

user3133925

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

asked Mar 28 at 11:07

Isam H. AbuaqlainIsam H. Abuaqlain

3677 bronze badges

2 Answers
2

active

oldest

votes

3

This can be easily done with streams:

Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();

You can combine this with varargs to get what you want:

public static void main (String[] args) 
 String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
 int[] arguments =
 Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();
 pages(arguments);


public static void pages(int... numbers) 
 System.out.println("numbers: " + Arrays.toString(numbers));

Output will be:

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: of course varargs isn't needed in this specific case, it's useful only if you plan to call the same method with a variable number of int arguments, otherwise you can just change its signature to pages(int[] numbers).

share|improve this answer

edited Mar 28 at 12:19

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks a lot, it works for me! as I'm new to programming and I'm using java in android programming. when I implement this solution it asked me to upgrade my language from v7 to v8 with lambda. what does it mean??
  
  – Isam H. Abuaqlain
  Mar 28 at 12:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @IsamH.Abuaqlain It means that support for Streams was added starting from java 8 along with support for lambdas, so you can't use java 7 if you want to use Streams, you have to upgrade to java 8
  
  – BackSlash
  Mar 28 at 12:08
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I appreciate it!
  
  – Isam H. Abuaqlain
  Mar 28 at 12:10
  

  
  
  
  

add a comment
 | 

1

Do this :

public class Test 
 public static void main(String..args) 
 String pages = "1,2,3,6,9";
 String[] pagesArr = pages.split(",");
 pages(pagesArr);
 

 static void pages(String... pagesArr) 
 int[] array = Arrays.asList(pagesArr).stream().mapToInt(Integer::parseInt).toArray();
 for (int i = 0; i < array.length; i++) 
 System.out.println(array[i]);
 
 

share|improve this answer

edited Mar 28 at 11:27

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Nice answer! I like the other one as well. It does not convert the array to a List first since a stream can be made from an array.
  
  – John Mercier
  Mar 28 at 12:24
  

  
  
  
  

add a comment
 | 

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3

This can be easily done with streams:

Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();

You can combine this with varargs to get what you want:

public static void main (String[] args) 
 String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
 int[] arguments =
 Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();
 pages(arguments);


public static void pages(int... numbers) 
 System.out.println("numbers: " + Arrays.toString(numbers));

Output will be:

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: of course varargs isn't needed in this specific case, it's useful only if you plan to call the same method with a variable number of int arguments, otherwise you can just change its signature to pages(int[] numbers).

share|improve this answer

edited Mar 28 at 12:19

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks a lot, it works for me! as I'm new to programming and I'm using java in android programming. when I implement this solution it asked me to upgrade my language from v7 to v8 with lambda. what does it mean??
  
  – Isam H. Abuaqlain
  Mar 28 at 12:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @IsamH.Abuaqlain It means that support for Streams was added starting from java 8 along with support for lambdas, so you can't use java 7 if you want to use Streams, you have to upgrade to java 8
  
  – BackSlash
  Mar 28 at 12:08
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I appreciate it!
  
  – Isam H. Abuaqlain
  Mar 28 at 12:10
  

  
  
  
  

add a comment
 | 

3

This can be easily done with streams:

Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();

You can combine this with varargs to get what you want:

public static void main (String[] args) 
 String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
 int[] arguments =
 Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();
 pages(arguments);


public static void pages(int... numbers) 
 System.out.println("numbers: " + Arrays.toString(numbers));

Output will be:

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: of course varargs isn't needed in this specific case, it's useful only if you plan to call the same method with a variable number of int arguments, otherwise you can just change its signature to pages(int[] numbers).

share|improve this answer

edited Mar 28 at 12:19

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks a lot, it works for me! as I'm new to programming and I'm using java in android programming. when I implement this solution it asked me to upgrade my language from v7 to v8 with lambda. what does it mean??
  
  – Isam H. Abuaqlain
  Mar 28 at 12:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @IsamH.Abuaqlain It means that support for Streams was added starting from java 8 along with support for lambdas, so you can't use java 7 if you want to use Streams, you have to upgrade to java 8
  
  – BackSlash
  Mar 28 at 12:08
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I appreciate it!
  
  – Isam H. Abuaqlain
  Mar 28 at 12:10
  

  
  
  
  

add a comment
 | 

This can be easily done with streams:

Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();

You can combine this with varargs to get what you want:

public static void main (String[] args) 
 String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
 int[] arguments =
 Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();
 pages(arguments);


public static void pages(int... numbers) 
 System.out.println("numbers: " + Arrays.toString(numbers));

Output will be:

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: of course varargs isn't needed in this specific case, it's useful only if you plan to call the same method with a variable number of int arguments, otherwise you can just change its signature to pages(int[] numbers).

share|improve this answer

edited Mar 28 at 12:19

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();

public static void main (String[] args) 
 String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
 int[] arguments =
 Stream
 .of(commaSeparated.split(","))
 .mapToInt(Integer::parseInt)
 .toArray();
 pages(arguments);


public static void pages(int... numbers) 
 System.out.println("numbers: " + Arrays.toString(numbers));

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

share|improve this answer

edited Mar 28 at 12:19

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

answered Mar 28 at 11:15

BackSlashBackSlash

17.1k1717 gold badges6363 silver badges107107 bronze badges

1

Do this :

public class Test 
 public static void main(String..args) 
 String pages = "1,2,3,6,9";
 String[] pagesArr = pages.split(",");
 pages(pagesArr);
 

 static void pages(String... pagesArr) 
 int[] array = Arrays.asList(pagesArr).stream().mapToInt(Integer::parseInt).toArray();
 for (int i = 0; i < array.length; i++) 
 System.out.println(array[i]);
 
 

share|improve this answer

edited Mar 28 at 11:27

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Nice answer! I like the other one as well. It does not convert the array to a List first since a stream can be made from an array.
  
  – John Mercier
  Mar 28 at 12:24
  

  
  
  
  

add a comment
 | 

1

Do this :

public class Test 
 public static void main(String..args) 
 String pages = "1,2,3,6,9";
 String[] pagesArr = pages.split(",");
 pages(pagesArr);
 

 static void pages(String... pagesArr) 
 int[] array = Arrays.asList(pagesArr).stream().mapToInt(Integer::parseInt).toArray();
 for (int i = 0; i < array.length; i++) 
 System.out.println(array[i]);
 
 

share|improve this answer

edited Mar 28 at 11:27

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Nice answer! I like the other one as well. It does not convert the array to a List first since a stream can be made from an array.
  
  – John Mercier
  Mar 28 at 12:24
  

  
  
  
  

add a comment
 | 

Do this :

public class Test 
 public static void main(String..args) 
 String pages = "1,2,3,6,9";
 String[] pagesArr = pages.split(",");
 pages(pagesArr);
 

 static void pages(String... pagesArr) 
 int[] array = Arrays.asList(pagesArr).stream().mapToInt(Integer::parseInt).toArray();
 for (int i = 0; i < array.length; i++) 
 System.out.println(array[i]);
 
 

share|improve this answer

edited Mar 28 at 11:27

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

public class Test 
 public static void main(String..args) 
 String pages = "1,2,3,6,9";
 String[] pagesArr = pages.split(",");
 pages(pagesArr);
 

 static void pages(String... pagesArr) 
 int[] array = Arrays.asList(pagesArr).stream().mapToInt(Integer::parseInt).toArray();
 for (int i = 0; i < array.length; i++) 
 System.out.println(array[i]);
 
 

share|improve this answer

edited Mar 28 at 11:27

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges

answered Mar 28 at 11:22

Anish B.Anish B.

1,09011 gold badge55 silver badges1818 bronze badges