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Using getters with this. in java

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0

I am doing a project for CS, and I just realized that I do not understand the mechanics behind the this. java reference and getters. Specifically, if I have the following:

class Circle
 private int radius;


public Circle(int radius)
 this.radius = radius;


public int getRadius()
 return radius;

• Why is it that for the constructor, I use this.radius to reference the data field "radius" in the Circle class, but for the constructor, I have this.radius = radius?




• Does it make a difference whether or not I use the this. so long as it is the only data field named radius?




• I just tested it on Sublime, and it outputs the same result.
  
  Just according to my own logic, would it not make more sense to use this.radius to return the radius in the getRadius() getter instead of just return radius because I am referring to the data field in the object Circle?

I really appreciate all the help I can get!

java oop getter

share|improve this question

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As your constructor public Circle(int radius)... has parameter name radius which is same like the global parameter name, and you are assigning global parameter(radius) to local parameter (radius) and as there is an ambiguity in names. To simplify we refer Global parameter with this. Like this.radius = radius
  
  – Kavita_p
  Mar 24 at 19:09
  
  

  
  
  
  

add a comment | 

0

I am doing a project for CS, and I just realized that I do not understand the mechanics behind the this. java reference and getters. Specifically, if I have the following:

class Circle
 private int radius;


public Circle(int radius)
 this.radius = radius;


public int getRadius()
 return radius;

• Why is it that for the constructor, I use this.radius to reference the data field "radius" in the Circle class, but for the constructor, I have this.radius = radius?




• Does it make a difference whether or not I use the this. so long as it is the only data field named radius?




• I just tested it on Sublime, and it outputs the same result.
  
  Just according to my own logic, would it not make more sense to use this.radius to return the radius in the getRadius() getter instead of just return radius because I am referring to the data field in the object Circle?

I really appreciate all the help I can get!

java oop getter

share|improve this question

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As your constructor public Circle(int radius)... has parameter name radius which is same like the global parameter name, and you are assigning global parameter(radius) to local parameter (radius) and as there is an ambiguity in names. To simplify we refer Global parameter with this. Like this.radius = radius
  
  – Kavita_p
  Mar 24 at 19:09
  
  

  
  
  
  

add a comment | 

I am doing a project for CS, and I just realized that I do not understand the mechanics behind the this. java reference and getters. Specifically, if I have the following:

class Circle
 private int radius;


public Circle(int radius)
 this.radius = radius;


public int getRadius()
 return radius;

• Why is it that for the constructor, I use this.radius to reference the data field "radius" in the Circle class, but for the constructor, I have this.radius = radius?




• Does it make a difference whether or not I use the this. so long as it is the only data field named radius?




• I just tested it on Sublime, and it outputs the same result.
  
  Just according to my own logic, would it not make more sense to use this.radius to return the radius in the getRadius() getter instead of just return radius because I am referring to the data field in the object Circle?

I really appreciate all the help I can get!

java oop getter

share|improve this question

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

class Circle
 private int radius;


public Circle(int radius)
 this.radius = radius;


public int getRadius()
 return radius;

share|improve this question

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

share|improve this question

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

edited Mar 24 at 19:09

YCF_L

35k104687

edited Mar 24 at 19:09

YCF_L

35k104687

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

asked Mar 24 at 19:02

Daanyal AkhtarDaanyal Akhtar

11

3 Answers
3

active

oldest

votes

4

It's because radius is the name of both parameter of constructor and field of the class. To disambiguate those this keyword is used. In case of getter this is not needed, but also won't hurt. Some formatters add this by default, it's equivalent to:

public int getRadius()
 return this.radius;

share|improve this answer

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

add a comment | 

2

You don't need this in the constructor if you do not shadow the local name. That is with

public Circle(int r)
 this.radius = r;

You can write

public Circle(int r)
 radius = r;

The this is only required when it is used to specify which radius you are referring to.

share|improve this answer

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

add a comment | 

0

Actually when you refer to this.radius that means you use a class field variable. Otherwise (in your code) you may re-assign your radius as an argument in a given constructor that is may be unwanted in your case. To distinguish it you must either use different name of a variable or use this.

share|improve this answer

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

add a comment | 

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4

It's because radius is the name of both parameter of constructor and field of the class. To disambiguate those this keyword is used. In case of getter this is not needed, but also won't hurt. Some formatters add this by default, it's equivalent to:

public int getRadius()
 return this.radius;

share|improve this answer

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

add a comment | 

4

It's because radius is the name of both parameter of constructor and field of the class. To disambiguate those this keyword is used. In case of getter this is not needed, but also won't hurt. Some formatters add this by default, it's equivalent to:

public int getRadius()
 return this.radius;

share|improve this answer

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

add a comment | 

It's because radius is the name of both parameter of constructor and field of the class. To disambiguate those this keyword is used. In case of getter this is not needed, but also won't hurt. Some formatters add this by default, it's equivalent to:

public int getRadius()
 return this.radius;

share|improve this answer

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

public int getRadius()
 return this.radius;

share|improve this answer

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

answered Mar 24 at 19:04

AndronicusAndronicus

7,54432035

2

You don't need this in the constructor if you do not shadow the local name. That is with

public Circle(int r)
 this.radius = r;

You can write

public Circle(int r)
 radius = r;

The this is only required when it is used to specify which radius you are referring to.

share|improve this answer

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

add a comment | 

2

You don't need this in the constructor if you do not shadow the local name. That is with

public Circle(int r)
 this.radius = r;

You can write

public Circle(int r)
 radius = r;

The this is only required when it is used to specify which radius you are referring to.

share|improve this answer

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

add a comment | 

You don't need this in the constructor if you do not shadow the local name. That is with

public Circle(int r)
 this.radius = r;

You can write

public Circle(int r)
 radius = r;

The this is only required when it is used to specify which radius you are referring to.

share|improve this answer

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

public Circle(int r)
 this.radius = r;

public Circle(int r)
 radius = r;

share|improve this answer

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

answered Mar 24 at 19:06

Elliott FrischElliott Frisch

158k1399193

0

Actually when you refer to this.radius that means you use a class field variable. Otherwise (in your code) you may re-assign your radius as an argument in a given constructor that is may be unwanted in your case. To distinguish it you must either use different name of a variable or use this.

share|improve this answer

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

add a comment | 

0

Actually when you refer to this.radius that means you use a class field variable. Otherwise (in your code) you may re-assign your radius as an argument in a given constructor that is may be unwanted in your case. To distinguish it you must either use different name of a variable or use this.

share|improve this answer

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

add a comment | 

Actually when you refer to this.radius that means you use a class field variable. Otherwise (in your code) you may re-assign your radius as an argument in a given constructor that is may be unwanted in your case. To distinguish it you must either use different name of a variable or use this.

share|improve this answer

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

share|improve this answer

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173

answered Mar 24 at 19:09

Тимур БибарсовТимур Бибарсов

173