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Doing an Enthuware OCP question. Can't understand this at all
Path.relativize behaviour when “dot directory” is includedMaking a class follow OCP - Factoring functions into objectsIf I have a full unit test suite for an application, must I still apply the Open/Closed Principle (OCP)?How do you write code that conforms to the OCP?Good examples of OCP in open source librariesUnderstanding the relationship between Liskov and OCPHow we can use OCP with delegation?How to modify the function to satisfy OCP?OCP Java SE 6 Practice Questions - WeatherTest EnumDo OCP and DIP break YAGNI?Solid OCP violation consequences
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
What will the following code fragment print?
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1.relativize(p2);
System.out.println(p3);
Apparently the answer is:
........index.html
But I don't see how whatsoever. p1 starts off in c, then into the personal directory. Then the single full stop means the current directory. Then into photos. Then the double full stops means go up a directory so you should be back into photos. Then readme.txt should be in the photos folder. Which would then read as c -> personal -> [current_directory] -> photos -> readme.txt.
That means you should only need three .. before going into index. How is it four?
open-closed-principle
add a comment |
What will the following code fragment print?
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1.relativize(p2);
System.out.println(p3);
Apparently the answer is:
........index.html
But I don't see how whatsoever. p1 starts off in c, then into the personal directory. Then the single full stop means the current directory. Then into photos. Then the double full stops means go up a directory so you should be back into photos. Then readme.txt should be in the photos folder. Which would then read as c -> personal -> [current_directory] -> photos -> readme.txt.
That means you should only need three .. before going into index. How is it four?
open-closed-principle
Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09
add a comment |
What will the following code fragment print?
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1.relativize(p2);
System.out.println(p3);
Apparently the answer is:
........index.html
But I don't see how whatsoever. p1 starts off in c, then into the personal directory. Then the single full stop means the current directory. Then into photos. Then the double full stops means go up a directory so you should be back into photos. Then readme.txt should be in the photos folder. Which would then read as c -> personal -> [current_directory] -> photos -> readme.txt.
That means you should only need three .. before going into index. How is it four?
open-closed-principle
What will the following code fragment print?
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1.relativize(p2);
System.out.println(p3);
Apparently the answer is:
........index.html
But I don't see how whatsoever. p1 starts off in c, then into the personal directory. Then the single full stop means the current directory. Then into photos. Then the double full stops means go up a directory so you should be back into photos. Then readme.txt should be in the photos folder. Which would then read as c -> personal -> [current_directory] -> photos -> readme.txt.
That means you should only need three .. before going into index. How is it four?
open-closed-principle
open-closed-principle
asked Mar 25 at 19:30
jenny lorinejenny lorine
774 bronze badges
774 bronze badges
Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09
add a comment |
Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09
Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09
Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09
add a comment |
1 Answer
1
active
oldest
votes
The path segments .
and ..
in p1
, are considered just as another name by relativize
, not a special case for the current directory or the parent directory, respectively.
You need to normalize the path to eliminate redundant name elements like .
and ..
:
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p1Normalized = p1.normalize();
System.out.println(p1Normalized);
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1Normalized.relativize(p2);
System.out.println(p3);
The output is:
c:\personal\readme.txt
..index.html
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The path segments .
and ..
in p1
, are considered just as another name by relativize
, not a special case for the current directory or the parent directory, respectively.
You need to normalize the path to eliminate redundant name elements like .
and ..
:
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p1Normalized = p1.normalize();
System.out.println(p1Normalized);
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1Normalized.relativize(p2);
System.out.println(p3);
The output is:
c:\personal\readme.txt
..index.html
add a comment |
The path segments .
and ..
in p1
, are considered just as another name by relativize
, not a special case for the current directory or the parent directory, respectively.
You need to normalize the path to eliminate redundant name elements like .
and ..
:
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p1Normalized = p1.normalize();
System.out.println(p1Normalized);
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1Normalized.relativize(p2);
System.out.println(p3);
The output is:
c:\personal\readme.txt
..index.html
add a comment |
The path segments .
and ..
in p1
, are considered just as another name by relativize
, not a special case for the current directory or the parent directory, respectively.
You need to normalize the path to eliminate redundant name elements like .
and ..
:
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p1Normalized = p1.normalize();
System.out.println(p1Normalized);
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1Normalized.relativize(p2);
System.out.println(p3);
The output is:
c:\personal\readme.txt
..index.html
The path segments .
and ..
in p1
, are considered just as another name by relativize
, not a special case for the current directory or the parent directory, respectively.
You need to normalize the path to eliminate redundant name elements like .
and ..
:
Path p1 = Paths.get("c:\personal\.\photos\..\readme.txt");
Path p1Normalized = p1.normalize();
System.out.println(p1Normalized);
Path p2 = Paths.get("c:\personal\index.html");
Path p3 = p1Normalized.relativize(p2);
System.out.println(p3);
The output is:
c:\personal\readme.txt
..index.html
answered Mar 26 at 16:39
gparisgparis
1,0329 silver badges26 bronze badges
1,0329 silver badges26 bronze badges
add a comment |
add a comment |
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Check this answer to a similar question: stackoverflow.com/a/34271865/634412
– gparis
Mar 26 at 15:09