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How to find an Element by index in selenium webdriver for java


How to find Element [For Selenium]List.get(index) to extend xpath for another List <WebElement>How do I efficiently iterate over each entry in a Java Map?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?How do I generate random integers within a specific range in Java?How to get an enum value from a string value in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?How to take screenshot with Selenium WebDriverHow to split a string in JavaHow do I convert a String to an int in Java?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4















Im trying to automate the Google Images page:



https://www.google.com/search?q=pluralsight&biw=1416&bih=685&source=lnms&tbm=isch&sa=X&ei=qGd6VN6bEZTooAT7q4C4BQ&sqi=2&ved=0CAgQ_AUoAw



All the images have the same class but no id and the results are constantly changing. So I would like to be able to click on the images based on their index.



I know how to do it in C#...but I cant figure out how to specify in the index in Java. When I try to select an index beyond 0, I get and IndexOutOfBounds error, but i cant figure out why



WebElement image = chromeDriver.findElement(By.className("rg_di"));
WebElement imageLink = image.findElements(By.tagName("a")).get(1);
imageLink.click();


Here is the entire code im using...any help would be appreciated:



 System.setProperty("webdriver.chrome.driver", "/Users/user/chromedriver");
WebDriver chromeDriver = new ChromeDriver();
chromeDriver.get("http://www.google.com");

WebElement searchBox = chromeDriver.findElement(By.id("gbqfq"));
searchBox.sendKeys("pluralsight");
searchBox.sendKeys(Keys.RETURN);

chromeDriver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

WebElement imagesLink = chromeDriver.findElement(By.linkText("Images"));
imagesLink.click();

WebElement image = chromeDriver.findElement(By.className("rg_di"));
WebElement imageLink = image.findElements(By.tagName("a")).get(1);
imageLink.click();


Any help would be greatly appreciated










share|improve this question




























    4















    Im trying to automate the Google Images page:



    https://www.google.com/search?q=pluralsight&biw=1416&bih=685&source=lnms&tbm=isch&sa=X&ei=qGd6VN6bEZTooAT7q4C4BQ&sqi=2&ved=0CAgQ_AUoAw



    All the images have the same class but no id and the results are constantly changing. So I would like to be able to click on the images based on their index.



    I know how to do it in C#...but I cant figure out how to specify in the index in Java. When I try to select an index beyond 0, I get and IndexOutOfBounds error, but i cant figure out why



    WebElement image = chromeDriver.findElement(By.className("rg_di"));
    WebElement imageLink = image.findElements(By.tagName("a")).get(1);
    imageLink.click();


    Here is the entire code im using...any help would be appreciated:



     System.setProperty("webdriver.chrome.driver", "/Users/user/chromedriver");
    WebDriver chromeDriver = new ChromeDriver();
    chromeDriver.get("http://www.google.com");

    WebElement searchBox = chromeDriver.findElement(By.id("gbqfq"));
    searchBox.sendKeys("pluralsight");
    searchBox.sendKeys(Keys.RETURN);

    chromeDriver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

    WebElement imagesLink = chromeDriver.findElement(By.linkText("Images"));
    imagesLink.click();

    WebElement image = chromeDriver.findElement(By.className("rg_di"));
    WebElement imageLink = image.findElements(By.tagName("a")).get(1);
    imageLink.click();


    Any help would be greatly appreciated










    share|improve this question
























      4












      4








      4








      Im trying to automate the Google Images page:



      https://www.google.com/search?q=pluralsight&biw=1416&bih=685&source=lnms&tbm=isch&sa=X&ei=qGd6VN6bEZTooAT7q4C4BQ&sqi=2&ved=0CAgQ_AUoAw



      All the images have the same class but no id and the results are constantly changing. So I would like to be able to click on the images based on their index.



      I know how to do it in C#...but I cant figure out how to specify in the index in Java. When I try to select an index beyond 0, I get and IndexOutOfBounds error, but i cant figure out why



      WebElement image = chromeDriver.findElement(By.className("rg_di"));
      WebElement imageLink = image.findElements(By.tagName("a")).get(1);
      imageLink.click();


      Here is the entire code im using...any help would be appreciated:



       System.setProperty("webdriver.chrome.driver", "/Users/user/chromedriver");
      WebDriver chromeDriver = new ChromeDriver();
      chromeDriver.get("http://www.google.com");

      WebElement searchBox = chromeDriver.findElement(By.id("gbqfq"));
      searchBox.sendKeys("pluralsight");
      searchBox.sendKeys(Keys.RETURN);

      chromeDriver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

      WebElement imagesLink = chromeDriver.findElement(By.linkText("Images"));
      imagesLink.click();

      WebElement image = chromeDriver.findElement(By.className("rg_di"));
      WebElement imageLink = image.findElements(By.tagName("a")).get(1);
      imageLink.click();


      Any help would be greatly appreciated










      share|improve this question














      Im trying to automate the Google Images page:



      https://www.google.com/search?q=pluralsight&biw=1416&bih=685&source=lnms&tbm=isch&sa=X&ei=qGd6VN6bEZTooAT7q4C4BQ&sqi=2&ved=0CAgQ_AUoAw



      All the images have the same class but no id and the results are constantly changing. So I would like to be able to click on the images based on their index.



      I know how to do it in C#...but I cant figure out how to specify in the index in Java. When I try to select an index beyond 0, I get and IndexOutOfBounds error, but i cant figure out why



      WebElement image = chromeDriver.findElement(By.className("rg_di"));
      WebElement imageLink = image.findElements(By.tagName("a")).get(1);
      imageLink.click();


      Here is the entire code im using...any help would be appreciated:



       System.setProperty("webdriver.chrome.driver", "/Users/user/chromedriver");
      WebDriver chromeDriver = new ChromeDriver();
      chromeDriver.get("http://www.google.com");

      WebElement searchBox = chromeDriver.findElement(By.id("gbqfq"));
      searchBox.sendKeys("pluralsight");
      searchBox.sendKeys(Keys.RETURN);

      chromeDriver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

      WebElement imagesLink = chromeDriver.findElement(By.linkText("Images"));
      imagesLink.click();

      WebElement image = chromeDriver.findElement(By.className("rg_di"));
      WebElement imageLink = image.findElements(By.tagName("a")).get(1);
      imageLink.click();


      Any help would be greatly appreciated







      java selenium selenium-webdriver






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 30 '14 at 0:52









      Tim BolandTim Boland

      1,1683 gold badges18 silver badges35 bronze badges




      1,1683 gold badges18 silver badges35 bronze badges






















          4 Answers
          4






          active

          oldest

          votes


















          4














          In your code:



          WebElement image = chromeDriver.findElement(By.className("rg_di"));


          will return the first element found on the page with a class of "rg_di".



          That element has only one <a href=... /a> tag in it.



          You are getting an IndexOutOfBounds exception because you are asking for the second one (zero based indexing). If you change your final WebElement to:



          WebElement imageLink = image.findElements(By.tagName("a")).get(0);


          The code should work for you with that small change.



          This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):



          public static void main(String[] args) 
          // I don't have Chrome installed >.<
          WebDriver driver = new FirefoxDriver();

          driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

          driver.get("http://www.google.com");

          WebElement searchBox = driver.findElement(By.id("gbqfq"));
          searchBox.sendKeys("pluralsight");
          searchBox.sendKeys(Keys.RETURN);

          driver.findElement(By.linkText("Images")).click();

          WebElement image = driver.findElement(By.className("rg_di"));
          image.findElements(By.tagName("a")).get(0).click();

          // super-shortened version:
          // driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();






          share|improve this answer























          • Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

            – Tim Boland
            Nov 30 '14 at 5:04


















          2














          I'd do:



          List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));

          we.get(1) //should get first element in array





          share|improve this answer






























            2














            This code worked very well when we have similar object properties for same web buttons, then using



            List<WebElement> we = webdriver.findElements(By.cssSelector(""));


            and then getting



             we.get(1).click();


            Thank you so much for posting this answer.






            share|improve this answer
































              0














              Another solution may be like this:
              If the class name and the index of the web element are known, then following code works:



              driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();





              share|improve this answer



























                Your Answer






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                4 Answers
                4






                active

                oldest

                votes








                4 Answers
                4






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                4














                In your code:



                WebElement image = chromeDriver.findElement(By.className("rg_di"));


                will return the first element found on the page with a class of "rg_di".



                That element has only one <a href=... /a> tag in it.



                You are getting an IndexOutOfBounds exception because you are asking for the second one (zero based indexing). If you change your final WebElement to:



                WebElement imageLink = image.findElements(By.tagName("a")).get(0);


                The code should work for you with that small change.



                This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):



                public static void main(String[] args) 
                // I don't have Chrome installed >.<
                WebDriver driver = new FirefoxDriver();

                driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

                driver.get("http://www.google.com");

                WebElement searchBox = driver.findElement(By.id("gbqfq"));
                searchBox.sendKeys("pluralsight");
                searchBox.sendKeys(Keys.RETURN);

                driver.findElement(By.linkText("Images")).click();

                WebElement image = driver.findElement(By.className("rg_di"));
                image.findElements(By.tagName("a")).get(0).click();

                // super-shortened version:
                // driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();






                share|improve this answer























                • Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                  – Tim Boland
                  Nov 30 '14 at 5:04















                4














                In your code:



                WebElement image = chromeDriver.findElement(By.className("rg_di"));


                will return the first element found on the page with a class of "rg_di".



                That element has only one <a href=... /a> tag in it.



                You are getting an IndexOutOfBounds exception because you are asking for the second one (zero based indexing). If you change your final WebElement to:



                WebElement imageLink = image.findElements(By.tagName("a")).get(0);


                The code should work for you with that small change.



                This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):



                public static void main(String[] args) 
                // I don't have Chrome installed >.<
                WebDriver driver = new FirefoxDriver();

                driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

                driver.get("http://www.google.com");

                WebElement searchBox = driver.findElement(By.id("gbqfq"));
                searchBox.sendKeys("pluralsight");
                searchBox.sendKeys(Keys.RETURN);

                driver.findElement(By.linkText("Images")).click();

                WebElement image = driver.findElement(By.className("rg_di"));
                image.findElements(By.tagName("a")).get(0).click();

                // super-shortened version:
                // driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();






                share|improve this answer























                • Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                  – Tim Boland
                  Nov 30 '14 at 5:04













                4












                4








                4







                In your code:



                WebElement image = chromeDriver.findElement(By.className("rg_di"));


                will return the first element found on the page with a class of "rg_di".



                That element has only one <a href=... /a> tag in it.



                You are getting an IndexOutOfBounds exception because you are asking for the second one (zero based indexing). If you change your final WebElement to:



                WebElement imageLink = image.findElements(By.tagName("a")).get(0);


                The code should work for you with that small change.



                This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):



                public static void main(String[] args) 
                // I don't have Chrome installed >.<
                WebDriver driver = new FirefoxDriver();

                driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

                driver.get("http://www.google.com");

                WebElement searchBox = driver.findElement(By.id("gbqfq"));
                searchBox.sendKeys("pluralsight");
                searchBox.sendKeys(Keys.RETURN);

                driver.findElement(By.linkText("Images")).click();

                WebElement image = driver.findElement(By.className("rg_di"));
                image.findElements(By.tagName("a")).get(0).click();

                // super-shortened version:
                // driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();






                share|improve this answer













                In your code:



                WebElement image = chromeDriver.findElement(By.className("rg_di"));


                will return the first element found on the page with a class of "rg_di".



                That element has only one <a href=... /a> tag in it.



                You are getting an IndexOutOfBounds exception because you are asking for the second one (zero based indexing). If you change your final WebElement to:



                WebElement imageLink = image.findElements(By.tagName("a")).get(0);


                The code should work for you with that small change.



                This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):



                public static void main(String[] args) 
                // I don't have Chrome installed >.<
                WebDriver driver = new FirefoxDriver();

                driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

                driver.get("http://www.google.com");

                WebElement searchBox = driver.findElement(By.id("gbqfq"));
                searchBox.sendKeys("pluralsight");
                searchBox.sendKeys(Keys.RETURN);

                driver.findElement(By.linkText("Images")).click();

                WebElement image = driver.findElement(By.className("rg_di"));
                image.findElements(By.tagName("a")).get(0).click();

                // super-shortened version:
                // driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 30 '14 at 4:45









                cbarrerascbarreras

                954 bronze badges




                954 bronze badges












                • Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                  – Tim Boland
                  Nov 30 '14 at 5:04

















                • Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                  – Tim Boland
                  Nov 30 '14 at 5:04
















                Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                – Tim Boland
                Nov 30 '14 at 5:04





                Yes i updated the code to use the id of the ordered list that all of the image links are in...so now i can get to each of them by index

                – Tim Boland
                Nov 30 '14 at 5:04













                2














                I'd do:



                List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));

                we.get(1) //should get first element in array





                share|improve this answer



























                  2














                  I'd do:



                  List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));

                  we.get(1) //should get first element in array





                  share|improve this answer

























                    2












                    2








                    2







                    I'd do:



                    List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));

                    we.get(1) //should get first element in array





                    share|improve this answer













                    I'd do:



                    List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));

                    we.get(1) //should get first element in array






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 30 '14 at 2:11









                    bcarbcar

                    6647 silver badges19 bronze badges




                    6647 silver badges19 bronze badges





















                        2














                        This code worked very well when we have similar object properties for same web buttons, then using



                        List<WebElement> we = webdriver.findElements(By.cssSelector(""));


                        and then getting



                         we.get(1).click();


                        Thank you so much for posting this answer.






                        share|improve this answer





























                          2














                          This code worked very well when we have similar object properties for same web buttons, then using



                          List<WebElement> we = webdriver.findElements(By.cssSelector(""));


                          and then getting



                           we.get(1).click();


                          Thank you so much for posting this answer.






                          share|improve this answer



























                            2












                            2








                            2







                            This code worked very well when we have similar object properties for same web buttons, then using



                            List<WebElement> we = webdriver.findElements(By.cssSelector(""));


                            and then getting



                             we.get(1).click();


                            Thank you so much for posting this answer.






                            share|improve this answer















                            This code worked very well when we have similar object properties for same web buttons, then using



                            List<WebElement> we = webdriver.findElements(By.cssSelector(""));


                            and then getting



                             we.get(1).click();


                            Thank you so much for posting this answer.







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Mar 18 '16 at 2:39









                            BMW

                            24.7k5 gold badges60 silver badges75 bronze badges




                            24.7k5 gold badges60 silver badges75 bronze badges










                            answered Mar 18 '16 at 2:37









                            Pardhiva EPardhiva E

                            211 bronze badge




                            211 bronze badge





















                                0














                                Another solution may be like this:
                                If the class name and the index of the web element are known, then following code works:



                                driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();





                                share|improve this answer





























                                  0














                                  Another solution may be like this:
                                  If the class name and the index of the web element are known, then following code works:



                                  driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();





                                  share|improve this answer



























                                    0












                                    0








                                    0







                                    Another solution may be like this:
                                    If the class name and the index of the web element are known, then following code works:



                                    driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();





                                    share|improve this answer















                                    Another solution may be like this:
                                    If the class name and the index of the web element are known, then following code works:



                                    driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();






                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited Mar 25 at 19:54









                                    trincot

                                    138k18 gold badges105 silver badges143 bronze badges




                                    138k18 gold badges105 silver badges143 bronze badges










                                    answered Mar 25 at 19:33









                                    Beytullah uzunBeytullah uzun

                                    1




                                    1



























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