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Python Identify (Convert) text to date

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1

I am trying to find best way to convert "Friday 1st March 2019" or "Saturday 2nd March 2019" to python datetime object.

I tried by splitting, than had thoughts on regex, but I am quite sure there is more 'elegant' way ofdoing it

From string "Friday 1st March 2019" I expect 01-03-2019 or 2019-03-01

TNX!

python date formatting

share|improve this question

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

add a comment | 

1

I am trying to find best way to convert "Friday 1st March 2019" or "Saturday 2nd March 2019" to python datetime object.

I tried by splitting, than had thoughts on regex, but I am quite sure there is more 'elegant' way ofdoing it

From string "Friday 1st March 2019" I expect 01-03-2019 or 2019-03-01

TNX!

python date formatting

share|improve this question

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

add a comment | 

I am trying to find best way to convert "Friday 1st March 2019" or "Saturday 2nd March 2019" to python datetime object.

I tried by splitting, than had thoughts on regex, but I am quite sure there is more 'elegant' way ofdoing it

From string "Friday 1st March 2019" I expect 01-03-2019 or 2019-03-01

TNX!

python date formatting

share|improve this question

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

share|improve this question

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

share|improve this question

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

asked Mar 25 at 20:00

JovanJovan

751313 bronze badges

3 Answers
3

active

oldest

votes

6

Maybe not the "best" way, but a very easy way is dateutil's parser

from dateutil import parser
parser.parse("Friday 1st March 2019")

Returns:

datetime.datetime(2019, 3, 1, 0, 0)

It can pretty much be wrapped up as:

from dateutil import parser
from datetime import datetime as dt
dt.strftime(parser.parse("Friday 1st March 2019"), "%d-%m-%Y")

Returning:

'01-03-2019'

share|improve this answer

edited Mar 25 at 20:29

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Exactly what I have been asking for! Thank you tgikal!
  
  – Jovan
  Mar 25 at 22:18
  

  
  
  
  

add a comment | 

1

Please refer to an already answered question:
How to get the datetime from a string containing '2nd' for the date in Python?

As I can only repeat, solution is to use dateutil parser:

from dateutil.parser import parse

your_string = "Friday 1st March 2019"
date_obj = parse(your_string)

Behind the scenes, I guess the "1st", and "2nd" parts are extracted somehow (e.g. splitting+regex) and simplified to its day value only.
According to an input like that, the common datetime library can be used with proper date format string:

import datetime
simplified_txt = "Friday 1 March 2019"
datetime_obj = datetime.datetime.strptime(simplified_txt,"%A %d %B %Y")

share|improve this answer

edited Mar 25 at 20:48

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

add a comment | 

1

You are going to face issues with 1st, 2nd.

So, try this (without adding any external/third party library):

import re
from datetime import datetime as dt
ds = "Friday 1st March 2019"
parts = ds.split(" ")
ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
)
a = dt.strptime(ds, "%A %d %B %Y")

If you want to make it into a function, do this:

def convdate(s):
 parts = s.split(" ")
 ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
 )
 return dt.strptime(ds, "%A %d %B %Y")

share|improve this answer

edited Mar 25 at 22:26

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

add a comment | 

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6

Maybe not the "best" way, but a very easy way is dateutil's parser

from dateutil import parser
parser.parse("Friday 1st March 2019")

Returns:

datetime.datetime(2019, 3, 1, 0, 0)

It can pretty much be wrapped up as:

from dateutil import parser
from datetime import datetime as dt
dt.strftime(parser.parse("Friday 1st March 2019"), "%d-%m-%Y")

Returning:

'01-03-2019'

share|improve this answer

edited Mar 25 at 20:29

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Exactly what I have been asking for! Thank you tgikal!
  
  – Jovan
  Mar 25 at 22:18
  

  
  
  
  

add a comment | 

6

Maybe not the "best" way, but a very easy way is dateutil's parser

from dateutil import parser
parser.parse("Friday 1st March 2019")

Returns:

datetime.datetime(2019, 3, 1, 0, 0)

It can pretty much be wrapped up as:

from dateutil import parser
from datetime import datetime as dt
dt.strftime(parser.parse("Friday 1st March 2019"), "%d-%m-%Y")

Returning:

'01-03-2019'

share|improve this answer

edited Mar 25 at 20:29

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Exactly what I have been asking for! Thank you tgikal!
  
  – Jovan
  Mar 25 at 22:18
  

  
  
  
  

add a comment | 

Maybe not the "best" way, but a very easy way is dateutil's parser

from dateutil import parser
parser.parse("Friday 1st March 2019")

Returns:

datetime.datetime(2019, 3, 1, 0, 0)

It can pretty much be wrapped up as:

from dateutil import parser
from datetime import datetime as dt
dt.strftime(parser.parse("Friday 1st March 2019"), "%d-%m-%Y")

Returning:

'01-03-2019'

share|improve this answer

edited Mar 25 at 20:29

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

from dateutil import parser
parser.parse("Friday 1st March 2019")

datetime.datetime(2019, 3, 1, 0, 0)

from dateutil import parser
from datetime import datetime as dt
dt.strftime(parser.parse("Friday 1st March 2019"), "%d-%m-%Y")

'01-03-2019'

share|improve this answer

edited Mar 25 at 20:29

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

answered Mar 25 at 20:21

tgikaltgikal

96811 gold badge66 silver badges1414 bronze badges

1

Please refer to an already answered question:
How to get the datetime from a string containing '2nd' for the date in Python?

As I can only repeat, solution is to use dateutil parser:

from dateutil.parser import parse

your_string = "Friday 1st March 2019"
date_obj = parse(your_string)

Behind the scenes, I guess the "1st", and "2nd" parts are extracted somehow (e.g. splitting+regex) and simplified to its day value only.
According to an input like that, the common datetime library can be used with proper date format string:

import datetime
simplified_txt = "Friday 1 March 2019"
datetime_obj = datetime.datetime.strptime(simplified_txt,"%A %d %B %Y")

share|improve this answer

edited Mar 25 at 20:48

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

add a comment | 

1

Please refer to an already answered question:
How to get the datetime from a string containing '2nd' for the date in Python?

As I can only repeat, solution is to use dateutil parser:

from dateutil.parser import parse

your_string = "Friday 1st March 2019"
date_obj = parse(your_string)

Behind the scenes, I guess the "1st", and "2nd" parts are extracted somehow (e.g. splitting+regex) and simplified to its day value only.
According to an input like that, the common datetime library can be used with proper date format string:

import datetime
simplified_txt = "Friday 1 March 2019"
datetime_obj = datetime.datetime.strptime(simplified_txt,"%A %d %B %Y")

share|improve this answer

edited Mar 25 at 20:48

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

add a comment | 

Please refer to an already answered question:
How to get the datetime from a string containing '2nd' for the date in Python?

As I can only repeat, solution is to use dateutil parser:

from dateutil.parser import parse

your_string = "Friday 1st March 2019"
date_obj = parse(your_string)

Behind the scenes, I guess the "1st", and "2nd" parts are extracted somehow (e.g. splitting+regex) and simplified to its day value only.
According to an input like that, the common datetime library can be used with proper date format string:

import datetime
simplified_txt = "Friday 1 March 2019"
datetime_obj = datetime.datetime.strptime(simplified_txt,"%A %d %B %Y")

share|improve this answer

edited Mar 25 at 20:48

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

from dateutil.parser import parse

your_string = "Friday 1st March 2019"
date_obj = parse(your_string)

import datetime
simplified_txt = "Friday 1 March 2019"
datetime_obj = datetime.datetime.strptime(simplified_txt,"%A %d %B %Y")

share|improve this answer

edited Mar 25 at 20:48

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

answered Mar 25 at 20:39

Bence KőváriBence Kővári

9166 bronze badges

1

You are going to face issues with 1st, 2nd.

So, try this (without adding any external/third party library):

import re
from datetime import datetime as dt
ds = "Friday 1st March 2019"
parts = ds.split(" ")
ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
)
a = dt.strptime(ds, "%A %d %B %Y")

If you want to make it into a function, do this:

def convdate(s):
 parts = s.split(" ")
 ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
 )
 return dt.strptime(ds, "%A %d %B %Y")

share|improve this answer

edited Mar 25 at 22:26

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

add a comment | 

1

You are going to face issues with 1st, 2nd.

So, try this (without adding any external/third party library):

import re
from datetime import datetime as dt
ds = "Friday 1st March 2019"
parts = ds.split(" ")
ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
)
a = dt.strptime(ds, "%A %d %B %Y")

If you want to make it into a function, do this:

def convdate(s):
 parts = s.split(" ")
 ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
 )
 return dt.strptime(ds, "%A %d %B %Y")

share|improve this answer

edited Mar 25 at 22:26

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

add a comment | 

You are going to face issues with 1st, 2nd.

So, try this (without adding any external/third party library):

import re
from datetime import datetime as dt
ds = "Friday 1st March 2019"
parts = ds.split(" ")
ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
)
a = dt.strptime(ds, "%A %d %B %Y")

If you want to make it into a function, do this:

def convdate(s):
 parts = s.split(" ")
 ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
 )
 return dt.strptime(ds, "%A %d %B %Y")

share|improve this answer

edited Mar 25 at 22:26

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

import re
from datetime import datetime as dt
ds = "Friday 1st March 2019"
parts = ds.split(" ")
ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
)
a = dt.strptime(ds, "%A %d %B %Y")

def convdate(s):
 parts = s.split(" ")
 ds = " ".format(
 parts[0],
 re.sub('[^0-9]','', parts[1]),
 parts[2],
 parts[3]
 )
 return dt.strptime(ds, "%A %d %B %Y")

share|improve this answer

edited Mar 25 at 22:26

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges

answered Mar 25 at 20:09

Pablo Santa CruzPablo Santa Cruz

139k2828 gold badges205205 silver badges256256 bronze badges