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“subscript out of bounds error” when trying to knit to .md file? How to fix?
How to fix “Subscript out of bounds error”Cryptic dplyr error when trying to knit htmlInexplicable “subscript out of bounds” error in dplyr::filter()Subscript out of bounds errorError in R: subscript out of boundsSubscript out of bounds when using [[]]Subscript out of bounds error in rmarkdownOut of bounds subscript errorDplyr - Mutate subscript out of boundsError knitting file in RStudio
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
my rmarkdown file seems to have an issue knitting on this specific chunk of code:
library(tidyverse)
df <- data.frame(female = c("Republican", "Republican", "Democrat", "Democrat"),
male = c("Republican", "Democrat", "Republican", "Democrat"),
n = c(100, 50, 50, 150))
xtabs(n ~ female + male, df)
# male
# female Democrat Republican
# Democrat 150 50
# Republican 50 100
I am trying to calculate the probability of a Rep Female being with a Rep Man, and vice versa. So in this example that would be (100 / 150), but I don't know how to do that in a relation to the variables.
I tried this:
Fem <- colSums(df[ , "Republican", drop = FALSE] ) / sum(colSums(df))
Fem
Men <- rowSums(df["Republican", , drop = FALSE ] ) / sum(rowSums(df))
Men
This works fine in the code and produces probabilities, but refuses to compile when I try to knit it into an md file. It says:
Error in `[.default`(df, , "Republican", drop = FALSE) : subscript out of bounds
Calls: <Anonymous> ... colSums -> -> is.data.frame -> [ -> [.table -> NextMethod
In addition: Warning messages:
1: package 'tidyverse' was built under R version 3.5.2
2: package 'tidyr' was built under R version 3.5.2
3: package 'forcats' was built under R version 3.5.2
Execution Halted
Could someone help me decipher where I messed up? Thank you!
r dplyr r-markdown
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
|
show 2 more comments
my rmarkdown file seems to have an issue knitting on this specific chunk of code:
library(tidyverse)
df <- data.frame(female = c("Republican", "Republican", "Democrat", "Democrat"),
male = c("Republican", "Democrat", "Republican", "Democrat"),
n = c(100, 50, 50, 150))
xtabs(n ~ female + male, df)
# male
# female Democrat Republican
# Democrat 150 50
# Republican 50 100
I am trying to calculate the probability of a Rep Female being with a Rep Man, and vice versa. So in this example that would be (100 / 150), but I don't know how to do that in a relation to the variables.
I tried this:
Fem <- colSums(df[ , "Republican", drop = FALSE] ) / sum(colSums(df))
Fem
Men <- rowSums(df["Republican", , drop = FALSE ] ) / sum(rowSums(df))
Men
This works fine in the code and produces probabilities, but refuses to compile when I try to knit it into an md file. It says:
Error in `[.default`(df, , "Republican", drop = FALSE) : subscript out of bounds
Calls: <Anonymous> ... colSums -> -> is.data.frame -> [ -> [.table -> NextMethod
In addition: Warning messages:
1: package 'tidyverse' was built under R version 3.5.2
2: package 'tidyr' was built under R version 3.5.2
3: package 'forcats' was built under R version 3.5.2
Execution Halted
Could someone help me decipher where I messed up? Thank you!
r dplyr r-markdown
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
df["Republican",]only works if there are row names, your sample data does not. Do you meandf[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)
– r2evans
Mar 25 at 19:38
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
There must be code that you are not sharing, since that error occurs whendfis not a frame. Are you by chance overwriting withdf <- xtabs(...)? That's rather important. More the point,data.framedoes not auto-generate row names like that, and that's the only place you are assigning todf.)
– r2evans
Mar 25 at 19:43
1
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
1
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty withls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you dodf<-data.frame(...)and thendf<-xtabs(...,data=df). Further, if it is the table and not the frame,df["Republican",,drop=F]gets you the republicans, not the males (or females), so your summary statistic is mis-informing.
– r2evans
Mar 25 at 19:53
|
show 2 more comments
my rmarkdown file seems to have an issue knitting on this specific chunk of code:
library(tidyverse)
df <- data.frame(female = c("Republican", "Republican", "Democrat", "Democrat"),
male = c("Republican", "Democrat", "Republican", "Democrat"),
n = c(100, 50, 50, 150))
xtabs(n ~ female + male, df)
# male
# female Democrat Republican
# Democrat 150 50
# Republican 50 100
I am trying to calculate the probability of a Rep Female being with a Rep Man, and vice versa. So in this example that would be (100 / 150), but I don't know how to do that in a relation to the variables.
I tried this:
Fem <- colSums(df[ , "Republican", drop = FALSE] ) / sum(colSums(df))
Fem
Men <- rowSums(df["Republican", , drop = FALSE ] ) / sum(rowSums(df))
Men
This works fine in the code and produces probabilities, but refuses to compile when I try to knit it into an md file. It says:
Error in `[.default`(df, , "Republican", drop = FALSE) : subscript out of bounds
Calls: <Anonymous> ... colSums -> -> is.data.frame -> [ -> [.table -> NextMethod
In addition: Warning messages:
1: package 'tidyverse' was built under R version 3.5.2
2: package 'tidyr' was built under R version 3.5.2
3: package 'forcats' was built under R version 3.5.2
Execution Halted
Could someone help me decipher where I messed up? Thank you!
r dplyr r-markdown
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
my rmarkdown file seems to have an issue knitting on this specific chunk of code:
library(tidyverse)
df <- data.frame(female = c("Republican", "Republican", "Democrat", "Democrat"),
male = c("Republican", "Democrat", "Republican", "Democrat"),
n = c(100, 50, 50, 150))
xtabs(n ~ female + male, df)
# male
# female Democrat Republican
# Democrat 150 50
# Republican 50 100
I am trying to calculate the probability of a Rep Female being with a Rep Man, and vice versa. So in this example that would be (100 / 150), but I don't know how to do that in a relation to the variables.
I tried this:
Fem <- colSums(df[ , "Republican", drop = FALSE] ) / sum(colSums(df))
Fem
Men <- rowSums(df["Republican", , drop = FALSE ] ) / sum(rowSums(df))
Men
This works fine in the code and produces probabilities, but refuses to compile when I try to knit it into an md file. It says:
Error in `[.default`(df, , "Republican", drop = FALSE) : subscript out of bounds
Calls: <Anonymous> ... colSums -> -> is.data.frame -> [ -> [.table -> NextMethod
In addition: Warning messages:
1: package 'tidyverse' was built under R version 3.5.2
2: package 'tidyr' was built under R version 3.5.2
3: package 'forcats' was built under R version 3.5.2
Execution Halted
Could someone help me decipher where I messed up? Thank you!
r dplyr r-markdown
r dplyr r-markdown
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
edited Mar 25 at 19:44
r2evans
30.5k3 gold badges32 silver badges59 bronze badges
30.5k3 gold badges32 silver badges59 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
asked Mar 25 at 19:31
skipndippskipndipp
85 bronze badges
85 bronze badges
df["Republican",]only works if there are row names, your sample data does not. Do you meandf[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)
– r2evans
Mar 25 at 19:38
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
There must be code that you are not sharing, since that error occurs whendfis not a frame. Are you by chance overwriting withdf <- xtabs(...)? That's rather important. More the point,data.framedoes not auto-generate row names like that, and that's the only place you are assigning todf.)
– r2evans
Mar 25 at 19:43
1
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
1
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty withls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you dodf<-data.frame(...)and thendf<-xtabs(...,data=df). Further, if it is the table and not the frame,df["Republican",,drop=F]gets you the republicans, not the males (or females), so your summary statistic is mis-informing.
– r2evans
Mar 25 at 19:53
|
show 2 more comments
df["Republican",]only works if there are row names, your sample data does not. Do you meandf[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)
– r2evans
Mar 25 at 19:38
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
There must be code that you are not sharing, since that error occurs whendfis not a frame. Are you by chance overwriting withdf <- xtabs(...)? That's rather important. More the point,data.framedoes not auto-generate row names like that, and that's the only place you are assigning todf.)
– r2evans
Mar 25 at 19:43
1
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
1
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty withls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you dodf<-data.frame(...)and thendf<-xtabs(...,data=df). Further, if it is the table and not the frame,df["Republican",,drop=F]gets you the republicans, not the males (or females), so your summary statistic is mis-informing.
– r2evans
Mar 25 at 19:53
df["Republican",] only works if there are row names, your sample data does not. Do you mean df[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)– r2evans
Mar 25 at 19:38
df["Republican",] only works if there are row names, your sample data does not. Do you mean df[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)– r2evans
Mar 25 at 19:38
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
There must be code that you are not sharing, since that error occurs when
df is not a frame. Are you by chance overwriting with df <- xtabs(...)? That's rather important. More the point, data.frame does not auto-generate row names like that, and that's the only place you are assigning to df.)– r2evans
Mar 25 at 19:43
There must be code that you are not sharing, since that error occurs when
df is not a frame. Are you by chance overwriting with df <- xtabs(...)? That's rather important. More the point, data.frame does not auto-generate row names like that, and that's the only place you are assigning to df.)– r2evans
Mar 25 at 19:43
1
1
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
1
1
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty with
ls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you do df<-data.frame(...) and then df<-xtabs(...,data=df). Further, if it is the table and not the frame, df["Republican",,drop=F] gets you the republicans, not the males (or females), so your summary statistic is mis-informing.– r2evans
Mar 25 at 19:53
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty with
ls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you do df<-data.frame(...) and then df<-xtabs(...,data=df). Further, if it is the table and not the frame, df["Republican",,drop=F] gets you the republicans, not the males (or females), so your summary statistic is mis-informing.– r2evans
Mar 25 at 19:53
|
show 2 more comments
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df["Republican",]only works if there are row names, your sample data does not. Do you meandf[ df$female == "Republican",,drop=FALSE]? (Does that code work on the console, regardless of rmarkdown? I suggest when making your rmarkdown documents, you try things on the console before trying to automate and render your report.)– r2evans
Mar 25 at 19:38
The code I provided works well for me on the console :/ It automatically generated row names for me. Your solution gives me this error: "Error in df$female : $ operator is invalid for atomic vectors"
– skipndipp
Mar 25 at 19:41
There must be code that you are not sharing, since that error occurs when
dfis not a frame. Are you by chance overwriting withdf <- xtabs(...)? That's rather important. More the point,data.framedoes not auto-generate row names like that, and that's the only place you are assigning todf.)– r2evans
Mar 25 at 19:43
1
I promise that that's all the code I've used. And sorry about tidyverse, I only put it there since I know it's loaded and didn't know if it would affect the issue.
– skipndipp
Mar 25 at 19:48
1
Something is missing, of that I am confident. If you start a new R session (don't reload a cache! make sure the environment is empty with
ls()), then type in your code as you present it here, you will get errors or warnings different from your question. Your assertion only makes sense (so far) if you dodf<-data.frame(...)and thendf<-xtabs(...,data=df). Further, if it is the table and not the frame,df["Republican",,drop=F]gets you the republicans, not the males (or females), so your summary statistic is mis-informing.– r2evans
Mar 25 at 19:53