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Aggregating existing query to work for multiple rows
Can I concatenate multiple MySQL rows into one field?Mysql performance with nested indicesspeed up this query ( join + mediumtext field)MySQL query optimization - increase speed and efficiencyMySQL Limit LEFT JOIN Subquery after joiningHow to select rows from one table and order it by the sum of a column from another table?Need help in SQL query performanceWhat is better in performance for 1-to-1 relationship: a new table or a VARCHAR column with a lot of empty entriesvoyager databases and MariaDB serverHow to optimize a select query with multiple left joins in a large database
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have a ledger table, and right now I have the ability to find the date or NULL if someone is delinquent based on their payment history. I need a query that allows me to find all delinquent members instead of just a specific one.
I need the ability to run a query that gets any member that is delinquent and return to me the member_id and the date of delinquency.
Basically what the original query to find delinquency for a specific member does, just doing every member instead of a specific one.
I have tried:
SELECT DISTINCT member_id, created_at FROM member_ledger_items WHERE
balance > 0 and id > (
IFNULL(
(SELECT id from member_ledger_items WHERE balance <= 0 and member_ledger_items.deleted_at is NULL GROUP BY member_id ORDER BY created_at, id desc LIMIT 1),
0
)
) and `member_ledger_items`.`deleted_at` is null GROUP BY member_id order by created_at asc, id asc;
This is the query to find if a specific member is delinquent:
select `created_at` from `member_ledger_items` where `member_id` = ? and `balance` > 0 and `id` >
(
IFNULL(
(select `id` from `member_ledger_items` where `member_id` = ? and `balance` <= 0 and `member_ledger_items`.`deleted_at` is null order by `created_at` desc, `id` desc limit 1)
, 0)
)
and `member_ledger_items`.`deleted_at` is null order by `created_at` asc, `id` asc limit 1;
Here is the create syntax of the member_ledger_items table:
CREATE TABLE `member_ledger_items` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`member_id` int(10) unsigned NOT NULL,
`status` varchar(20) COLLATE utf8_unicode_ci NOT NULL,
`type` enum('credit','debit') COLLATE utf8_unicode_ci NOT NULL,
`category` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`memo` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
`amount` decimal(13,3) DEFAULT NULL,
`autopay` tinyint(1) DEFAULT NULL,
`late` tinyint(1) DEFAULT NULL,
`date` date NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
`deleted_at` timestamp NULL DEFAULT NULL,
`balance` decimal(13,3) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=53596 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
I need rows with member_id and date of starting delinquency.
Is this possible?
Any help would be appreciated!
mysql
add a comment |
I have a ledger table, and right now I have the ability to find the date or NULL if someone is delinquent based on their payment history. I need a query that allows me to find all delinquent members instead of just a specific one.
I need the ability to run a query that gets any member that is delinquent and return to me the member_id and the date of delinquency.
Basically what the original query to find delinquency for a specific member does, just doing every member instead of a specific one.
I have tried:
SELECT DISTINCT member_id, created_at FROM member_ledger_items WHERE
balance > 0 and id > (
IFNULL(
(SELECT id from member_ledger_items WHERE balance <= 0 and member_ledger_items.deleted_at is NULL GROUP BY member_id ORDER BY created_at, id desc LIMIT 1),
0
)
) and `member_ledger_items`.`deleted_at` is null GROUP BY member_id order by created_at asc, id asc;
This is the query to find if a specific member is delinquent:
select `created_at` from `member_ledger_items` where `member_id` = ? and `balance` > 0 and `id` >
(
IFNULL(
(select `id` from `member_ledger_items` where `member_id` = ? and `balance` <= 0 and `member_ledger_items`.`deleted_at` is null order by `created_at` desc, `id` desc limit 1)
, 0)
)
and `member_ledger_items`.`deleted_at` is null order by `created_at` asc, `id` asc limit 1;
Here is the create syntax of the member_ledger_items table:
CREATE TABLE `member_ledger_items` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`member_id` int(10) unsigned NOT NULL,
`status` varchar(20) COLLATE utf8_unicode_ci NOT NULL,
`type` enum('credit','debit') COLLATE utf8_unicode_ci NOT NULL,
`category` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`memo` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
`amount` decimal(13,3) DEFAULT NULL,
`autopay` tinyint(1) DEFAULT NULL,
`late` tinyint(1) DEFAULT NULL,
`date` date NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
`deleted_at` timestamp NULL DEFAULT NULL,
`balance` decimal(13,3) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=53596 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
I need rows with member_id and date of starting delinquency.
Is this possible?
Any help would be appreciated!
mysql
add a comment |
I have a ledger table, and right now I have the ability to find the date or NULL if someone is delinquent based on their payment history. I need a query that allows me to find all delinquent members instead of just a specific one.
I need the ability to run a query that gets any member that is delinquent and return to me the member_id and the date of delinquency.
Basically what the original query to find delinquency for a specific member does, just doing every member instead of a specific one.
I have tried:
SELECT DISTINCT member_id, created_at FROM member_ledger_items WHERE
balance > 0 and id > (
IFNULL(
(SELECT id from member_ledger_items WHERE balance <= 0 and member_ledger_items.deleted_at is NULL GROUP BY member_id ORDER BY created_at, id desc LIMIT 1),
0
)
) and `member_ledger_items`.`deleted_at` is null GROUP BY member_id order by created_at asc, id asc;
This is the query to find if a specific member is delinquent:
select `created_at` from `member_ledger_items` where `member_id` = ? and `balance` > 0 and `id` >
(
IFNULL(
(select `id` from `member_ledger_items` where `member_id` = ? and `balance` <= 0 and `member_ledger_items`.`deleted_at` is null order by `created_at` desc, `id` desc limit 1)
, 0)
)
and `member_ledger_items`.`deleted_at` is null order by `created_at` asc, `id` asc limit 1;
Here is the create syntax of the member_ledger_items table:
CREATE TABLE `member_ledger_items` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`member_id` int(10) unsigned NOT NULL,
`status` varchar(20) COLLATE utf8_unicode_ci NOT NULL,
`type` enum('credit','debit') COLLATE utf8_unicode_ci NOT NULL,
`category` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`memo` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
`amount` decimal(13,3) DEFAULT NULL,
`autopay` tinyint(1) DEFAULT NULL,
`late` tinyint(1) DEFAULT NULL,
`date` date NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
`deleted_at` timestamp NULL DEFAULT NULL,
`balance` decimal(13,3) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=53596 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
I need rows with member_id and date of starting delinquency.
Is this possible?
Any help would be appreciated!
mysql
I have a ledger table, and right now I have the ability to find the date or NULL if someone is delinquent based on their payment history. I need a query that allows me to find all delinquent members instead of just a specific one.
I need the ability to run a query that gets any member that is delinquent and return to me the member_id and the date of delinquency.
Basically what the original query to find delinquency for a specific member does, just doing every member instead of a specific one.
I have tried:
SELECT DISTINCT member_id, created_at FROM member_ledger_items WHERE
balance > 0 and id > (
IFNULL(
(SELECT id from member_ledger_items WHERE balance <= 0 and member_ledger_items.deleted_at is NULL GROUP BY member_id ORDER BY created_at, id desc LIMIT 1),
0
)
) and `member_ledger_items`.`deleted_at` is null GROUP BY member_id order by created_at asc, id asc;
This is the query to find if a specific member is delinquent:
select `created_at` from `member_ledger_items` where `member_id` = ? and `balance` > 0 and `id` >
(
IFNULL(
(select `id` from `member_ledger_items` where `member_id` = ? and `balance` <= 0 and `member_ledger_items`.`deleted_at` is null order by `created_at` desc, `id` desc limit 1)
, 0)
)
and `member_ledger_items`.`deleted_at` is null order by `created_at` asc, `id` asc limit 1;
Here is the create syntax of the member_ledger_items table:
CREATE TABLE `member_ledger_items` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`member_id` int(10) unsigned NOT NULL,
`status` varchar(20) COLLATE utf8_unicode_ci NOT NULL,
`type` enum('credit','debit') COLLATE utf8_unicode_ci NOT NULL,
`category` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`memo` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
`amount` decimal(13,3) DEFAULT NULL,
`autopay` tinyint(1) DEFAULT NULL,
`late` tinyint(1) DEFAULT NULL,
`date` date NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
`deleted_at` timestamp NULL DEFAULT NULL,
`balance` decimal(13,3) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=53596 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
I need rows with member_id and date of starting delinquency.
Is this possible?
Any help would be appreciated!
mysql
mysql
edited Mar 27 at 20:29
Jacob Hyde
asked Mar 27 at 17:51
Jacob HydeJacob Hyde
481 silver badge6 bronze badges
481 silver badge6 bronze badges
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
SELECT `member_id`,
(SELECT `created_at`
FROM `member_ledger_items` AS MLI2
WHERE `balance` > 0
AND MLI2.`member_id` = MLI.`member_id`
AND `id` > ( Ifnull((SELECT `id`
FROM `member_ledger_items` AS MLI3
WHERE `balance` <= 0
AND MLI3.`member_id` =
MLI2.`member_id`
AND MLI3.`deleted_at` IS NULL
ORDER BY `created_at` DESC,
`id` DESC
LIMIT 1), 0) )
AND MLI2.`deleted_at` IS NULL
ORDER BY `created_at` ASC,
`id` ASC
LIMIT 1) AS created_date
FROM `member_ledger_items` AS MLI
GROUP BY `member_id`;
Ended up being the solution
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
SELECT `member_id`,
(SELECT `created_at`
FROM `member_ledger_items` AS MLI2
WHERE `balance` > 0
AND MLI2.`member_id` = MLI.`member_id`
AND `id` > ( Ifnull((SELECT `id`
FROM `member_ledger_items` AS MLI3
WHERE `balance` <= 0
AND MLI3.`member_id` =
MLI2.`member_id`
AND MLI3.`deleted_at` IS NULL
ORDER BY `created_at` DESC,
`id` DESC
LIMIT 1), 0) )
AND MLI2.`deleted_at` IS NULL
ORDER BY `created_at` ASC,
`id` ASC
LIMIT 1) AS created_date
FROM `member_ledger_items` AS MLI
GROUP BY `member_id`;
Ended up being the solution
add a comment |
SELECT `member_id`,
(SELECT `created_at`
FROM `member_ledger_items` AS MLI2
WHERE `balance` > 0
AND MLI2.`member_id` = MLI.`member_id`
AND `id` > ( Ifnull((SELECT `id`
FROM `member_ledger_items` AS MLI3
WHERE `balance` <= 0
AND MLI3.`member_id` =
MLI2.`member_id`
AND MLI3.`deleted_at` IS NULL
ORDER BY `created_at` DESC,
`id` DESC
LIMIT 1), 0) )
AND MLI2.`deleted_at` IS NULL
ORDER BY `created_at` ASC,
`id` ASC
LIMIT 1) AS created_date
FROM `member_ledger_items` AS MLI
GROUP BY `member_id`;
Ended up being the solution
add a comment |
SELECT `member_id`,
(SELECT `created_at`
FROM `member_ledger_items` AS MLI2
WHERE `balance` > 0
AND MLI2.`member_id` = MLI.`member_id`
AND `id` > ( Ifnull((SELECT `id`
FROM `member_ledger_items` AS MLI3
WHERE `balance` <= 0
AND MLI3.`member_id` =
MLI2.`member_id`
AND MLI3.`deleted_at` IS NULL
ORDER BY `created_at` DESC,
`id` DESC
LIMIT 1), 0) )
AND MLI2.`deleted_at` IS NULL
ORDER BY `created_at` ASC,
`id` ASC
LIMIT 1) AS created_date
FROM `member_ledger_items` AS MLI
GROUP BY `member_id`;
Ended up being the solution
SELECT `member_id`,
(SELECT `created_at`
FROM `member_ledger_items` AS MLI2
WHERE `balance` > 0
AND MLI2.`member_id` = MLI.`member_id`
AND `id` > ( Ifnull((SELECT `id`
FROM `member_ledger_items` AS MLI3
WHERE `balance` <= 0
AND MLI3.`member_id` =
MLI2.`member_id`
AND MLI3.`deleted_at` IS NULL
ORDER BY `created_at` DESC,
`id` DESC
LIMIT 1), 0) )
AND MLI2.`deleted_at` IS NULL
ORDER BY `created_at` ASC,
`id` ASC
LIMIT 1) AS created_date
FROM `member_ledger_items` AS MLI
GROUP BY `member_id`;
Ended up being the solution
answered Mar 27 at 22:30
Jacob HydeJacob Hyde
481 silver badge6 bronze badges
481 silver badge6 bronze badges
add a comment |
add a comment |
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