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Batch processing multiple .csv files using R selecting only one column
Dealing with commas in a CSV fileHow to sort a dataframe by multiple column(s)Save PL/pgSQL output from PostgreSQL to a CSV fileHow to import CSV file to MySQL tableHow to import multiple .csv files at once?Read specific columns from a csv file with csv module?Combining csv files in R to different columnsLooping and extracting file numbers from .csv file names and inserting into a columnImport multiple CSV files, select 1 Column from each file & rename the column with the file name in Jupyter NoteboosBatch file for replace characters in all CSV of a folder
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am working on a project that involves 470 stats kept over a period of 40 years. My data is structured so that each year is a folder and its 470 corresponding stats (as .csv files) are kept inside that folder. Each of these files contains an ascending or descending column of numbers (inside the same .csv file) of which I care about. I need to know what column number this is for every .csv file.
Here is my problem. The information file of which I have been given that explains to me each of these stats is mislabeled. It tells me that the meaningful data is in column 4 for every .csv file (data_col = 4 for all attributes); however, this is only correct for 80-90% of the files from my observations.
I want to batch import column 4 from each file into one large data set (470 columns; each representing a stat) so I can see if the data in that column is ascending or descending. If it is not, I can manually open that file and find it myself. I can then modify my information file so I know which columns to run my analysis on later.
The alternative to this is opening and closing 470 files for each year (or 40 times) and looking to see if the data is in column 4 as stated.
How do I batch import a single column from multiple .csv files into one dataset in R?
r csv batch-processing dynamic-columns
add a comment |
I am working on a project that involves 470 stats kept over a period of 40 years. My data is structured so that each year is a folder and its 470 corresponding stats (as .csv files) are kept inside that folder. Each of these files contains an ascending or descending column of numbers (inside the same .csv file) of which I care about. I need to know what column number this is for every .csv file.
Here is my problem. The information file of which I have been given that explains to me each of these stats is mislabeled. It tells me that the meaningful data is in column 4 for every .csv file (data_col = 4 for all attributes); however, this is only correct for 80-90% of the files from my observations.
I want to batch import column 4 from each file into one large data set (470 columns; each representing a stat) so I can see if the data in that column is ascending or descending. If it is not, I can manually open that file and find it myself. I can then modify my information file so I know which columns to run my analysis on later.
The alternative to this is opening and closing 470 files for each year (or 40 times) and looking to see if the data is in column 4 as stated.
How do I batch import a single column from multiple .csv files into one dataset in R?
r csv batch-processing dynamic-columns
Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47
add a comment |
I am working on a project that involves 470 stats kept over a period of 40 years. My data is structured so that each year is a folder and its 470 corresponding stats (as .csv files) are kept inside that folder. Each of these files contains an ascending or descending column of numbers (inside the same .csv file) of which I care about. I need to know what column number this is for every .csv file.
Here is my problem. The information file of which I have been given that explains to me each of these stats is mislabeled. It tells me that the meaningful data is in column 4 for every .csv file (data_col = 4 for all attributes); however, this is only correct for 80-90% of the files from my observations.
I want to batch import column 4 from each file into one large data set (470 columns; each representing a stat) so I can see if the data in that column is ascending or descending. If it is not, I can manually open that file and find it myself. I can then modify my information file so I know which columns to run my analysis on later.
The alternative to this is opening and closing 470 files for each year (or 40 times) and looking to see if the data is in column 4 as stated.
How do I batch import a single column from multiple .csv files into one dataset in R?
r csv batch-processing dynamic-columns
I am working on a project that involves 470 stats kept over a period of 40 years. My data is structured so that each year is a folder and its 470 corresponding stats (as .csv files) are kept inside that folder. Each of these files contains an ascending or descending column of numbers (inside the same .csv file) of which I care about. I need to know what column number this is for every .csv file.
Here is my problem. The information file of which I have been given that explains to me each of these stats is mislabeled. It tells me that the meaningful data is in column 4 for every .csv file (data_col = 4 for all attributes); however, this is only correct for 80-90% of the files from my observations.
I want to batch import column 4 from each file into one large data set (470 columns; each representing a stat) so I can see if the data in that column is ascending or descending. If it is not, I can manually open that file and find it myself. I can then modify my information file so I know which columns to run my analysis on later.
The alternative to this is opening and closing 470 files for each year (or 40 times) and looking to see if the data is in column 4 as stated.
How do I batch import a single column from multiple .csv files into one dataset in R?
r csv batch-processing dynamic-columns
r csv batch-processing dynamic-columns
asked Mar 23 at 23:53
sharkguy95sharkguy95
12
12
Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47
add a comment |
Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47
Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47
Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47
add a comment |
1 Answer
1
active
oldest
votes
This will get all the CSV files in a directory and then read them into a single data.frame only keeping column 4 (or whatever columns you want to keep), and also put the file name in each row if you want to find errors in the input
library(tidyverse) # get useful functions
files <- list.files(path = '/d$/temp/csv',
pattern = ".*csv",
full.names = TRUE
)
all_data <- map_dfr(files, ~
read_csv(.x)[, 4] %>% # keep column 4
mutate(file = .x) # add file name
)
print(all_data[1:10,])
col4 file
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
The CSV files looked like this:
col1,col2,col3,col4,col5,col6
1,2,3,4,5,6
1,2,3,4,5,6
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
This will get all the CSV files in a directory and then read them into a single data.frame only keeping column 4 (or whatever columns you want to keep), and also put the file name in each row if you want to find errors in the input
library(tidyverse) # get useful functions
files <- list.files(path = '/d$/temp/csv',
pattern = ".*csv",
full.names = TRUE
)
all_data <- map_dfr(files, ~
read_csv(.x)[, 4] %>% # keep column 4
mutate(file = .x) # add file name
)
print(all_data[1:10,])
col4 file
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
The CSV files looked like this:
col1,col2,col3,col4,col5,col6
1,2,3,4,5,6
1,2,3,4,5,6
add a comment |
This will get all the CSV files in a directory and then read them into a single data.frame only keeping column 4 (or whatever columns you want to keep), and also put the file name in each row if you want to find errors in the input
library(tidyverse) # get useful functions
files <- list.files(path = '/d$/temp/csv',
pattern = ".*csv",
full.names = TRUE
)
all_data <- map_dfr(files, ~
read_csv(.x)[, 4] %>% # keep column 4
mutate(file = .x) # add file name
)
print(all_data[1:10,])
col4 file
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
The CSV files looked like this:
col1,col2,col3,col4,col5,col6
1,2,3,4,5,6
1,2,3,4,5,6
add a comment |
This will get all the CSV files in a directory and then read them into a single data.frame only keeping column 4 (or whatever columns you want to keep), and also put the file name in each row if you want to find errors in the input
library(tidyverse) # get useful functions
files <- list.files(path = '/d$/temp/csv',
pattern = ".*csv",
full.names = TRUE
)
all_data <- map_dfr(files, ~
read_csv(.x)[, 4] %>% # keep column 4
mutate(file = .x) # add file name
)
print(all_data[1:10,])
col4 file
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
The CSV files looked like this:
col1,col2,col3,col4,col5,col6
1,2,3,4,5,6
1,2,3,4,5,6
This will get all the CSV files in a directory and then read them into a single data.frame only keeping column 4 (or whatever columns you want to keep), and also put the file name in each row if you want to find errors in the input
library(tidyverse) # get useful functions
files <- list.files(path = '/d$/temp/csv',
pattern = ".*csv",
full.names = TRUE
)
all_data <- map_dfr(files, ~
read_csv(.x)[, 4] %>% # keep column 4
mutate(file = .x) # add file name
)
print(all_data[1:10,])
col4 file
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
4 /d$/temp/csv/Document1 - Copy (2).csv
The CSV files looked like this:
col1,col2,col3,col4,col5,col6
1,2,3,4,5,6
1,2,3,4,5,6
answered Mar 24 at 2:03
Data MungerData Munger
96566
96566
add a comment |
add a comment |
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Please have a look at the help center and try to put some code together, test it yourself and then ask here only what you cannot figure out on your own (with your coding attempt) otherwise it's impossible to help you and it looks like you're just asking us to do your work for you.
– Fons MA
Mar 24 at 1:47