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Creating scanner with multiple words
Create ArrayList from arrayHow do I create a Java string from the contents of a file?How can I create an executable JAR with dependencies using Maven?How do I create a file and write to it in Java?Create the perfect JPA entityCreating a memory leak with JavaJava - Scanner(System.in) and “Blocking a thread”Scanner is skipping nextLine() after using next() or nextFoo()?Keep getting this error message for my RockPaperScissor Program. How do I fix this error?
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I need to include 10 variables but when I type in anything it comes up with only 1 of the variables I need to know how to make it so for example when "Gaming" is typed, the program comes back with "Do you like gaming?" right now it is at the point where anything I type it comes up with "Do you like uni?"
I have tried searching google for 3 hours and have done everything they have said and I can't find it. using .contains doesn't work for some reason.
Scanner chatterbot = new Scanner(System.in);
String uni = ("University");
String gaming = ("Gaming");
uni = chatterbot.nextLine();
if (uni.contains("University"))
System.out.println("Do you like uni?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("Do you study one of SE CS or IT?");
else if (uni.contains("No"))
System.out.println("Do you study one of SE CS or IT?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("That is really great!");
else if (uni.contains("No"))
System.out.println("That is not good!");
System.exit(0);
gaming = chatterbot.nextLine();
if (gaming.contains("Gaming"))
System.out.println("Do you like gaming?");
gaming = chatterbot.nextLine();
if (gaming.contains("Yes"))
System.out.println("What kind of games do you like to play?");
I expect the output to be if the user types Uni then it says "Do you like uni?" and when you type gaming it says "Do you like gaming?" The uni part works but when I type Gaming nothing appears.
java
asked Mar 23 at 23:35
FidelityFidelity
62
add a comment |
I need to include 10 variables but when I type in anything it comes up with only 1 of the variables I need to know how to make it so for example when "Gaming" is typed, the program comes back with "Do you like gaming?" right now it is at the point where anything I type it comes up with "Do you like uni?"
I have tried searching google for 3 hours and have done everything they have said and I can't find it. using .contains doesn't work for some reason.
Scanner chatterbot = new Scanner(System.in);
String uni = ("University");
String gaming = ("Gaming");
uni = chatterbot.nextLine();
if (uni.contains("University"))
System.out.println("Do you like uni?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("Do you study one of SE CS or IT?");
else if (uni.contains("No"))
System.out.println("Do you study one of SE CS or IT?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("That is really great!");
else if (uni.contains("No"))
System.out.println("That is not good!");
System.exit(0);
gaming = chatterbot.nextLine();
if (gaming.contains("Gaming"))
System.out.println("Do you like gaming?");
gaming = chatterbot.nextLine();
if (gaming.contains("Yes"))
System.out.println("What kind of games do you like to play?");
I expect the output to be if the user types Uni then it says "Do you like uni?" and when you type gaming it says "Do you like gaming?" The uni part works but when I type Gaming nothing appears.
java
asked Mar 23 at 23:35
FidelityFidelity
62
Don't usenew String("University"), just doString uni = "University";
– GBlodgett
Mar 23 at 23:53
1
Also remove the semicolon after the lastif
– GBlodgett
Mar 24 at 0:00
No reason to use 2 different String fields for this. Just useString input = chatterbot.nextLine();first time and useinput = chatterbot.nextLine();second time. No need to instantiate strings with University and Gaming values either.
– oxyt
Mar 24 at 0:03
add a comment |
I need to include 10 variables but when I type in anything it comes up with only 1 of the variables I need to know how to make it so for example when "Gaming" is typed, the program comes back with "Do you like gaming?" right now it is at the point where anything I type it comes up with "Do you like uni?"
I have tried searching google for 3 hours and have done everything they have said and I can't find it. using .contains doesn't work for some reason.
Scanner chatterbot = new Scanner(System.in);
String uni = ("University");
String gaming = ("Gaming");
uni = chatterbot.nextLine();
if (uni.contains("University"))
System.out.println("Do you like uni?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("Do you study one of SE CS or IT?");
else if (uni.contains("No"))
System.out.println("Do you study one of SE CS or IT?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("That is really great!");
else if (uni.contains("No"))
System.out.println("That is not good!");
System.exit(0);
gaming = chatterbot.nextLine();
if (gaming.contains("Gaming"))
System.out.println("Do you like gaming?");
gaming = chatterbot.nextLine();
if (gaming.contains("Yes"))
System.out.println("What kind of games do you like to play?");
I expect the output to be if the user types Uni then it says "Do you like uni?" and when you type gaming it says "Do you like gaming?" The uni part works but when I type Gaming nothing appears.
java
asked Mar 23 at 23:35
FidelityFidelity
62
I need to include 10 variables but when I type in anything it comes up with only 1 of the variables I need to know how to make it so for example when "Gaming" is typed, the program comes back with "Do you like gaming?" right now it is at the point where anything I type it comes up with "Do you like uni?"
I have tried searching google for 3 hours and have done everything they have said and I can't find it. using .contains doesn't work for some reason.
Scanner chatterbot = new Scanner(System.in);
String uni = ("University");
String gaming = ("Gaming");
uni = chatterbot.nextLine();
if (uni.contains("University"))
System.out.println("Do you like uni?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("Do you study one of SE CS or IT?");
else if (uni.contains("No"))
System.out.println("Do you study one of SE CS or IT?");
uni = chatterbot.nextLine();
if (uni.contains("Yes"))
System.out.println("That is really great!");
else if (uni.contains("No"))
System.out.println("That is not good!");
System.exit(0);
gaming = chatterbot.nextLine();
if (gaming.contains("Gaming"))
System.out.println("Do you like gaming?");
gaming = chatterbot.nextLine();
if (gaming.contains("Yes"))
System.out.println("What kind of games do you like to play?");
I expect the output to be if the user types Uni then it says "Do you like uni?" and when you type gaming it says "Do you like gaming?" The uni part works but when I type Gaming nothing appears.
java
java
asked Mar 23 at 23:35
FidelityFidelity
62
asked Mar 23 at 23:35
FidelityFidelity
62
edited Mar 24 at 10:07
Fidelity
asked Mar 23 at 23:35
FidelityFidelity
62
asked Mar 23 at 23:35
FidelityFidelity
62
asked Mar 23 at 23:35
FidelityFidelity
62
62
Don't usenew String("University"), just doString uni = "University";
– GBlodgett
Mar 23 at 23:53
1
Also remove the semicolon after the lastif
– GBlodgett
Mar 24 at 0:00
No reason to use 2 different String fields for this. Just useString input = chatterbot.nextLine();first time and useinput = chatterbot.nextLine();second time. No need to instantiate strings with University and Gaming values either.
– oxyt
Mar 24 at 0:03
add a comment |
Don't usenew String("University"), just doString uni = "University";
– GBlodgett
Mar 23 at 23:53
1
Also remove the semicolon after the lastif
– GBlodgett
Mar 24 at 0:00
No reason to use 2 different String fields for this. Just useString input = chatterbot.nextLine();first time and useinput = chatterbot.nextLine();second time. No need to instantiate strings with University and Gaming values either.
– oxyt
Mar 24 at 0:03
Don't use
new String("University"), just do String uni = "University";– GBlodgett
Mar 23 at 23:53
Don't use
new String("University"), just do String uni = "University";– GBlodgett
Mar 23 at 23:53
1
1
Also remove the semicolon after the last
if– GBlodgett
Mar 24 at 0:00
Also remove the semicolon after the last
if– GBlodgett
Mar 24 at 0:00
No reason to use 2 different String fields for this. Just use
String input = chatterbot.nextLine(); first time and use input = chatterbot.nextLine(); second time. No need to instantiate strings with University and Gaming values either.– oxyt
Mar 24 at 0:03
No reason to use 2 different String fields for this. Just use
String input = chatterbot.nextLine(); first time and use input = chatterbot.nextLine(); second time. No need to instantiate strings with University and Gaming values either.– oxyt
Mar 24 at 0:03
add a comment |
1 Answer
1
active
oldest
votes
When you call chatterbot.nextLine() your input is consumed so if you call nextLine() again it waits for the next input.
But by saving the input in a variable you can compare it to more than one value.
This should work:
Scanner chatterbot = new Scanner(System.in);
String input = chatterbot.nextLine();
if (input.contains("University"))
System.out.println("Do you like uni?");
else if (input.contains("Gaming"))
System.out.println("Do you like gaming?");
answered Mar 24 at 0:12
BahmutBahmut
111
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
When you call chatterbot.nextLine() your input is consumed so if you call nextLine() again it waits for the next input.
But by saving the input in a variable you can compare it to more than one value.
This should work:
Scanner chatterbot = new Scanner(System.in);
String input = chatterbot.nextLine();
if (input.contains("University"))
System.out.println("Do you like uni?");
else if (input.contains("Gaming"))
System.out.println("Do you like gaming?");
answered Mar 24 at 0:12
BahmutBahmut
111
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
add a comment |
When you call chatterbot.nextLine() your input is consumed so if you call nextLine() again it waits for the next input.
But by saving the input in a variable you can compare it to more than one value.
This should work:
Scanner chatterbot = new Scanner(System.in);
String input = chatterbot.nextLine();
if (input.contains("University"))
System.out.println("Do you like uni?");
else if (input.contains("Gaming"))
System.out.println("Do you like gaming?");
answered Mar 24 at 0:12
BahmutBahmut
111
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
add a comment |
When you call chatterbot.nextLine() your input is consumed so if you call nextLine() again it waits for the next input.
But by saving the input in a variable you can compare it to more than one value.
This should work:
Scanner chatterbot = new Scanner(System.in);
String input = chatterbot.nextLine();
if (input.contains("University"))
System.out.println("Do you like uni?");
else if (input.contains("Gaming"))
System.out.println("Do you like gaming?");
answered Mar 24 at 0:12
BahmutBahmut
111
When you call chatterbot.nextLine() your input is consumed so if you call nextLine() again it waits for the next input.
But by saving the input in a variable you can compare it to more than one value.
This should work:
Scanner chatterbot = new Scanner(System.in);
String input = chatterbot.nextLine();
if (input.contains("University"))
System.out.println("Do you like uni?");
else if (input.contains("Gaming"))
System.out.println("Do you like gaming?");
answered Mar 24 at 0:12
BahmutBahmut
111
answered Mar 24 at 0:12
BahmutBahmut
111
answered Mar 24 at 0:12
BahmutBahmut
111
answered Mar 24 at 0:12
BahmutBahmut
111
111
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
add a comment |
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
I need to be able to add multiple answers for questions.
– Fidelity
Mar 24 at 1:10
add a comment |
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Don't use
new String("University"), just doString uni = "University";– GBlodgett
Mar 23 at 23:53
1
Also remove the semicolon after the last
if– GBlodgett
Mar 24 at 0:00
No reason to use 2 different String fields for this. Just use
String input = chatterbot.nextLine();first time and useinput = chatterbot.nextLine();second time. No need to instantiate strings with University and Gaming values either.– oxyt
Mar 24 at 0:03