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Convert a list to dictionary without extra curly brackets being added

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0

Say I have a list like this:

alist = ['key': 'value']

And then I convert it to a dictionary like this

adict = dict(alist)

The formatting becomes

'''key: 'value'

This makes it so I can't access the data from the dictionary. Is there a way to convert the list to a dictionary without there being extra ' ' -- brackets and single quotes

python dictionary

share|improve this question

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The code you posted does not run without exceptions. It does not produce the output you posted. Please check again.
  
  – Markus Unterwaditzer
  Mar 23 at 23:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of How do I merge a list of dicts into a single dict?
  
  – Michael Doubez
  Mar 23 at 23:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  adict = alist[0] should do it.
  
  – martineau
  Mar 24 at 2:18
  

  
  
  
  

add a comment | 

0

Say I have a list like this:

alist = ['key': 'value']

And then I convert it to a dictionary like this

adict = dict(alist)

The formatting becomes

'''key: 'value'

This makes it so I can't access the data from the dictionary. Is there a way to convert the list to a dictionary without there being extra ' ' -- brackets and single quotes

python dictionary

share|improve this question

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The code you posted does not run without exceptions. It does not produce the output you posted. Please check again.
  
  – Markus Unterwaditzer
  Mar 23 at 23:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of How do I merge a list of dicts into a single dict?
  
  – Michael Doubez
  Mar 23 at 23:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  adict = alist[0] should do it.
  
  – martineau
  Mar 24 at 2:18
  

  
  
  
  

add a comment | 

Say I have a list like this:

alist = ['key': 'value']

And then I convert it to a dictionary like this

adict = dict(alist)

The formatting becomes

'''key: 'value'

This makes it so I can't access the data from the dictionary. Is there a way to convert the list to a dictionary without there being extra ' ' -- brackets and single quotes

python dictionary

share|improve this question

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

alist = ['key': 'value']

adict = dict(alist)

'''key: 'value'

share|improve this question

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

share|improve this question

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

edited Mar 24 at 2:18

martineau

71.7k1093190

edited Mar 24 at 2:18

martineau

71.7k1093190

asked Mar 23 at 23:35

the_martianthe_martian

352216

asked Mar 23 at 23:35

the_martianthe_martian

352216

3 Answers
3

active

oldest

votes

1

You can use the index 0 to avoid the extra braces because the dictionary can be accessed as alist[0]. Moreover, you do not need dict additionally because your list content is already a dictionary

adict = alist[0]

Now you get the desired behavior

print (adict)
# 'key': 'value'

share|improve this answer

edited Mar 23 at 23:39

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @DeveshKumarSingh: It works for me. Anyway, dict is not need here because the list contains already a dictionary. Check my edit
  
  – Sheldore
  Mar 23 at 23:41
  

  
  
  
  

add a comment | 

1

If you first structure your list by swapping the curly braces, you won't have any issues using this :)

dict([('A', 1), ('B', 2), ('C', 3)])

share|improve this answer

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

add a comment | 

0

If your objective is to initialise a dictionary object with a key value pair (or a bunch of key value pairs), why would you use a list first?

You could simple write

adict = 'key': 'value', 'Hello': 'world' 

print(adict)

share|improve this answer

answered Mar 23 at 23:43

GroGro

50549

add a comment | 

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1

You can use the index 0 to avoid the extra braces because the dictionary can be accessed as alist[0]. Moreover, you do not need dict additionally because your list content is already a dictionary

adict = alist[0]

Now you get the desired behavior

print (adict)
# 'key': 'value'

share|improve this answer

edited Mar 23 at 23:39

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @DeveshKumarSingh: It works for me. Anyway, dict is not need here because the list contains already a dictionary. Check my edit
  
  – Sheldore
  Mar 23 at 23:41
  

  
  
  
  

add a comment | 

1

You can use the index 0 to avoid the extra braces because the dictionary can be accessed as alist[0]. Moreover, you do not need dict additionally because your list content is already a dictionary

adict = alist[0]

Now you get the desired behavior

print (adict)
# 'key': 'value'

share|improve this answer

edited Mar 23 at 23:39

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @DeveshKumarSingh: It works for me. Anyway, dict is not need here because the list contains already a dictionary. Check my edit
  
  – Sheldore
  Mar 23 at 23:41
  

  
  
  
  

add a comment | 

You can use the index 0 to avoid the extra braces because the dictionary can be accessed as alist[0]. Moreover, you do not need dict additionally because your list content is already a dictionary

adict = alist[0]

Now you get the desired behavior

print (adict)
# 'key': 'value'

share|improve this answer

edited Mar 23 at 23:39

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

adict = alist[0]

print (adict)
# 'key': 'value'

share|improve this answer

edited Mar 23 at 23:39

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

answered Mar 23 at 23:37

SheldoreSheldore

17.4k31330

1

If you first structure your list by swapping the curly braces, you won't have any issues using this :)

dict([('A', 1), ('B', 2), ('C', 3)])

share|improve this answer

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

add a comment | 

1

If you first structure your list by swapping the curly braces, you won't have any issues using this :)

dict([('A', 1), ('B', 2), ('C', 3)])

share|improve this answer

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

add a comment | 

If you first structure your list by swapping the curly braces, you won't have any issues using this :)

dict([('A', 1), ('B', 2), ('C', 3)])

share|improve this answer

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

share|improve this answer

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

answered Mar 23 at 23:40

David SilveiroDavid Silveiro

595518

0

If your objective is to initialise a dictionary object with a key value pair (or a bunch of key value pairs), why would you use a list first?

You could simple write

adict = 'key': 'value', 'Hello': 'world' 

print(adict)

share|improve this answer

answered Mar 23 at 23:43

GroGro

50549

add a comment | 

0

If your objective is to initialise a dictionary object with a key value pair (or a bunch of key value pairs), why would you use a list first?

You could simple write

adict = 'key': 'value', 'Hello': 'world' 

print(adict)

share|improve this answer

answered Mar 23 at 23:43

GroGro

50549

add a comment | 

If your objective is to initialise a dictionary object with a key value pair (or a bunch of key value pairs), why would you use a list first?

You could simple write

adict = 'key': 'value', 'Hello': 'world' 

print(adict)

share|improve this answer

answered Mar 23 at 23:43

GroGro

50549

adict = 'key': 'value', 'Hello': 'world' 

print(adict)

share|improve this answer

answered Mar 23 at 23:43

GroGro

50549

answered Mar 23 at 23:43

GroGro

50549

answered Mar 23 at 23:43

GroGro

50549