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How does Padlevski code compile with no error [duplicate]

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This question already has an answer here:

• 
  What is this smiley-with-beard expression: “<:]%>”?
  
  4 answers
  
  


• 
  Why are there digraphs in C and C++?
  
  4 answers
  
  

The code associated to Padlevski compiles with no error.

int main() <:]()<%[]()[:>()<%();();(); 

In the c++ conference, he said that it is a lambda in lambda. I can only see one of the lambdas.

int main()

 <:]()<%
 []()
 
 [:>()<%();();
 }
 ();
}

I also do not understand <:, :>, <%.

How does it work?
wandbox

c++ lambda

share|improve this question

asked Mar 23 at 23:36

qiverqiver

62

marked as duplicate by Praetorian c++
Users with the  c++ badge can single-handedly close c++ questions as duplicates and reopen them as needed.

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Mar 23 at 23:40

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

0

This question already has an answer here:

• 
  What is this smiley-with-beard expression: “<:]%>”?
  
  4 answers
  
  


• 
  Why are there digraphs in C and C++?
  
  4 answers
  
  

The code associated to Padlevski compiles with no error.

int main() <:]()<%[]()[:>()<%();();(); }

In the c++ conference, he said that it is a lambda in lambda. I can only see one of the lambdas.

int main()

 <:]()<%
 []()
 
 [:>()<%();();
 }
 ();
}

I also do not understand <:, :>, <%.

How does it work?
wandbox

c++ lambda

share|improve this question

asked Mar 23 at 23:36

qiverqiver

62

marked as duplicate by Praetorian c++
Users with the  c++ badge can single-handedly close c++ questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
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$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
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$hover.showInfoMessage('',
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Mar 23 at 23:40

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

This question already has an answer here:

• 
  What is this smiley-with-beard expression: “<:]%>”?
  
  4 answers
  
  


• 
  Why are there digraphs in C and C++?
  
  4 answers
  
  

The code associated to Padlevski compiles with no error.

int main() <:]()<%[]()[:>()<%();();(); }

In the c++ conference, he said that it is a lambda in lambda. I can only see one of the lambdas.

int main()

 <:]()<%
 []()
 
 [:>()<%();();
 }
 ();
}

I also do not understand <:, :>, <%.

How does it work?
wandbox

c++ lambda

share|improve this question

asked Mar 23 at 23:36

qiverqiver

62

int main() <:]()<%[]()[:>()<%();();(); }

int main()

 <:]()<%
 []()
 
 [:>()<%();();
 }
 ();
}

share|improve this question

asked Mar 23 at 23:36

qiverqiver

62

share|improve this question

asked Mar 23 at 23:36

qiverqiver

62

asked Mar 23 at 23:36

qiverqiver

62

asked Mar 23 at 23:36

qiverqiver

62