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Django: How do I combine a list and a queryset, paginate both of them and iterate through them in the template?
How to combine 2 or more querysets in a Django view?How do I do a not equal in Django queryset filtering?django - convert a list back to a querysetHow to get the current URL within a Django template?How to concatenate strings in django templates?How to convert a Django QuerySet to a listHow to perform OR condition in django queryset?How do I find the duplicates in a list and create another list with them?Django - iterate number in for loop of a templateDjango multiple queryset combine into a pagination
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I'm finishing up my leader-board. I currently return the top 100 leaders for a given category. I need to attach the current rank to the results.
At first I tried the forloop.counter variable in the template, but since the results are paginated by 10 results at a time, each new page reset the counter.
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
results = paginator.get_page(page)
context = 'results': results, 'rank': rank
currently returning wrong rank on page 2,3 etc
django list templates pagination django-queryset
add a comment |
I'm finishing up my leader-board. I currently return the top 100 leaders for a given category. I need to attach the current rank to the results.
At first I tried the forloop.counter variable in the template, but since the results are paginated by 10 results at a time, each new page reset the counter.
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
results = paginator.get_page(page)
context = 'results': results, 'rank': rank
currently returning wrong rank on page 2,3 etc
django list templates pagination django-queryset
add a comment |
I'm finishing up my leader-board. I currently return the top 100 leaders for a given category. I need to attach the current rank to the results.
At first I tried the forloop.counter variable in the template, but since the results are paginated by 10 results at a time, each new page reset the counter.
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
results = paginator.get_page(page)
context = 'results': results, 'rank': rank
currently returning wrong rank on page 2,3 etc
django list templates pagination django-queryset
I'm finishing up my leader-board. I currently return the top 100 leaders for a given category. I need to attach the current rank to the results.
At first I tried the forloop.counter variable in the template, but since the results are paginated by 10 results at a time, each new page reset the counter.
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
results = paginator.get_page(page)
context = 'results': results, 'rank': rank
currently returning wrong rank on page 2,3 etc
django list templates pagination django-queryset
django list templates pagination django-queryset
asked Mar 23 at 4:48
crappy_hackercrappy_hacker
414
414
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The answer wasn't that hard: I just used zip to combine the list and queryset. For the pagination I just repeated the same paginate steps for the rank that I used for the queryset with new variable names. Finally, I iterated through the zipped variable in the template:
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
stats = paginator.get_page(page)
paginator2 = Paginator(rank, 10)
page2 = request.GET.get('page')
rank = paginator2.get_page(page2)
rank_and_query = zip(rank, stats)
context = 'rank_and_query': rank_and_query
% for rank,stats in rank_and_query %
<li> rank : stats.leader </li>
% endfor %
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The answer wasn't that hard: I just used zip to combine the list and queryset. For the pagination I just repeated the same paginate steps for the rank that I used for the queryset with new variable names. Finally, I iterated through the zipped variable in the template:
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
stats = paginator.get_page(page)
paginator2 = Paginator(rank, 10)
page2 = request.GET.get('page')
rank = paginator2.get_page(page2)
rank_and_query = zip(rank, stats)
context = 'rank_and_query': rank_and_query
% for rank,stats in rank_and_query %
<li> rank : stats.leader </li>
% endfor %
add a comment |
The answer wasn't that hard: I just used zip to combine the list and queryset. For the pagination I just repeated the same paginate steps for the rank that I used for the queryset with new variable names. Finally, I iterated through the zipped variable in the template:
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
stats = paginator.get_page(page)
paginator2 = Paginator(rank, 10)
page2 = request.GET.get('page')
rank = paginator2.get_page(page2)
rank_and_query = zip(rank, stats)
context = 'rank_and_query': rank_and_query
% for rank,stats in rank_and_query %
<li> rank : stats.leader </li>
% endfor %
add a comment |
The answer wasn't that hard: I just used zip to combine the list and queryset. For the pagination I just repeated the same paginate steps for the rank that I used for the queryset with new variable names. Finally, I iterated through the zipped variable in the template:
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
stats = paginator.get_page(page)
paginator2 = Paginator(rank, 10)
page2 = request.GET.get('page')
rank = paginator2.get_page(page2)
rank_and_query = zip(rank, stats)
context = 'rank_and_query': rank_and_query
% for rank,stats in rank_and_query %
<li> rank : stats.leader </li>
% endfor %
The answer wasn't that hard: I just used zip to combine the list and queryset. For the pagination I just repeated the same paginate steps for the rank that I used for the queryset with new variable names. Finally, I iterated through the zipped variable in the template:
def leaderboard(request):
stats = Leaderboard.objects.all().order_by('-most_hits')[:100]
rank = list(range(1, 101))
paginator = Paginator(stats, 10)
page = request.GET.get('page')
stats = paginator.get_page(page)
paginator2 = Paginator(rank, 10)
page2 = request.GET.get('page')
rank = paginator2.get_page(page2)
rank_and_query = zip(rank, stats)
context = 'rank_and_query': rank_and_query
% for rank,stats in rank_and_query %
<li> rank : stats.leader </li>
% endfor %
answered Mar 23 at 5:10
crappy_hackercrappy_hacker
414
414
add a comment |
add a comment |
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