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sending notification to one user using Channels 2

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0

I want to send notification to specific authenticated user using Channels 2.

In below code i am sending notification as a broadcast instead of that i want to send notification to a specific user.

from channels.generic.websocket import AsyncJsonWebsocketConsumer


class NotifyConsumer(AsyncJsonWebsocketConsumer):

 async def connect(self):
 await self.accept()
 await self.channel_layer.group_add("gossip", self.channel_name)
 print(f"Added self.channel_name channel to gossip")

 async def disconnect(self, close_code):
 await self.channel_layer.group_discard("gossip", self.channel_name)
 print(f"Removed self.channel_name channel to gossip")

 async def user_gossip(self, event):
 await self.send_json(event)
 print(f"Got message event at self.channel_name")

python django python-3.x websocket django-channels

share|improve this question

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

add a comment | 

0

I want to send notification to specific authenticated user using Channels 2.

In below code i am sending notification as a broadcast instead of that i want to send notification to a specific user.

from channels.generic.websocket import AsyncJsonWebsocketConsumer


class NotifyConsumer(AsyncJsonWebsocketConsumer):

 async def connect(self):
 await self.accept()
 await self.channel_layer.group_add("gossip", self.channel_name)
 print(f"Added self.channel_name channel to gossip")

 async def disconnect(self, close_code):
 await self.channel_layer.group_discard("gossip", self.channel_name)
 print(f"Removed self.channel_name channel to gossip")

 async def user_gossip(self, event):
 await self.send_json(event)
 print(f"Got message event at self.channel_name")

python django python-3.x websocket django-channels

share|improve this question

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

add a comment | 

I want to send notification to specific authenticated user using Channels 2.

In below code i am sending notification as a broadcast instead of that i want to send notification to a specific user.

from channels.generic.websocket import AsyncJsonWebsocketConsumer


class NotifyConsumer(AsyncJsonWebsocketConsumer):

 async def connect(self):
 await self.accept()
 await self.channel_layer.group_add("gossip", self.channel_name)
 print(f"Added self.channel_name channel to gossip")

 async def disconnect(self, close_code):
 await self.channel_layer.group_discard("gossip", self.channel_name)
 print(f"Removed self.channel_name channel to gossip")

 async def user_gossip(self, event):
 await self.send_json(event)
 print(f"Got message event at self.channel_name")

python django python-3.x websocket django-channels

share|improve this question

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

from channels.generic.websocket import AsyncJsonWebsocketConsumer


class NotifyConsumer(AsyncJsonWebsocketConsumer):

 async def connect(self):
 await self.accept()
 await self.channel_layer.group_add("gossip", self.channel_name)
 print(f"Added self.channel_name channel to gossip")

 async def disconnect(self, close_code):
 await self.channel_layer.group_discard("gossip", self.channel_name)
 print(f"Removed self.channel_name channel to gossip")

 async def user_gossip(self, event):
 await self.send_json(event)
 print(f"Got message event at self.channel_name")

share|improve this question

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

share|improve this question

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

asked Mar 23 at 4:52

Mukul MantoshMukul Mantosh

77112

1 Answer
1

active

oldest

votes

1

Most users new to Django-channels 2.x face this problem. let me explain.

self.channel_layer.group_add("gossip", self.channel_name) takes two arguments: room_name and channel_name

When you connect from your browser via socket to this consumer, you are creating a new socket connection called as channel. So, when you open multiple pages in your browser, multiple channels are created. Each channel has a unique Id/name : channel_name

room is a group of channels. If anyone sends a message to the room, all channels in that room will receive that message.

So, if you need to send a notification/message to a single user, then you must create a room only for that particular user.

Assuming that current user is passed in the consumer's scope.

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
 self.user_room_name,
 self.channel_name
 )

Whenever you send/broadcast a message to user_room_name, It will only be received by that user.

share|improve this answer

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

add a comment | 

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1

Most users new to Django-channels 2.x face this problem. let me explain.

self.channel_layer.group_add("gossip", self.channel_name) takes two arguments: room_name and channel_name

When you connect from your browser via socket to this consumer, you are creating a new socket connection called as channel. So, when you open multiple pages in your browser, multiple channels are created. Each channel has a unique Id/name : channel_name

room is a group of channels. If anyone sends a message to the room, all channels in that room will receive that message.

So, if you need to send a notification/message to a single user, then you must create a room only for that particular user.

Assuming that current user is passed in the consumer's scope.

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
 self.user_room_name,
 self.channel_name
 )

Whenever you send/broadcast a message to user_room_name, It will only be received by that user.

share|improve this answer

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

add a comment | 

1

Most users new to Django-channels 2.x face this problem. let me explain.

self.channel_layer.group_add("gossip", self.channel_name) takes two arguments: room_name and channel_name

When you connect from your browser via socket to this consumer, you are creating a new socket connection called as channel. So, when you open multiple pages in your browser, multiple channels are created. Each channel has a unique Id/name : channel_name

room is a group of channels. If anyone sends a message to the room, all channels in that room will receive that message.

So, if you need to send a notification/message to a single user, then you must create a room only for that particular user.

Assuming that current user is passed in the consumer's scope.

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
 self.user_room_name,
 self.channel_name
 )

Whenever you send/broadcast a message to user_room_name, It will only be received by that user.

share|improve this answer

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

add a comment | 

Most users new to Django-channels 2.x face this problem. let me explain.

self.channel_layer.group_add("gossip", self.channel_name) takes two arguments: room_name and channel_name

When you connect from your browser via socket to this consumer, you are creating a new socket connection called as channel. So, when you open multiple pages in your browser, multiple channels are created. Each channel has a unique Id/name : channel_name

room is a group of channels. If anyone sends a message to the room, all channels in that room will receive that message.

So, if you need to send a notification/message to a single user, then you must create a room only for that particular user.

Assuming that current user is passed in the consumer's scope.

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
 self.user_room_name,
 self.channel_name
 )

Whenever you send/broadcast a message to user_room_name, It will only be received by that user.

share|improve this answer

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
 self.user_room_name,
 self.channel_name
 )

share|improve this answer

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523

answered Mar 23 at 6:01

spiritsreespiritsree

1,8801523