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Trying to upload image using jquery

Is there an “exists” function for jQuery?How can I upload files asynchronously?Add table row in jQueryHow do I check if an element is hidden in jQuery?Setting “checked” for a checkbox with jQuery?How to check whether a checkbox is checked in jQuery?Disable/enable an input with jQuery?Preview an image before it is uploadedjQuery scroll to element“Thinking in AngularJS” if I have a jQuery background?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

can anybody help me? I' m trying to upload an image using jquery and laravel but don't know how to pass the data

Ajax Function

var form_data = new FormData();

form_data.append('file', file_data);
form_data.append('link', link);
form_data.append('comment', comment);
form_data.append('reportid', reportid);

$.ajax(
 url:" route('report.update') ",
 type:"GET",
 data:form_data,
 contentType:false,
 cache:false,
 processData:false,
 success:function(data) 
 alert(data);
 
);

Route

Route::get('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Controller:

public function reportUpdate(Request $request)

 $file = $request->file('file');

 echo $file->getClientOriginalName();

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

1

Change type GET to POST, and change your Route too

– Saromase
Mar 22 at 10:19

1

Firstly,your route is wrong, it should be POST. And you cannot directly send a file via AJAX like this. What you can do is upload the file using some other methods and pass the name or path of file in your form data.. You can use libraries like blueimp (github.com/blueimp/jQuery-File-Upload )to upload the file , and then pass the return file data in AJAX

– Sauav
Mar 22 at 10:30

add a comment |

can anybody help me? I' m trying to upload an image using jquery and laravel but don't know how to pass the data

Ajax Function

var form_data = new FormData();

form_data.append('file', file_data);
form_data.append('link', link);
form_data.append('comment', comment);
form_data.append('reportid', reportid);

$.ajax(
 url:" route('report.update') ",
 type:"GET",
 data:form_data,
 contentType:false,
 cache:false,
 processData:false,
 success:function(data) 
 alert(data);
 
);

Route

Route::get('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Controller:

public function reportUpdate(Request $request)

 $file = $request->file('file');

 echo $file->getClientOriginalName();

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

1

Change type GET to POST, and change your Route too

– Saromase
Mar 22 at 10:19

1

Firstly,your route is wrong, it should be POST. And you cannot directly send a file via AJAX like this. What you can do is upload the file using some other methods and pass the name or path of file in your form data.. You can use libraries like blueimp (github.com/blueimp/jQuery-File-Upload )to upload the file , and then pass the return file data in AJAX

– Sauav
Mar 22 at 10:30

add a comment |

can anybody help me? I' m trying to upload an image using jquery and laravel but don't know how to pass the data

Ajax Function

var form_data = new FormData();

form_data.append('file', file_data);
form_data.append('link', link);
form_data.append('comment', comment);
form_data.append('reportid', reportid);

$.ajax(
 url:" route('report.update') ",
 type:"GET",
 data:form_data,
 contentType:false,
 cache:false,
 processData:false,
 success:function(data) 
 alert(data);
 
);

Route

Route::get('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Controller:

public function reportUpdate(Request $request)

 $file = $request->file('file');

 echo $file->getClientOriginalName();

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

can anybody help me? I' m trying to upload an image using jquery and laravel but don't know how to pass the data

Ajax Function

var form_data = new FormData();

form_data.append('file', file_data);
form_data.append('link', link);
form_data.append('comment', comment);
form_data.append('reportid', reportid);

$.ajax(
 url:" route('report.update') ",
 type:"GET",
 data:form_data,
 contentType:false,
 cache:false,
 processData:false,
 success:function(data) 
 alert(data);
 
);

Route

Route::get('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Controller:

public function reportUpdate(Request $request)

 $file = $request->file('file');

 echo $file->getClientOriginalName();

jquery laravel

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

edited Mar 22 at 10:30

bhavinjr

981213

edited Mar 22 at 10:30

bhavinjr

981213

edited Mar 22 at 10:30

bhavinjr

981213

asked Mar 22 at 10:17

Mr. X

asked Mar 22 at 10:17

Mr. X

asked Mar 22 at 10:17

Mr. X

1

Change type GET to POST, and change your Route too

– Saromase
Mar 22 at 10:19

1

Firstly,your route is wrong, it should be POST. And you cannot directly send a file via AJAX like this. What you can do is upload the file using some other methods and pass the name or path of file in your form data.. You can use libraries like blueimp (github.com/blueimp/jQuery-File-Upload )to upload the file , and then pass the return file data in AJAX

– Sauav
Mar 22 at 10:30

add a comment |

1

Change type GET to POST, and change your Route too

– Saromase
Mar 22 at 10:19

1

Firstly,your route is wrong, it should be POST. And you cannot directly send a file via AJAX like this. What you can do is upload the file using some other methods and pass the name or path of file in your form data.. You can use libraries like blueimp (github.com/blueimp/jQuery-File-Upload )to upload the file , and then pass the return file data in AJAX

– Sauav
Mar 22 at 10:30

Change type GET to POST, and change your Route too

– Saromase
Mar 22 at 10:19

Firstly,your route is wrong, it should be POST. And you cannot directly send a file via AJAX like this. What you can do is upload the file using some other methods and pass the name or path of file in your form data.. You can use libraries like blueimp (github.com/blueimp/jQuery-File-Upload )to upload the file , and then pass the return file data in AJAX

– Sauav
Mar 22 at 10:30

add a comment |

3 Answers
3

active

oldest

votes

Ajax

 $("#FormId").on('submit', (function(e) 
 e.preventDefault();
 $.ajax(
 url: " route('report.update') ",
 type: "POST",
 data: new FormData(this),
 contentType: false,
 cache: false,
 processData: false,
 success: function(data) 
 


 )
 ));

Route

Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Function

public function reportUpdate(Request $request)

 $file = $request->file('file');

 $fileName = time().$request->file('file')->getClientOriginalName();
 $path=$file->move('FolderPath',$fileName);

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

add a comment |

add enctype="multipart/form-data" in your form

enctype="multipart/form-data"

$.ajax(

 url:" route('report.update') ",
 type:"POST",
 data:form_data,
 contentType:false,
 processData:false,
 success:function(data)
 alert(data);
 

);

 Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

answered Mar 22 at 10:24

Akash Kumar Verma

830414

add a comment |

just try this

var formData = new FormData($("#formid")[0]);
$.ajax(
 url: " route('report.update') ",
 type: 'POST',
 dataType: 'JSON',
 data: formData,
 processData: false,
 contentType: false,
 enctype: 'multipart/form-data',
 mimeType: 'multipart/form-data',
 cache: false,
 success: function(data, textStatus, jqXHR) 
 console.log(data)
 
);

and use form method is POST

answered Mar 23 at 4:21

Paras Raiyani

793

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

Ajax

 $("#FormId").on('submit', (function(e) 
 e.preventDefault();
 $.ajax(
 url: " route('report.update') ",
 type: "POST",
 data: new FormData(this),
 contentType: false,
 cache: false,
 processData: false,
 success: function(data) 
 


 )
 ));

Route

Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Function

public function reportUpdate(Request $request)

 $file = $request->file('file');

 $fileName = time().$request->file('file')->getClientOriginalName();
 $path=$file->move('FolderPath',$fileName);

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

add a comment |

Ajax

 $("#FormId").on('submit', (function(e) 
 e.preventDefault();
 $.ajax(
 url: " route('report.update') ",
 type: "POST",
 data: new FormData(this),
 contentType: false,
 cache: false,
 processData: false,
 success: function(data) 
 


 )
 ));

Route

Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Function

public function reportUpdate(Request $request)

 $file = $request->file('file');

 $fileName = time().$request->file('file')->getClientOriginalName();
 $path=$file->move('FolderPath',$fileName);

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

add a comment |

Ajax

 $("#FormId").on('submit', (function(e) 
 e.preventDefault();
 $.ajax(
 url: " route('report.update') ",
 type: "POST",
 data: new FormData(this),
 contentType: false,
 cache: false,
 processData: false,
 success: function(data) 
 


 )
 ));

Route

Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Function

public function reportUpdate(Request $request)

 $file = $request->file('file');

 $fileName = time().$request->file('file')->getClientOriginalName();
 $path=$file->move('FolderPath',$fileName);

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

Ajax

 $("#FormId").on('submit', (function(e) 
 e.preventDefault();
 $.ajax(
 url: " route('report.update') ",
 type: "POST",
 data: new FormData(this),
 contentType: false,
 cache: false,
 processData: false,
 success: function(data) 
 


 )
 ));

Route

Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

Function

public function reportUpdate(Request $request)

 $file = $request->file('file');

 $fileName = time().$request->file('file')->getClientOriginalName();
 $path=$file->move('FolderPath',$fileName);

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

answered Mar 23 at 4:32

JIJOMON K.A

1,2481724

add a comment |

add enctype="multipart/form-data" in your form

enctype="multipart/form-data"

$.ajax(

 url:" route('report.update') ",
 type:"POST",
 data:form_data,
 contentType:false,
 processData:false,
 success:function(data)
 alert(data);
 

);

 Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

answered Mar 22 at 10:24

Akash Kumar Verma

830414

add a comment |

add enctype="multipart/form-data" in your form

enctype="multipart/form-data"

$.ajax(

 url:" route('report.update') ",
 type:"POST",
 data:form_data,
 contentType:false,
 processData:false,
 success:function(data)
 alert(data);
 

);

 Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

answered Mar 22 at 10:24

Akash Kumar Verma

830414

add a comment |

add enctype="multipart/form-data" in your form

enctype="multipart/form-data"

$.ajax(

 url:" route('report.update') ",
 type:"POST",
 data:form_data,
 contentType:false,
 processData:false,
 success:function(data)
 alert(data);
 

);

 Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

answered Mar 22 at 10:24

Akash Kumar Verma

830414

add enctype="multipart/form-data" in your form

enctype="multipart/form-data"

$.ajax(

 url:" route('report.update') ",
 type:"POST",
 data:form_data,
 contentType:false,
 processData:false,
 success:function(data)
 alert(data);
 

);

 Route::POST('report-update', ['uses'=>'Executive@reportUpdate', 'as'=>'report.update']);

answered Mar 22 at 10:24

Akash Kumar Verma

830414

answered Mar 22 at 10:24

Akash Kumar Verma

830414

answered Mar 22 at 10:24

Akash Kumar Verma

830414

answered Mar 22 at 10:24

Akash Kumar Verma

830414

add a comment |

just try this

var formData = new FormData($("#formid")[0]);
$.ajax(
 url: " route('report.update') ",
 type: 'POST',
 dataType: 'JSON',
 data: formData,
 processData: false,
 contentType: false,
 enctype: 'multipart/form-data',
 mimeType: 'multipart/form-data',
 cache: false,
 success: function(data, textStatus, jqXHR) 
 console.log(data)
 
);

and use form method is POST

answered Mar 23 at 4:21

Paras Raiyani

793

add a comment |

just try this

var formData = new FormData($("#formid")[0]);
$.ajax(
 url: " route('report.update') ",
 type: 'POST',
 dataType: 'JSON',
 data: formData,
 processData: false,
 contentType: false,
 enctype: 'multipart/form-data',
 mimeType: 'multipart/form-data',
 cache: false,
 success: function(data, textStatus, jqXHR) 
 console.log(data)
 
);

and use form method is POST

answered Mar 23 at 4:21

Paras Raiyani

793

add a comment |

just try this

var formData = new FormData($("#formid")[0]);
$.ajax(
 url: " route('report.update') ",
 type: 'POST',
 dataType: 'JSON',
 data: formData,
 processData: false,
 contentType: false,
 enctype: 'multipart/form-data',
 mimeType: 'multipart/form-data',
 cache: false,
 success: function(data, textStatus, jqXHR) 
 console.log(data)
 
);

and use form method is POST

answered Mar 23 at 4:21

Paras Raiyani

793

just try this

var formData = new FormData($("#formid")[0]);
$.ajax(
 url: " route('report.update') ",
 type: 'POST',
 dataType: 'JSON',
 data: formData,
 processData: false,
 contentType: false,
 enctype: 'multipart/form-data',
 mimeType: 'multipart/form-data',
 cache: false,
 success: function(data, textStatus, jqXHR) 
 console.log(data)
 
);

and use form method is POST

answered Mar 23 at 4:21

Paras Raiyani

793

answered Mar 23 at 4:21

Paras Raiyani

793

answered Mar 23 at 4:21

Paras Raiyani

793

answered Mar 23 at 4:21

Paras Raiyani

793

add a comment |

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