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filtering a javascript table based upon its values

How do JavaScript closures work?Which “href” value should I use for JavaScript links, “#” or “javascript:void(0)”?How do I remove a property from a JavaScript object?Which equals operator (== vs ===) should be used in JavaScript comparisons?How do I include a JavaScript file in another JavaScript file?Sort array of objects by string property valueWhat does “use strict” do in JavaScript, and what is the reasoning behind it?How to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?For-each over an array in JavaScript?

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-2

My table/Array is created in Javascript and is not hard codded in HTML.

I am trying to filter and return the table based on any one who has visited the UK.

I want to place a function with the parameters of (candidates, countries).

var people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
 ];

I have tried

people.filter(person=>person.countries.includes('UK'))

However the table is not dynamic and does not change to reflect this on my webpage if i use this code, instead it just returns the original array of 'people'. Why doesn't this approach work?

javascript arrays sorting

share|improve this question

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  people.filter(person=>person.countries.includes('UK'))
  
  – Gabriele Petrioli
  Mar 23 at 23:18
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  "I am trying to filter" ... show us what you have actually tried. Stackoverflow isn't a free code writing service. The objective is for you to show your attempts to solve issues yourself and others help when code doesn't work as expected
  
  – charlietfl
  Mar 23 at 23:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This works - however when i console.log(people) after this code it still brings back the original array, instead of the new array which should only include those people who have been to the UK
  
  – seebz
  Mar 24 at 0:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  filter returns a new Array, it doesn't modify the original. Try people = people.filter(…).
  
  – twhb
  Mar 24 at 1:26
  

  
  
  
  

add a comment | 

-2

My table/Array is created in Javascript and is not hard codded in HTML.

I am trying to filter and return the table based on any one who has visited the UK.

I want to place a function with the parameters of (candidates, countries).

var people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
 ];

I have tried

people.filter(person=>person.countries.includes('UK'))

However the table is not dynamic and does not change to reflect this on my webpage if i use this code, instead it just returns the original array of 'people'. Why doesn't this approach work?

javascript arrays sorting

share|improve this question

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  people.filter(person=>person.countries.includes('UK'))
  
  – Gabriele Petrioli
  Mar 23 at 23:18
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  "I am trying to filter" ... show us what you have actually tried. Stackoverflow isn't a free code writing service. The objective is for you to show your attempts to solve issues yourself and others help when code doesn't work as expected
  
  – charlietfl
  Mar 23 at 23:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This works - however when i console.log(people) after this code it still brings back the original array, instead of the new array which should only include those people who have been to the UK
  
  – seebz
  Mar 24 at 0:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  filter returns a new Array, it doesn't modify the original. Try people = people.filter(…).
  
  – twhb
  Mar 24 at 1:26
  

  
  
  
  

add a comment | 

My table/Array is created in Javascript and is not hard codded in HTML.

I am trying to filter and return the table based on any one who has visited the UK.

I want to place a function with the parameters of (candidates, countries).

var people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
 ];

I have tried

people.filter(person=>person.countries.includes('UK'))

However the table is not dynamic and does not change to reflect this on my webpage if i use this code, instead it just returns the original array of 'people'. Why doesn't this approach work?

javascript arrays sorting

share|improve this question

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

var people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
 ];

people.filter(person=>person.countries.includes('UK'))

share|improve this question

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

share|improve this question

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

edited Mar 24 at 5:10

David C. Rankin

44.9k33252

asked Mar 23 at 23:14

seebzseebz

61

asked Mar 23 at 23:14

seebzseebz

61

1 Answer
1

active

oldest

votes

0

I think this is what are you looking for:

const people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
];

const filterCandidates = (candidates, country) =>
 candidates.filter(( countries ) => countries.includes(country));

result:

["name":"Matt","countries":["UK","USA","Russia"],"name":"Ben","countries":["UK","India"],"name":"Katie","countries":["UK","China"]]

https://es6console.com/jtm4kvvn/

share|improve this answer

answered Mar 23 at 23:32

MichalMichal

112

add a comment | 

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0

I think this is what are you looking for:

const people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
];

const filterCandidates = (candidates, country) =>
 candidates.filter(( countries ) => countries.includes(country));

result:

["name":"Matt","countries":["UK","USA","Russia"],"name":"Ben","countries":["UK","India"],"name":"Katie","countries":["UK","China"]]

https://es6console.com/jtm4kvvn/

share|improve this answer

answered Mar 23 at 23:32

MichalMichal

112

add a comment | 

0

I think this is what are you looking for:

const people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
];

const filterCandidates = (candidates, country) =>
 candidates.filter(( countries ) => countries.includes(country));

result:

["name":"Matt","countries":["UK","USA","Russia"],"name":"Ben","countries":["UK","India"],"name":"Katie","countries":["UK","China"]]

https://es6console.com/jtm4kvvn/

share|improve this answer

answered Mar 23 at 23:32

MichalMichal

112

add a comment | 

I think this is what are you looking for:

const people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
];

const filterCandidates = (candidates, country) =>
 candidates.filter(( countries ) => countries.includes(country));

result:

["name":"Matt","countries":["UK","USA","Russia"],"name":"Ben","countries":["UK","India"],"name":"Katie","countries":["UK","China"]]

https://es6console.com/jtm4kvvn/

share|improve this answer

answered Mar 23 at 23:32

MichalMichal

112

const people = [
 name: "Matt", countries: ["UK", "USA", "Russia"] ,
 name: "Simon", countries: ["Canada", "China"] ,
 name: "Ben", countries: ["UK", "India"] ,
 name: "Katie", countries: ["UK", "China"] ,
 name: "Omar", countries: ["Canada", "China"] ,
 name: "Simon", countries: ["India", "China", "USA"] ,
];

const filterCandidates = (candidates, country) =>
 candidates.filter(( countries ) => countries.includes(country));

share|improve this answer

answered Mar 23 at 23:32

MichalMichal

112

answered Mar 23 at 23:32

MichalMichal

112

answered Mar 23 at 23:32

MichalMichal

112