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i have if condition in program what that exact value be in that condition?

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0

I have a while loop and if conditions in this program and output will be everything is fine. but,my problem is in if condition like
if arr[i]<dep[j] in that condition arr[i] means arr[1]. but dep[j] means, I don't know the index. can anyone explain this code?

here is the code.

def bus(arr, dep, n):
 arr.sort()
 dep.sort()
 p = 1
 r = 1
 i = 1
 j = 0
 while i < n and j < n:
 if arr[i] < dep[j]:
 print(arr[i], dep[j])
 print(dep[j])
 p += 1
 print(p)
 i += 1
 if p > r:
 r = p
 print(r, p)
 else:
 p -= 1
 print(p)
 j += 1
 return r


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

python python-3.x python-2.7

share|improve this question

edited Mar 25 at 7:01

Brahma Reddy

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What exactly is your problem?
  
  – DirtyBit
  Mar 25 at 6:32
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if arr[i]<dep[j]: print(arr[i],dep[j]) print(dep[j]) p+=1 print(p) i+=1 in this condition if arr[i]<dep[j]: the value 1120 value will be stored dep[ j ] .why exactly 1120 will be stored in this condition.
  
  – Brahma Reddy
  Mar 25 at 6:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why you are staring i from 1 ?
  
  – Muthu Kumar
  Mar 25 at 6:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  because i don't want to start with oth index.that's why i take 1 index.
  
  – Brahma Reddy
  Mar 25 at 6:47
  

  
  
  
  

add a comment | 

0

I have a while loop and if conditions in this program and output will be everything is fine. but,my problem is in if condition like
if arr[i]<dep[j] in that condition arr[i] means arr[1]. but dep[j] means, I don't know the index. can anyone explain this code?

here is the code.

def bus(arr, dep, n):
 arr.sort()
 dep.sort()
 p = 1
 r = 1
 i = 1
 j = 0
 while i < n and j < n:
 if arr[i] < dep[j]:
 print(arr[i], dep[j])
 print(dep[j])
 p += 1
 print(p)
 i += 1
 if p > r:
 r = p
 print(r, p)
 else:
 p -= 1
 print(p)
 j += 1
 return r


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

python python-3.x python-2.7

share|improve this question

edited Mar 25 at 7:01

Brahma Reddy

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What exactly is your problem?
  
  – DirtyBit
  Mar 25 at 6:32
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if arr[i]<dep[j]: print(arr[i],dep[j]) print(dep[j]) p+=1 print(p) i+=1 in this condition if arr[i]<dep[j]: the value 1120 value will be stored dep[ j ] .why exactly 1120 will be stored in this condition.
  
  – Brahma Reddy
  Mar 25 at 6:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why you are staring i from 1 ?
  
  – Muthu Kumar
  Mar 25 at 6:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  because i don't want to start with oth index.that's why i take 1 index.
  
  – Brahma Reddy
  Mar 25 at 6:47
  

  
  
  
  

add a comment | 

I have a while loop and if conditions in this program and output will be everything is fine. but,my problem is in if condition like
if arr[i]<dep[j] in that condition arr[i] means arr[1]. but dep[j] means, I don't know the index. can anyone explain this code?

here is the code.

def bus(arr, dep, n):
 arr.sort()
 dep.sort()
 p = 1
 r = 1
 i = 1
 j = 0
 while i < n and j < n:
 if arr[i] < dep[j]:
 print(arr[i], dep[j])
 print(dep[j])
 p += 1
 print(p)
 i += 1
 if p > r:
 r = p
 print(r, p)
 else:
 p -= 1
 print(p)
 j += 1
 return r


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

python python-3.x python-2.7

share|improve this question

edited Mar 25 at 7:01

Brahma Reddy

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

def bus(arr, dep, n):
 arr.sort()
 dep.sort()
 p = 1
 r = 1
 i = 1
 j = 0
 while i < n and j < n:
 if arr[i] < dep[j]:
 print(arr[i], dep[j])
 print(dep[j])
 p += 1
 print(p)
 i += 1
 if p > r:
 r = p
 print(r, p)
 else:
 p -= 1
 print(p)
 j += 1
 return r


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this question

edited Mar 25 at 7:01

Brahma Reddy

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

share|improve this question

edited Mar 25 at 7:01

Brahma Reddy

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

asked Mar 25 at 6:31

Brahma ReddyBrahma Reddy

165

1 Answer
1

active

oldest

votes

0

Your program is little reformatted with the meaningful variable names. Hope this will answer your problem.

def bus(arr, dep, total_bus):
 arr.sort()
 dep.sort()

 if total_bus == 0:
 # when there is no bus
 return 0

 if dep[0] > arr[total_bus - 1]:
 # when all bus comes in and after bus leaving 1 by 1
 return n

 platform = 1
 arr_index = 1
 dep_index = 0
 cur_bus = 1
 while arr_index < total_bus and dep_index < total_bus:
 if arr[arr_index] > dep[dep_index]:
 dep_index += 1
 cur_bus -= 1
 else:
 cur_bus += 1
 arr_index += 1
 if cur_bus > platform:
 platform += 1

 return platform


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this answer

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

add a comment | 

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0

Your program is little reformatted with the meaningful variable names. Hope this will answer your problem.

def bus(arr, dep, total_bus):
 arr.sort()
 dep.sort()

 if total_bus == 0:
 # when there is no bus
 return 0

 if dep[0] > arr[total_bus - 1]:
 # when all bus comes in and after bus leaving 1 by 1
 return n

 platform = 1
 arr_index = 1
 dep_index = 0
 cur_bus = 1
 while arr_index < total_bus and dep_index < total_bus:
 if arr[arr_index] > dep[dep_index]:
 dep_index += 1
 cur_bus -= 1
 else:
 cur_bus += 1
 arr_index += 1
 if cur_bus > platform:
 platform += 1

 return platform


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this answer

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

add a comment | 

0

Your program is little reformatted with the meaningful variable names. Hope this will answer your problem.

def bus(arr, dep, total_bus):
 arr.sort()
 dep.sort()

 if total_bus == 0:
 # when there is no bus
 return 0

 if dep[0] > arr[total_bus - 1]:
 # when all bus comes in and after bus leaving 1 by 1
 return n

 platform = 1
 arr_index = 1
 dep_index = 0
 cur_bus = 1
 while arr_index < total_bus and dep_index < total_bus:
 if arr[arr_index] > dep[dep_index]:
 dep_index += 1
 cur_bus -= 1
 else:
 cur_bus += 1
 arr_index += 1
 if cur_bus > platform:
 platform += 1

 return platform


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this answer

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

add a comment | 

Your program is little reformatted with the meaningful variable names. Hope this will answer your problem.

def bus(arr, dep, total_bus):
 arr.sort()
 dep.sort()

 if total_bus == 0:
 # when there is no bus
 return 0

 if dep[0] > arr[total_bus - 1]:
 # when all bus comes in and after bus leaving 1 by 1
 return n

 platform = 1
 arr_index = 1
 dep_index = 0
 cur_bus = 1
 while arr_index < total_bus and dep_index < total_bus:
 if arr[arr_index] > dep[dep_index]:
 dep_index += 1
 cur_bus -= 1
 else:
 cur_bus += 1
 arr_index += 1
 if cur_bus > platform:
 platform += 1

 return platform


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this answer

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

def bus(arr, dep, total_bus):
 arr.sort()
 dep.sort()

 if total_bus == 0:
 # when there is no bus
 return 0

 if dep[0] > arr[total_bus - 1]:
 # when all bus comes in and after bus leaving 1 by 1
 return n

 platform = 1
 arr_index = 1
 dep_index = 0
 cur_bus = 1
 while arr_index < total_bus and dep_index < total_bus:
 if arr[arr_index] > dep[dep_index]:
 dep_index += 1
 cur_bus -= 1
 else:
 cur_bus += 1
 arr_index += 1
 if cur_bus > platform:
 platform += 1

 return platform


arr = [900, 940, 950, 1100, 1500, 1800]
dep = [910, 1200, 1120, 1130, 1900, 2000]
n = len(arr)
print('min no.of platforms:', bus(arr, dep, n))

share|improve this answer

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212

answered Mar 25 at 7:24

Muthu KumarMuthu Kumar

336212