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Perl5Matcher.matches(input, pattern) is returning true for input containing semicolon even when semicolon is not in pattern
Matcher returns matches on a regex pattern, but split() fails to find a match on the same regex?Regular expression pattern with ? character and characterSequense contains unicode characterFinding whether a string meets a certain patternI need something to look at the characters in a string and accept the string if it only has the certain characters in Javareturning true with an occurance of a letter in a string?Java RegEx match string containing non-ASCII that exceeds given lengthRegular expression for a string contains characters not in a specific setFREJ Regex cannot match non alphanumeric charactersUsing regex/String Method: Print Words containing PatternMatch all the letters in string
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have a string MyString = "AP;"; or any other number of strings containing ;
When I attempt to validate that MyString matches a pattern
eg. MyPattern = "^[a-zA-Z0-9 ()+-_.]*$";
Which I believe should allow AlphaNumerics, and the characters ()+-_.]* but not ;
However the below statement is returning True!
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_.]*$");
Perl5Matcher matcher = new Perl5Matcher();
if (matcher.matches("AP;", sepMatchPattern))
return true;
else
return false;
Can anyone explain why the semicolon keeps getting allowed through?
java pattern-matching
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
add a comment |
I have a string MyString = "AP;"; or any other number of strings containing ;
When I attempt to validate that MyString matches a pattern
eg. MyPattern = "^[a-zA-Z0-9 ()+-_.]*$";
Which I believe should allow AlphaNumerics, and the characters ()+-_.]* but not ;
However the below statement is returning True!
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_.]*$");
Perl5Matcher matcher = new Perl5Matcher();
if (matcher.matches("AP;", sepMatchPattern))
return true;
else
return false;
Can anyone explain why the semicolon keeps getting allowed through?
java pattern-matching
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
add a comment |
I have a string MyString = "AP;"; or any other number of strings containing ;
When I attempt to validate that MyString matches a pattern
eg. MyPattern = "^[a-zA-Z0-9 ()+-_.]*$";
Which I believe should allow AlphaNumerics, and the characters ()+-_.]* but not ;
However the below statement is returning True!
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_.]*$");
Perl5Matcher matcher = new Perl5Matcher();
if (matcher.matches("AP;", sepMatchPattern))
return true;
else
return false;
Can anyone explain why the semicolon keeps getting allowed through?
java pattern-matching
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
I have a string MyString = "AP;"; or any other number of strings containing ;
When I attempt to validate that MyString matches a pattern
eg. MyPattern = "^[a-zA-Z0-9 ()+-_.]*$";
Which I believe should allow AlphaNumerics, and the characters ()+-_.]* but not ;
However the below statement is returning True!
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_.]*$");
Perl5Matcher matcher = new Perl5Matcher();
if (matcher.matches("AP;", sepMatchPattern))
return true;
else
return false;
Can anyone explain why the semicolon keeps getting allowed through?
java pattern-matching
java pattern-matching
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
edited Mar 25 at 6:57
Jonathan Leffler
583k966971053
583k966971053
asked Feb 18 '13 at 17:51
SolidSolid
2016
asked Feb 18 '13 at 17:51
SolidSolid
2016
asked Feb 18 '13 at 17:51
SolidSolid
2016
2016
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The problem lies in the regular expression that you have defined - ^[a-zA-Z0-9 ()+-_.]*$. Within this regular expression is a character class of alpha (upper and lower), numeric, space, parentheses, and some punctuation. One of the punctuation characters is a period. The period is not escaped, and thus it has its original meaning of any character (including a semi colon).
This regex will match any string - it is essentially ^.*$.
To fix this, escape the period.
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_\.]*$");
Edit:
It turns out that there is another item that I missed in there that has special meaning. The hyphen in the character class of "+-_" does not mean "plus, hyphen, or underscore". Rather, it means all the characters from 0x2B to 0x5F (inclusive). A quick test shows that ^[+-_]*$ also matches AP; because A and P are 0x41 and 0x50 and the notorious semicolon is 0x3B - all within the range of 0x2B to 0x5F.
The correct regular expression is:
"^[a-zA-Z0-9 ()+\-_\.]*$"
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
add a comment |
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The problem lies in the regular expression that you have defined - ^[a-zA-Z0-9 ()+-_.]*$. Within this regular expression is a character class of alpha (upper and lower), numeric, space, parentheses, and some punctuation. One of the punctuation characters is a period. The period is not escaped, and thus it has its original meaning of any character (including a semi colon).
This regex will match any string - it is essentially ^.*$.
To fix this, escape the period.
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_\.]*$");
Edit:
It turns out that there is another item that I missed in there that has special meaning. The hyphen in the character class of "+-_" does not mean "plus, hyphen, or underscore". Rather, it means all the characters from 0x2B to 0x5F (inclusive). A quick test shows that ^[+-_]*$ also matches AP; because A and P are 0x41 and 0x50 and the notorious semicolon is 0x3B - all within the range of 0x2B to 0x5F.
The correct regular expression is:
"^[a-zA-Z0-9 ()+\-_\.]*$"
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
add a comment |
The problem lies in the regular expression that you have defined - ^[a-zA-Z0-9 ()+-_.]*$. Within this regular expression is a character class of alpha (upper and lower), numeric, space, parentheses, and some punctuation. One of the punctuation characters is a period. The period is not escaped, and thus it has its original meaning of any character (including a semi colon).
This regex will match any string - it is essentially ^.*$.
To fix this, escape the period.
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_\.]*$");
Edit:
It turns out that there is another item that I missed in there that has special meaning. The hyphen in the character class of "+-_" does not mean "plus, hyphen, or underscore". Rather, it means all the characters from 0x2B to 0x5F (inclusive). A quick test shows that ^[+-_]*$ also matches AP; because A and P are 0x41 and 0x50 and the notorious semicolon is 0x3B - all within the range of 0x2B to 0x5F.
The correct regular expression is:
"^[a-zA-Z0-9 ()+\-_\.]*$"
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
add a comment |
The problem lies in the regular expression that you have defined - ^[a-zA-Z0-9 ()+-_.]*$. Within this regular expression is a character class of alpha (upper and lower), numeric, space, parentheses, and some punctuation. One of the punctuation characters is a period. The period is not escaped, and thus it has its original meaning of any character (including a semi colon).
This regex will match any string - it is essentially ^.*$.
To fix this, escape the period.
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_\.]*$");
Edit:
It turns out that there is another item that I missed in there that has special meaning. The hyphen in the character class of "+-_" does not mean "plus, hyphen, or underscore". Rather, it means all the characters from 0x2B to 0x5F (inclusive). A quick test shows that ^[+-_]*$ also matches AP; because A and P are 0x41 and 0x50 and the notorious semicolon is 0x3B - all within the range of 0x2B to 0x5F.
The correct regular expression is:
"^[a-zA-Z0-9 ()+\-_\.]*$"
The problem lies in the regular expression that you have defined - ^[a-zA-Z0-9 ()+-_.]*$. Within this regular expression is a character class of alpha (upper and lower), numeric, space, parentheses, and some punctuation. One of the punctuation characters is a period. The period is not escaped, and thus it has its original meaning of any character (including a semi colon).
This regex will match any string - it is essentially ^.*$.
To fix this, escape the period.
Pattern sepMatchPattern = sepMatchCompiler.compile("^[a-zA-Z0-9 ()+-_\.]*$");
Edit:
It turns out that there is another item that I missed in there that has special meaning. The hyphen in the character class of "+-_" does not mean "plus, hyphen, or underscore". Rather, it means all the characters from 0x2B to 0x5F (inclusive). A quick test shows that ^[+-_]*$ also matches AP; because A and P are 0x41 and 0x50 and the notorious semicolon is 0x3B - all within the range of 0x2B to 0x5F.
The correct regular expression is:
"^[a-zA-Z0-9 ()+\-_\.]*$"
edited Feb 19 '13 at 15:08
answered Feb 18 '13 at 18:34
user289086
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
add a comment |
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
Thanks MichaelT however I've added the escaping and ; still passes. Even without the escaping though strings with % or £ will still fail.
– Solid
Feb 19 '13 at 9:26
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
@Ethan Ah ha, there's another thing that needs escaping in there that I missed. The dash.
– user289086
Feb 19 '13 at 15:01
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
Thanks again Michael. I am confused as to why % was returning false before the escaping was introduced, if . was allowing any character to return true.
– Solid
Feb 20 '13 at 9:43
add a comment |
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