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Create an array of timestamps in python


Calling an external command in PythonWhat are metaclasses in Python?Finding the index of an item given a list containing it in PythonHow do you get a timestamp in JavaScript?How can I safely create a nested directory?Does Python have a ternary conditional operator?Should I use the datetime or timestamp data type in MySQL?How to get the current time in PythonDoes Python have a string 'contains' substring method?single positional indexer is out-of-bounds index error






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2















I have been trying to create a time vector in python 3.x to plot wind velocity against time.

Wind Velocity was sampled every 5 minutes, starting from 00:00 and finishing at 23:55 (i.e., 288 samples per day).



I use pandas to read the data. I store velocity variables in a numpy vector. I saved variables using numpy.array(met1.loc[ini:fin, 'm/s Wind']) and work perfect for wind speed. When I tried to do it for datetime variables, as numpy.array(met1.loc[ini:fin, 'Measurement Time']) showed me the next error:



'the label [Measurement Time] is not in the [columns]' (please see code behind for more detail)



met1.head() looks like this:



 . m/s Wind m/s Gusts ° Direction RH °C Temp 
Measurement Time
2018-11-13 11:20:00 6.77 9.5 268 0.068590 12.6
2018-11-13 11:25:00 6.90 10.4 284 0.067255 12.9
2018-11-13 11:30:00 6.59 11.3 279 0.066381 13.1
2018-11-13 11:35:00 7.10 10.1 279 0.073019 13.1
2018-11-13 11:40:00 6.01 9.8 273 0.073498 13.0


Code looks like this:



import numpy as np
import pandas as pd

met1 = pd.read_excel('database.xls', sheet_name=0, skiprows=2, index_col = 'Measurement Time', parse_dates=[0]) #reading data base

def variables (ini, fin):
# Variables for MET-1
wind1 = np.array(met1.loc[ini:fin, 'm/s Wind'])
dir1 = np.array(met1.loc[ini:fin, '° Direction'])
rh1 = np.array(met1.loc[ini:fin, 'RH']) # 0.123
temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
print(wind1)
print(tiempo)

variables('2018-11-15','2018-11-15')


---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1789 if not ax.contains(key):
-> 1790 error()
1791 except TypeError as e:

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786

KeyError: 'the label [Measurement Time] is not in the [columns]'

During handling of the above exception, another exception occurred:

KeyError Traceback (most recent call last)
<ipython-input-182-130dc8c7095b> in <module>
1 # variables('2018-11-13','2018-11-13') # Mount day
2 # variables('2018-11-14','2018-11-14') # Mount day
----> 3 variables('2018-11-15','2018-11-15')
4 variables('2018-11-16','2018-11-16')
5 variables('2018-11-17','2018-11-17')

<ipython-input-181-2a7e1e919435> in variables(ini, fin)
17 temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
18 p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
---> 19 tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
20 print(tiempo)
21

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1470 except (KeyError, IndexError):
1471 pass
-> 1472 return self._getitem_tuple(key)
1473 else:
1474 # we by definition only have the 0th axis

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
868 def _getitem_tuple(self, tup):
869 try:
--> 870 return self._getitem_lowerdim(tup)
871 except IndexingError:
872 pass

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
996 for i, key in enumerate(tup):
997 if is_label_like(key) or isinstance(key, tuple):
--> 998 section = self._getitem_axis(key, axis=i)
999
1000 # we have yielded a scalar ?

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1909
1910 # fall thru to straight lookup
-> 1911 self._validate_key(key, axis)
1912 return self._get_label(key, axis=axis)
1913

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1796 raise
1797 except:
-> 1798 error()
1799
1800 def _is_scalar_access(self, key):

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1783 raise KeyError(u"the label [key] is not in the [axis]"
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786
1787 try:

KeyError: 'the label [Measurement Time] is not in the [columns]'


The time vector I need should look like this!!!: ['00:00' '00:05' ..... '23:50' '23:55'] for date '2018-11-15'










share|improve this question
























  • please provide the sample data for your question.

    – Regressor
    Mar 25 at 18:25











  • Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

    – Matias SIGNORIO DUQUE
    Mar 25 at 19:53











  • And what isn't working, exactly?

    – juanpa.arrivillaga
    Mar 25 at 19:53











  • If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

    – vurmux
    Mar 25 at 20:01






  • 1





    Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

    – juanpa.arrivillaga
    Mar 25 at 20:07

















2















I have been trying to create a time vector in python 3.x to plot wind velocity against time.

Wind Velocity was sampled every 5 minutes, starting from 00:00 and finishing at 23:55 (i.e., 288 samples per day).



I use pandas to read the data. I store velocity variables in a numpy vector. I saved variables using numpy.array(met1.loc[ini:fin, 'm/s Wind']) and work perfect for wind speed. When I tried to do it for datetime variables, as numpy.array(met1.loc[ini:fin, 'Measurement Time']) showed me the next error:



'the label [Measurement Time] is not in the [columns]' (please see code behind for more detail)



met1.head() looks like this:



 . m/s Wind m/s Gusts ° Direction RH °C Temp 
Measurement Time
2018-11-13 11:20:00 6.77 9.5 268 0.068590 12.6
2018-11-13 11:25:00 6.90 10.4 284 0.067255 12.9
2018-11-13 11:30:00 6.59 11.3 279 0.066381 13.1
2018-11-13 11:35:00 7.10 10.1 279 0.073019 13.1
2018-11-13 11:40:00 6.01 9.8 273 0.073498 13.0


Code looks like this:



import numpy as np
import pandas as pd

met1 = pd.read_excel('database.xls', sheet_name=0, skiprows=2, index_col = 'Measurement Time', parse_dates=[0]) #reading data base

def variables (ini, fin):
# Variables for MET-1
wind1 = np.array(met1.loc[ini:fin, 'm/s Wind'])
dir1 = np.array(met1.loc[ini:fin, '° Direction'])
rh1 = np.array(met1.loc[ini:fin, 'RH']) # 0.123
temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
print(wind1)
print(tiempo)

variables('2018-11-15','2018-11-15')


---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1789 if not ax.contains(key):
-> 1790 error()
1791 except TypeError as e:

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786

KeyError: 'the label [Measurement Time] is not in the [columns]'

During handling of the above exception, another exception occurred:

KeyError Traceback (most recent call last)
<ipython-input-182-130dc8c7095b> in <module>
1 # variables('2018-11-13','2018-11-13') # Mount day
2 # variables('2018-11-14','2018-11-14') # Mount day
----> 3 variables('2018-11-15','2018-11-15')
4 variables('2018-11-16','2018-11-16')
5 variables('2018-11-17','2018-11-17')

<ipython-input-181-2a7e1e919435> in variables(ini, fin)
17 temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
18 p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
---> 19 tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
20 print(tiempo)
21

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1470 except (KeyError, IndexError):
1471 pass
-> 1472 return self._getitem_tuple(key)
1473 else:
1474 # we by definition only have the 0th axis

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
868 def _getitem_tuple(self, tup):
869 try:
--> 870 return self._getitem_lowerdim(tup)
871 except IndexingError:
872 pass

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
996 for i, key in enumerate(tup):
997 if is_label_like(key) or isinstance(key, tuple):
--> 998 section = self._getitem_axis(key, axis=i)
999
1000 # we have yielded a scalar ?

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1909
1910 # fall thru to straight lookup
-> 1911 self._validate_key(key, axis)
1912 return self._get_label(key, axis=axis)
1913

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1796 raise
1797 except:
-> 1798 error()
1799
1800 def _is_scalar_access(self, key):

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1783 raise KeyError(u"the label [key] is not in the [axis]"
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786
1787 try:

KeyError: 'the label [Measurement Time] is not in the [columns]'


The time vector I need should look like this!!!: ['00:00' '00:05' ..... '23:50' '23:55'] for date '2018-11-15'










share|improve this question
























  • please provide the sample data for your question.

    – Regressor
    Mar 25 at 18:25











  • Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

    – Matias SIGNORIO DUQUE
    Mar 25 at 19:53











  • And what isn't working, exactly?

    – juanpa.arrivillaga
    Mar 25 at 19:53











  • If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

    – vurmux
    Mar 25 at 20:01






  • 1





    Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

    – juanpa.arrivillaga
    Mar 25 at 20:07













2












2








2








I have been trying to create a time vector in python 3.x to plot wind velocity against time.

Wind Velocity was sampled every 5 minutes, starting from 00:00 and finishing at 23:55 (i.e., 288 samples per day).



I use pandas to read the data. I store velocity variables in a numpy vector. I saved variables using numpy.array(met1.loc[ini:fin, 'm/s Wind']) and work perfect for wind speed. When I tried to do it for datetime variables, as numpy.array(met1.loc[ini:fin, 'Measurement Time']) showed me the next error:



'the label [Measurement Time] is not in the [columns]' (please see code behind for more detail)



met1.head() looks like this:



 . m/s Wind m/s Gusts ° Direction RH °C Temp 
Measurement Time
2018-11-13 11:20:00 6.77 9.5 268 0.068590 12.6
2018-11-13 11:25:00 6.90 10.4 284 0.067255 12.9
2018-11-13 11:30:00 6.59 11.3 279 0.066381 13.1
2018-11-13 11:35:00 7.10 10.1 279 0.073019 13.1
2018-11-13 11:40:00 6.01 9.8 273 0.073498 13.0


Code looks like this:



import numpy as np
import pandas as pd

met1 = pd.read_excel('database.xls', sheet_name=0, skiprows=2, index_col = 'Measurement Time', parse_dates=[0]) #reading data base

def variables (ini, fin):
# Variables for MET-1
wind1 = np.array(met1.loc[ini:fin, 'm/s Wind'])
dir1 = np.array(met1.loc[ini:fin, '° Direction'])
rh1 = np.array(met1.loc[ini:fin, 'RH']) # 0.123
temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
print(wind1)
print(tiempo)

variables('2018-11-15','2018-11-15')


---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1789 if not ax.contains(key):
-> 1790 error()
1791 except TypeError as e:

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786

KeyError: 'the label [Measurement Time] is not in the [columns]'

During handling of the above exception, another exception occurred:

KeyError Traceback (most recent call last)
<ipython-input-182-130dc8c7095b> in <module>
1 # variables('2018-11-13','2018-11-13') # Mount day
2 # variables('2018-11-14','2018-11-14') # Mount day
----> 3 variables('2018-11-15','2018-11-15')
4 variables('2018-11-16','2018-11-16')
5 variables('2018-11-17','2018-11-17')

<ipython-input-181-2a7e1e919435> in variables(ini, fin)
17 temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
18 p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
---> 19 tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
20 print(tiempo)
21

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1470 except (KeyError, IndexError):
1471 pass
-> 1472 return self._getitem_tuple(key)
1473 else:
1474 # we by definition only have the 0th axis

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
868 def _getitem_tuple(self, tup):
869 try:
--> 870 return self._getitem_lowerdim(tup)
871 except IndexingError:
872 pass

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
996 for i, key in enumerate(tup):
997 if is_label_like(key) or isinstance(key, tuple):
--> 998 section = self._getitem_axis(key, axis=i)
999
1000 # we have yielded a scalar ?

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1909
1910 # fall thru to straight lookup
-> 1911 self._validate_key(key, axis)
1912 return self._get_label(key, axis=axis)
1913

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1796 raise
1797 except:
-> 1798 error()
1799
1800 def _is_scalar_access(self, key):

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1783 raise KeyError(u"the label [key] is not in the [axis]"
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786
1787 try:

KeyError: 'the label [Measurement Time] is not in the [columns]'


The time vector I need should look like this!!!: ['00:00' '00:05' ..... '23:50' '23:55'] for date '2018-11-15'










share|improve this question
















I have been trying to create a time vector in python 3.x to plot wind velocity against time.

Wind Velocity was sampled every 5 minutes, starting from 00:00 and finishing at 23:55 (i.e., 288 samples per day).



I use pandas to read the data. I store velocity variables in a numpy vector. I saved variables using numpy.array(met1.loc[ini:fin, 'm/s Wind']) and work perfect for wind speed. When I tried to do it for datetime variables, as numpy.array(met1.loc[ini:fin, 'Measurement Time']) showed me the next error:



'the label [Measurement Time] is not in the [columns]' (please see code behind for more detail)



met1.head() looks like this:



 . m/s Wind m/s Gusts ° Direction RH °C Temp 
Measurement Time
2018-11-13 11:20:00 6.77 9.5 268 0.068590 12.6
2018-11-13 11:25:00 6.90 10.4 284 0.067255 12.9
2018-11-13 11:30:00 6.59 11.3 279 0.066381 13.1
2018-11-13 11:35:00 7.10 10.1 279 0.073019 13.1
2018-11-13 11:40:00 6.01 9.8 273 0.073498 13.0


Code looks like this:



import numpy as np
import pandas as pd

met1 = pd.read_excel('database.xls', sheet_name=0, skiprows=2, index_col = 'Measurement Time', parse_dates=[0]) #reading data base

def variables (ini, fin):
# Variables for MET-1
wind1 = np.array(met1.loc[ini:fin, 'm/s Wind'])
dir1 = np.array(met1.loc[ini:fin, '° Direction'])
rh1 = np.array(met1.loc[ini:fin, 'RH']) # 0.123
temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
print(wind1)
print(tiempo)

variables('2018-11-15','2018-11-15')


---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1789 if not ax.contains(key):
-> 1790 error()
1791 except TypeError as e:

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786

KeyError: 'the label [Measurement Time] is not in the [columns]'

During handling of the above exception, another exception occurred:

KeyError Traceback (most recent call last)
<ipython-input-182-130dc8c7095b> in <module>
1 # variables('2018-11-13','2018-11-13') # Mount day
2 # variables('2018-11-14','2018-11-14') # Mount day
----> 3 variables('2018-11-15','2018-11-15')
4 variables('2018-11-16','2018-11-16')
5 variables('2018-11-17','2018-11-17')

<ipython-input-181-2a7e1e919435> in variables(ini, fin)
17 temp1 = np.array(met1.loc[ini:fin, '°C Temp'])
18 p1 = np.array(met1.loc[ini:fin, 'kPa Pressure'])
---> 19 tiempo = np.array(met1.loc[ini:fin, 'Measurement Time'])
20 print(tiempo)
21

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in __getitem__(self, key)
1470 except (KeyError, IndexError):
1471 pass
-> 1472 return self._getitem_tuple(key)
1473 else:
1474 # we by definition only have the 0th axis

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
868 def _getitem_tuple(self, tup):
869 try:
--> 870 return self._getitem_lowerdim(tup)
871 except IndexingError:
872 pass

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
996 for i, key in enumerate(tup):
997 if is_label_like(key) or isinstance(key, tuple):
--> 998 section = self._getitem_axis(key, axis=i)
999
1000 # we have yielded a scalar ?

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
1909
1910 # fall thru to straight lookup
-> 1911 self._validate_key(key, axis)
1912 return self._get_label(key, axis=axis)
1913

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
1796 raise
1797 except:
-> 1798 error()
1799
1800 def _is_scalar_access(self, key):

~/anaconda3/lib/python3.6/site-packages/pandas/core/indexing.py in error()
1783 raise KeyError(u"the label [key] is not in the [axis]"
1784 .format(key=key,
-> 1785 axis=self.obj._get_axis_name(axis)))
1786
1787 try:

KeyError: 'the label [Measurement Time] is not in the [columns]'


The time vector I need should look like this!!!: ['00:00' '00:05' ..... '23:50' '23:55'] for date '2018-11-15'







python python-3.x datetime time






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 25 at 20:39







Matias SIGNORIO DUQUE

















asked Mar 25 at 18:05









Matias SIGNORIO DUQUEMatias SIGNORIO DUQUE

114 bronze badges




114 bronze badges












  • please provide the sample data for your question.

    – Regressor
    Mar 25 at 18:25











  • Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

    – Matias SIGNORIO DUQUE
    Mar 25 at 19:53











  • And what isn't working, exactly?

    – juanpa.arrivillaga
    Mar 25 at 19:53











  • If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

    – vurmux
    Mar 25 at 20:01






  • 1





    Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

    – juanpa.arrivillaga
    Mar 25 at 20:07

















  • please provide the sample data for your question.

    – Regressor
    Mar 25 at 18:25











  • Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

    – Matias SIGNORIO DUQUE
    Mar 25 at 19:53











  • And what isn't working, exactly?

    – juanpa.arrivillaga
    Mar 25 at 19:53











  • If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

    – vurmux
    Mar 25 at 20:01






  • 1





    Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

    – juanpa.arrivillaga
    Mar 25 at 20:07
















please provide the sample data for your question.

– Regressor
Mar 25 at 18:25





please provide the sample data for your question.

– Regressor
Mar 25 at 18:25













Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

– Matias SIGNORIO DUQUE
Mar 25 at 19:53





Thanks for your answer. I add the head of the database. I tried to save the variable as tiempo = np.array(met1.loc[ini:fin, 'Measurement Time']) but when I print(tiempo) show me the next error: 'the label [Measurement Time] is not in the [columns]'

– Matias SIGNORIO DUQUE
Mar 25 at 19:53













And what isn't working, exactly?

– juanpa.arrivillaga
Mar 25 at 19:53





And what isn't working, exactly?

– juanpa.arrivillaga
Mar 25 at 19:53













If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

– vurmux
Mar 25 at 20:01





If you store measurement time in Python strings, you can just crop them with slices: datetime = datetime[:-3]

– vurmux
Mar 25 at 20:01




1




1





Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

– juanpa.arrivillaga
Mar 25 at 20:07





Edit your question don't put this in the comments. Show us, exactly the output you are seeing and provide an example of the output you require.

– juanpa.arrivillaga
Mar 25 at 20:07












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