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Getting exception while fetching a list from subquery
How to get an enum value from a string value in Java?HQl equivalent of sql queryHibernate: HQL Row Count Subquery issueJPA/hibernate subquery in from clauseHibernate HQL for finding by parameter and criteriahow to use Oracle's regexp_like in Hibernate HQL?hibernate HQL error for update query when use join onselecting records from tables using HQL Query…@HQL QuerySyntaxExceptionHow to select data from SubQuery in HQL?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I want to fetch a list from a subquery in HQL
return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);
I am getting error
•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]
java hibernate hql
add a comment |
I want to fetch a list from a subquery in HQL
return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);
I am getting error
•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]
java hibernate hql
1
Yes, because it's invalid, just like it says. Maybe you meant to have the=?inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.
– Dave Newton
Mar 26 at 13:49
add a comment |
I want to fetch a list from a subquery in HQL
return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);
I am getting error
•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]
java hibernate hql
I want to fetch a list from a subquery in HQL
return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);
I am getting error
•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]
java hibernate hql
java hibernate hql
edited Mar 26 at 13:48
Dave Newton
143k20 gold badges220 silver badges260 bronze badges
143k20 gold badges220 silver badges260 bronze badges
asked Mar 26 at 9:47
sumant kumarsumant kumar
13 bronze badges
13 bronze badges
1
Yes, because it's invalid, just like it says. Maybe you meant to have the=?inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.
– Dave Newton
Mar 26 at 13:49
add a comment |
1
Yes, because it's invalid, just like it says. Maybe you meant to have the=?inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.
– Dave Newton
Mar 26 at 13:49
1
1
Yes, because it's invalid, just like it says. Maybe you meant to have the
=? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.– Dave Newton
Mar 26 at 13:49
Yes, because it's invalid, just like it says. Maybe you meant to have the
=? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.– Dave Newton
Mar 26 at 13:49
add a comment |
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Yes, because it's invalid, just like it says. Maybe you meant to have the
=?inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.– Dave Newton
Mar 26 at 13:49