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Getting exception while fetching a list from subquery


How to get an enum value from a string value in Java?HQl equivalent of sql queryHibernate: HQL Row Count Subquery issueJPA/hibernate subquery in from clauseHibernate HQL for finding by parameter and criteriahow to use Oracle's regexp_like in Hibernate HQL?hibernate HQL error for update query when use join onselecting records from tables using HQL Query…@HQL QuerySyntaxExceptionHow to select data from SubQuery in HQL?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I want to fetch a list from a subquery in HQL



return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);


I am getting error




•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]











share|improve this question



















  • 1





    Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

    – Dave Newton
    Mar 26 at 13:49

















0















I want to fetch a list from a subquery in HQL



return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);


I am getting error




•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]











share|improve this question



















  • 1





    Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

    – Dave Newton
    Mar 26 at 13:49













0












0








0








I want to fetch a list from a subquery in HQL



return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);


I am getting error




•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]











share|improve this question
















I want to fetch a list from a subquery in HQL



return (List<Sitecnb>) hibernateTemplate.find(
"from Sitecnb as sc where sc.countrycnbCode in(from Land as ld where ld.landKennzeichen)= ? ", name);


I am getting error




•An unexpected error occured. Details: unexpected AST node: in near
line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as sc
where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land as
ld where ld.landKennzeichen)= ? ]; nested exception is
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in
near line 1, column 75 [from com.bearingpoint.sisnet.domain.Sitecnb as
sc where sc.countrycnbCode in(from com.bearingpoint.sisnet.domain.Land
as ld where ld.landKennzeichen)= ? ]








java hibernate hql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 13:48









Dave Newton

143k20 gold badges220 silver badges260 bronze badges




143k20 gold badges220 silver badges260 bronze badges










asked Mar 26 at 9:47









sumant kumarsumant kumar

13 bronze badges




13 bronze badges







  • 1





    Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

    – Dave Newton
    Mar 26 at 13:49












  • 1





    Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

    – Dave Newton
    Mar 26 at 13:49







1




1





Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

– Dave Newton
Mar 26 at 13:49





Yes, because it's invalid, just like it says. Maybe you meant to have the =? inside the parentheses instead of dangling outside? This is a basic syntax problem, which IMO means you should probably take a step back and actually learn a little bit about HQL instead of typing random strings.

– Dave Newton
Mar 26 at 13:49












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