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How to filter out certain combinations?

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1

I'm trying to filter the input of a TextBox using Regex. I need up to 3 numbers before the decimal point and I need 2 after it. This can be in any form.

I've tried changing the regex commands around but it creates errors and single inputs won't be valid. I'm using a TextBox in WPF to collect the data.

bool containsLetter = Regex.IsMatch(units.Text, "^[0-9]1,3([.] [0-9] 1,3)?$");
if (containsLetter == true)

 MessageBox.Show("error");

return containsLetter;

I want the regex filter to accept these types of inputs:

111.11,
11.11,
1.11,
1.01,
100,
10,
1,

c# regex wpf filter

share|improve this question

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Looks like all you have to do is remove the spaces from your regex pattern. Why did you add them in the first place?
  
  – Ahmed Abdelhameed
  Mar 26 at 1:46
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if we have answered your question, could you please accept an answer/upvote as detailed in: stackoverflow.com/help/someone-answers
  
  – Allan
  Apr 2 at 0:53
  

  
  
  
  

add a comment | 

1

I'm trying to filter the input of a TextBox using Regex. I need up to 3 numbers before the decimal point and I need 2 after it. This can be in any form.

I've tried changing the regex commands around but it creates errors and single inputs won't be valid. I'm using a TextBox in WPF to collect the data.

bool containsLetter = Regex.IsMatch(units.Text, "^[0-9]1,3([.] [0-9] 1,3)?$");
if (containsLetter == true)

 MessageBox.Show("error");

return containsLetter;

I want the regex filter to accept these types of inputs:

111.11,
11.11,
1.11,
1.01,
100,
10,
1,

c# regex wpf filter

share|improve this question

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Looks like all you have to do is remove the spaces from your regex pattern. Why did you add them in the first place?
  
  – Ahmed Abdelhameed
  Mar 26 at 1:46
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if we have answered your question, could you please accept an answer/upvote as detailed in: stackoverflow.com/help/someone-answers
  
  – Allan
  Apr 2 at 0:53
  

  
  
  
  

add a comment | 

I'm trying to filter the input of a TextBox using Regex. I need up to 3 numbers before the decimal point and I need 2 after it. This can be in any form.

I've tried changing the regex commands around but it creates errors and single inputs won't be valid. I'm using a TextBox in WPF to collect the data.

bool containsLetter = Regex.IsMatch(units.Text, "^[0-9]1,3([.] [0-9] 1,3)?$");
if (containsLetter == true)

 MessageBox.Show("error");

return containsLetter;

I want the regex filter to accept these types of inputs:

111.11,
11.11,
1.11,
1.01,
100,
10,
1,

c# regex wpf filter

share|improve this question

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

bool containsLetter = Regex.IsMatch(units.Text, "^[0-9]1,3([.] [0-9] 1,3)?$");
if (containsLetter == true)

 MessageBox.Show("error");

return containsLetter;

111.11,
11.11,
1.11,
1.01,
100,
10,
1,

share|improve this question

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

share|improve this question

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

edited Mar 26 at 1:49

Ahmed Abdelhameed

7,19688 gold badges2525 silver badges4949 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

asked Mar 26 at 1:44

xxishxxish

2755 bronze badges

1 Answer
1

active

oldest

votes

1

As it has been mentioned in the comment, spaces are characters that will be interpreted literally in your regex pattern.

Therefore in this part of your regex:

([.] [0-9] 1,3)

• a space is expected between . and [0-9],


• the same goes for after [0-9] where the regex would match 1 to 3 spaces.

This being said, for readability purpose you have several way to construct your regex.

1) Put the comments out of the regex:

string myregex = @"s" // Match any whitespace once
+ @"n" // Match one newline character
+ @"[a-zA-Z]"; // Match any letter

2) Add comments within your regex by using the syntax (?#comment)

needle(?# this will find a needle)

Example

3) Activate free-spacing mode within your regex:

nee # this will find a nee...
dle # ...dle (the split means nothing when white-space is ignored)

doc: https://www.regular-expressions.info/freespacing.html

Example

share|improve this answer

edited Mar 26 at 3:26

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

add a comment | 

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1

As it has been mentioned in the comment, spaces are characters that will be interpreted literally in your regex pattern.

Therefore in this part of your regex:

([.] [0-9] 1,3)

• a space is expected between . and [0-9],


• the same goes for after [0-9] where the regex would match 1 to 3 spaces.

This being said, for readability purpose you have several way to construct your regex.

1) Put the comments out of the regex:

string myregex = @"s" // Match any whitespace once
+ @"n" // Match one newline character
+ @"[a-zA-Z]"; // Match any letter

2) Add comments within your regex by using the syntax (?#comment)

needle(?# this will find a needle)

Example

3) Activate free-spacing mode within your regex:

nee # this will find a nee...
dle # ...dle (the split means nothing when white-space is ignored)

doc: https://www.regular-expressions.info/freespacing.html

Example

share|improve this answer

edited Mar 26 at 3:26

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

add a comment | 

1

As it has been mentioned in the comment, spaces are characters that will be interpreted literally in your regex pattern.

Therefore in this part of your regex:

([.] [0-9] 1,3)

• a space is expected between . and [0-9],


• the same goes for after [0-9] where the regex would match 1 to 3 spaces.

This being said, for readability purpose you have several way to construct your regex.

1) Put the comments out of the regex:

string myregex = @"s" // Match any whitespace once
+ @"n" // Match one newline character
+ @"[a-zA-Z]"; // Match any letter

2) Add comments within your regex by using the syntax (?#comment)

needle(?# this will find a needle)

Example

3) Activate free-spacing mode within your regex:

nee # this will find a nee...
dle # ...dle (the split means nothing when white-space is ignored)

doc: https://www.regular-expressions.info/freespacing.html

Example

share|improve this answer

edited Mar 26 at 3:26

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

add a comment | 

As it has been mentioned in the comment, spaces are characters that will be interpreted literally in your regex pattern.

Therefore in this part of your regex:

([.] [0-9] 1,3)

• a space is expected between . and [0-9],


• the same goes for after [0-9] where the regex would match 1 to 3 spaces.

This being said, for readability purpose you have several way to construct your regex.

1) Put the comments out of the regex:

string myregex = @"s" // Match any whitespace once
+ @"n" // Match one newline character
+ @"[a-zA-Z]"; // Match any letter

2) Add comments within your regex by using the syntax (?#comment)

needle(?# this will find a needle)

Example

3) Activate free-spacing mode within your regex:

nee # this will find a nee...
dle # ...dle (the split means nothing when white-space is ignored)

doc: https://www.regular-expressions.info/freespacing.html

Example

share|improve this answer

edited Mar 26 at 3:26

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

string myregex = @"s" // Match any whitespace once
+ @"n" // Match one newline character
+ @"[a-zA-Z]"; // Match any letter

share|improve this answer

edited Mar 26 at 3:26

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges

answered Mar 26 at 2:14

AllanAllan

9,86733 gold badges1515 silver badges3737 bronze badges