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How to fix exception in self._validate_spec(raw_spec)?
How to merge two dictionaries in a single expression?How do I check if a list is empty?How do I check whether a file exists without exceptions?How can I safely create a nested directory?How do I sort a dictionary by value?How to make a chain of function decorators?How to make a flat list out of list of listsManually raising (throwing) an exception in PythonHow do I list all files of a directory?Catch multiple exceptions in one line (except block)
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I am attempting to generate Flask code, using Connexion, from a .yaml file containing OpenAPI 3.0.0 specifications.
When I execute this:
I get
import connexion
app = connexion.App(__name__, specification_dir='swagger/')
app.add_api('Contato.yaml')
app.run(port=8080)
and I get this exception:
connexion.exceptions.InvalidSpecification: 'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato', 'x-scope': [''] is not valid under any of the given schemas
Failed validating 'oneOf' in schema['properties']['paths']['patternProperties']['^/']['properties']['get']['properties']['responses']['patternProperties']['^([0-9X]3)$']:
'oneOf': ['$ref': '#/definitions/response',
'$ref': '#/definitions/reference']
On instance['paths']['/idContato']['get']['responses']['200']:
'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato',
'x-scope': ['']
The .yaml file does not include 'x-scope'.
Where is this definition coming from?
How can I overcome this exception?
python flask-restful connexion
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
add a comment |
I am attempting to generate Flask code, using Connexion, from a .yaml file containing OpenAPI 3.0.0 specifications.
When I execute this:
I get
import connexion
app = connexion.App(__name__, specification_dir='swagger/')
app.add_api('Contato.yaml')
app.run(port=8080)
and I get this exception:
connexion.exceptions.InvalidSpecification: 'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato', 'x-scope': [''] is not valid under any of the given schemas
Failed validating 'oneOf' in schema['properties']['paths']['patternProperties']['^/']['properties']['get']['properties']['responses']['patternProperties']['^([0-9X]3)$']:
'oneOf': ['$ref': '#/definitions/response',
'$ref': '#/definitions/reference']
On instance['paths']['/idContato']['get']['responses']['200']:
'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato',
'x-scope': ['']
The .yaml file does not include 'x-scope'.
Where is this definition coming from?
How can I overcome this exception?
python flask-restful connexion
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
add a comment |
I am attempting to generate Flask code, using Connexion, from a .yaml file containing OpenAPI 3.0.0 specifications.
When I execute this:
I get
import connexion
app = connexion.App(__name__, specification_dir='swagger/')
app.add_api('Contato.yaml')
app.run(port=8080)
and I get this exception:
connexion.exceptions.InvalidSpecification: 'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato', 'x-scope': [''] is not valid under any of the given schemas
Failed validating 'oneOf' in schema['properties']['paths']['patternProperties']['^/']['properties']['get']['properties']['responses']['patternProperties']['^([0-9X]3)$']:
'oneOf': ['$ref': '#/definitions/response',
'$ref': '#/definitions/reference']
On instance['paths']['/idContato']['get']['responses']['200']:
'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato',
'x-scope': ['']
The .yaml file does not include 'x-scope'.
Where is this definition coming from?
How can I overcome this exception?
python flask-restful connexion
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
I am attempting to generate Flask code, using Connexion, from a .yaml file containing OpenAPI 3.0.0 specifications.
When I execute this:
I get
import connexion
app = connexion.App(__name__, specification_dir='swagger/')
app.add_api('Contato.yaml')
app.run(port=8080)
and I get this exception:
connexion.exceptions.InvalidSpecification: 'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato', 'x-scope': [''] is not valid under any of the given schemas
Failed validating 'oneOf' in schema['properties']['paths']['patternProperties']['^/']['properties']['get']['properties']['responses']['patternProperties']['^([0-9X]3)$']:
'oneOf': ['$ref': '#/definitions/response',
'$ref': '#/definitions/reference']
On instance['paths']['/idContato']['get']['responses']['200']:
'content': 'application/json': 'schema': '$ref': '#/components/schemas/Contato',
'x-scope': ['']
The .yaml file does not include 'x-scope'.
Where is this definition coming from?
How can I overcome this exception?
python flask-restful connexion
python flask-restful connexion
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
edited Mar 26 at 3:19
midniteOverflow
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
asked Mar 26 at 1:27
midniteOverflowmidniteOverflow
86 bronze badges
86 bronze badges
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I could not reproduce the error, I need more information but I believe this error was corrected in:
https://github.com/Yelp/swagger_spec_validator/issues/50
Add in your requirements file:
swagger-spec-validator == 2.4.0
I believe it will solve
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I could not reproduce the error, I need more information but I believe this error was corrected in:
https://github.com/Yelp/swagger_spec_validator/issues/50
Add in your requirements file:
swagger-spec-validator == 2.4.0
I believe it will solve
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
add a comment |
I could not reproduce the error, I need more information but I believe this error was corrected in:
https://github.com/Yelp/swagger_spec_validator/issues/50
Add in your requirements file:
swagger-spec-validator == 2.4.0
I believe it will solve
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
add a comment |
I could not reproduce the error, I need more information but I believe this error was corrected in:
https://github.com/Yelp/swagger_spec_validator/issues/50
Add in your requirements file:
swagger-spec-validator == 2.4.0
I believe it will solve
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
I could not reproduce the error, I need more information but I believe this error was corrected in:
https://github.com/Yelp/swagger_spec_validator/issues/50
Add in your requirements file:
swagger-spec-validator == 2.4.0
I believe it will solve
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
answered Apr 5 at 13:45
Kevin MartinsKevin Martins
1281 silver badge9 bronze badges
1281 silver badge9 bronze badges
add a comment |
add a comment |
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