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Counting the number of option tags in a select tag in jQuery

How do I check how many options there are in a dropdown menu?How to count number of option tags using jQuery?How to get visible options' count of HTML select tag, with multiple attribute set, while size not set?Jquery selector on child counthow can I calculate number of options tag when I get the select box with $thisIs there an “exists” function for jQuery?How do I check if an element is hidden in jQuery?jQuery get specific option tag textSetting “checked” for a checkbox with jQuery?How can I know which radio button is selected via jQuery?How to check whether a checkbox is checked in jQuery?Get selected text from a drop-down list (select box) using jQueryjQuery scroll to elementjQuery Get Selected Option From Dropdown

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151

11

How do I count the number of <option>s in a <select> DOM element using jQuery?

<select data-attr="dropdown" id="input1">
 <option value="Male" id="Male">Male</option>
 <option value="Female" id="Female">Female</option>
</select>

I want to find the number of <option> tags in the <select> DOM element, since with that I want to open the settings panel with that number of input fields with the corresponding option value from the drop-down box in it and to change it again in the preview panel.

The above drop-down box is in my preview panel which is generated by jQuery.

javascript jquery html

share|improve this question

edited Aug 17 at 13:00

Sebastian Simon

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asked Jul 20 '09 at 10:11

MercyMercy

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add a comment
 | 

151

11

How do I count the number of <option>s in a <select> DOM element using jQuery?

<select data-attr="dropdown" id="input1">
 <option value="Male" id="Male">Male</option>
 <option value="Female" id="Female">Female</option>
</select>

I want to find the number of <option> tags in the <select> DOM element, since with that I want to open the settings panel with that number of input fields with the corresponding option value from the drop-down box in it and to change it again in the preview panel.

The above drop-down box is in my preview panel which is generated by jQuery.

javascript jquery html

share|improve this question

edited Aug 17 at 13:00

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

asked Jul 20 '09 at 10:11

MercyMercy

96833 gold badges1111 silver badges1515 bronze badges

add a comment
 | 

How do I count the number of <option>s in a <select> DOM element using jQuery?

<select data-attr="dropdown" id="input1">
 <option value="Male" id="Male">Male</option>
 <option value="Female" id="Female">Female</option>
</select>

I want to find the number of <option> tags in the <select> DOM element, since with that I want to open the settings panel with that number of input fields with the corresponding option value from the drop-down box in it and to change it again in the preview panel.

The above drop-down box is in my preview panel which is generated by jQuery.

javascript jquery html

share|improve this question

edited Aug 17 at 13:00

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

asked Jul 20 '09 at 10:11

MercyMercy

96833 gold badges1111 silver badges1515 bronze badges

<select data-attr="dropdown" id="input1">
 <option value="Male" id="Male">Male</option>
 <option value="Female" id="Female">Female</option>
</select>

share|improve this question

edited Aug 17 at 13:00

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

asked Jul 20 '09 at 10:11

MercyMercy

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share|improve this question

edited Aug 17 at 13:00

Sebastian Simon

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asked Jul 20 '09 at 10:11

MercyMercy

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edited Aug 17 at 13:00

Sebastian Simon

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edited Aug 17 at 13:00

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

asked Jul 20 '09 at 10:11

MercyMercy

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asked Jul 20 '09 at 10:11

MercyMercy

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8 Answers
8

active

oldest

votes

245

$('#input1 option').length;

This will produce 2.

share|improve this answer

edited Aug 17 at 12:56

Sebastian Simon

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answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

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 | 

50

The W3C solution:

var len = document.getElementById("input1").length;

share|improve this answer

answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  A variation to this method with modern javascript will be var len = document.querySelector("#input1").length;
  
  – Jacob Nelson
  Jun 19 '14 at 9:44
  
  

  
  
  
  

add a comment
 | 

22

You can use either length property and length is better perfomance then size.

$('#input1 option').length;

OR you can use size function like

$('#input1 option').size(); 

Demo

share|improve this answer

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  This doesn't provide anything the answers from 2009 didn't also provide.
  
  – TylerH
  Mar 28 at 16:38
  

  
  
  
  

add a comment
 | 

18

Your question is a little confusing, but assuming you want to display the number of options in a panel:

<div id="preview"></div>

and

$(function() 
 $("#preview").text($("#input1 option").length + " items");
);

Not sure I understand the rest of your question.

share|improve this answer

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

add a comment
 | 

13

In a multi-select option box, you can use $('#input1 :selected').length; to get the number of selected options. This can be useful to disable buttons if a certain minimum number of options aren't met.

function refreshButtons () 
 if ($('#input :selected').length == 0)
 
 $('#submit').attr ('disabled', 'disabled');
 
 else
 
 $('#submit').removeAttr ('disabled');
 

share|improve this answer

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found this to work after removing the braces $('#input1 :selected').length; supporting documentation api.jquery.com/length
  
  – Leonard Kakande
  Mar 1 '16 at 6:03
  
  

  
  
  
  

add a comment
 | 

6

Ok, i had a few problems because i was inside a

$('.my-dropdown').live('click', function() 
);

I had multiples inside my page that's why i used a class.

My drop down was filled automatically by a ajax request when i clicked it, so i only had the element $(this)

so...

I had to do:

$('.my-dropdown').live('click', function()
 total_tems = $(this).find('option').length;
);

share|improve this answer

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

add a comment
 | 

5

The best form is this

$('#example option').length

share|improve this answer

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This code-only (low-value) solution was provided 4 years earlier by Sadikhasan. The use of length was posted by Karim79 9 years earlier. This answer can safely be purged from the page as it is completely redundant.
  
  – mickmackusa
  Jun 24 at 7:39
  

  
  
  
  

add a comment
 | 

-1

Another approach that can be useful.

$('#select-id').find('option').length

share|improve this answer

edited Aug 24 at 9:14

answered Mar 15 '18 at 0:38

zakzak

30211 silver badge55 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The question isn’t asking for the count of only selected <option>s.
  
  – Sebastian Simon
  Aug 17 at 13:00
  

  
  
  
  

add a comment
 | 

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245

$('#input1 option').length;

This will produce 2.

share|improve this answer

edited Aug 17 at 12:56

Sebastian Simon

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answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

6,10488 gold badges5252 silver badges7373 bronze badges

add a comment
 | 

245

$('#input1 option').length;

This will produce 2.

share|improve this answer

edited Aug 17 at 12:56

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

6,10488 gold badges5252 silver badges7373 bronze badges

add a comment
 | 

$('#input1 option').length;

This will produce 2.

share|improve this answer

edited Aug 17 at 12:56

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

6,10488 gold badges5252 silver badges7373 bronze badges

$('#input1 option').length;

share|improve this answer

edited Aug 17 at 12:56

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

6,10488 gold badges5252 silver badges7373 bronze badges

edited Aug 17 at 12:56

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

edited Aug 17 at 12:56

Sebastian Simon

11.3k66 gold badges3333 silver badges5454 bronze badges

answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

6,10488 gold badges5252 silver badges7373 bronze badges

answered Jul 20 '09 at 10:38

nightingale2k1nightingale2k1

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50

The W3C solution:

var len = document.getElementById("input1").length;

share|improve this answer

answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  A variation to this method with modern javascript will be var len = document.querySelector("#input1").length;
  
  – Jacob Nelson
  Jun 19 '14 at 9:44
  
  

  
  
  
  

add a comment
 | 

50

The W3C solution:

var len = document.getElementById("input1").length;

share|improve this answer

answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  A variation to this method with modern javascript will be var len = document.querySelector("#input1").length;
  
  – Jacob Nelson
  Jun 19 '14 at 9:44
  
  

  
  
  
  

add a comment
 | 

The W3C solution:

var len = document.getElementById("input1").length;

share|improve this answer

answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

var len = document.getElementById("input1").length;

share|improve this answer

answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

answered Jul 20 '09 at 10:17

karim79karim79

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answered Jul 20 '09 at 10:17

karim79karim79

306k5858 gold badges390390 silver badges392392 bronze badges

22

You can use either length property and length is better perfomance then size.

$('#input1 option').length;

OR you can use size function like

$('#input1 option').size(); 

Demo

share|improve this answer

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  This doesn't provide anything the answers from 2009 didn't also provide.
  
  – TylerH
  Mar 28 at 16:38
  

  
  
  
  

add a comment
 | 

22

You can use either length property and length is better perfomance then size.

$('#input1 option').length;

OR you can use size function like

$('#input1 option').size(); 

Demo

share|improve this answer

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  This doesn't provide anything the answers from 2009 didn't also provide.
  
  – TylerH
  Mar 28 at 16:38
  

  
  
  
  

add a comment
 | 

You can use either length property and length is better perfomance then size.

$('#input1 option').length;

OR you can use size function like

$('#input1 option').size(); 

Demo

share|improve this answer

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

$('#input1 option').length;

$('#input1 option').size(); 

share|improve this answer

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

answered Oct 28 '14 at 5:58

SadikhasanSadikhasan

14.4k1414 gold badges6565 silver badges9696 bronze badges

18

Your question is a little confusing, but assuming you want to display the number of options in a panel:

<div id="preview"></div>

and

$(function() 
 $("#preview").text($("#input1 option").length + " items");
);

Not sure I understand the rest of your question.

share|improve this answer

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

add a comment
 | 

18

Your question is a little confusing, but assuming you want to display the number of options in a panel:

<div id="preview"></div>

and

$(function() 
 $("#preview").text($("#input1 option").length + " items");
);

Not sure I understand the rest of your question.

share|improve this answer

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

add a comment
 | 

Your question is a little confusing, but assuming you want to display the number of options in a panel:

<div id="preview"></div>

and

$(function() 
 $("#preview").text($("#input1 option").length + " items");
);

Not sure I understand the rest of your question.

share|improve this answer

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

<div id="preview"></div>

$(function() 
 $("#preview").text($("#input1 option").length + " items");
);

share|improve this answer

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

answered Jul 20 '09 at 10:12

cletuscletus

526k142142 gold badges855855 silver badges917917 bronze badges

13

In a multi-select option box, you can use $('#input1 :selected').length; to get the number of selected options. This can be useful to disable buttons if a certain minimum number of options aren't met.

function refreshButtons () 
 if ($('#input :selected').length == 0)
 
 $('#submit').attr ('disabled', 'disabled');
 
 else
 
 $('#submit').removeAttr ('disabled');
 

share|improve this answer

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found this to work after removing the braces $('#input1 :selected').length; supporting documentation api.jquery.com/length
  
  – Leonard Kakande
  Mar 1 '16 at 6:03
  
  

  
  
  
  

add a comment
 | 

13

In a multi-select option box, you can use $('#input1 :selected').length; to get the number of selected options. This can be useful to disable buttons if a certain minimum number of options aren't met.

function refreshButtons () 
 if ($('#input :selected').length == 0)
 
 $('#submit').attr ('disabled', 'disabled');
 
 else
 
 $('#submit').removeAttr ('disabled');
 

share|improve this answer

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found this to work after removing the braces $('#input1 :selected').length; supporting documentation api.jquery.com/length
  
  – Leonard Kakande
  Mar 1 '16 at 6:03
  
  

  
  
  
  

add a comment
 | 

In a multi-select option box, you can use $('#input1 :selected').length; to get the number of selected options. This can be useful to disable buttons if a certain minimum number of options aren't met.

function refreshButtons () 
 if ($('#input :selected').length == 0)
 
 $('#submit').attr ('disabled', 'disabled');
 
 else
 
 $('#submit').removeAttr ('disabled');
 

share|improve this answer

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

function refreshButtons () 
 if ($('#input :selected').length == 0)
 
 $('#submit').attr ('disabled', 'disabled');
 
 else
 
 $('#submit').removeAttr ('disabled');
 

share|improve this answer

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

edited Mar 2 '16 at 10:02

Community♦

111 silver badge

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

answered Apr 10 '12 at 7:43

PhilipPhilip

2,56933 gold badges1919 silver badges3131 bronze badges

6

Ok, i had a few problems because i was inside a

$('.my-dropdown').live('click', function() 
);

I had multiples inside my page that's why i used a class.

My drop down was filled automatically by a ajax request when i clicked it, so i only had the element $(this)

so...

I had to do:

$('.my-dropdown').live('click', function()
 total_tems = $(this).find('option').length;
);

share|improve this answer

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

add a comment
 | 

6

Ok, i had a few problems because i was inside a

$('.my-dropdown').live('click', function() 
);

I had multiples inside my page that's why i used a class.

My drop down was filled automatically by a ajax request when i clicked it, so i only had the element $(this)

so...

I had to do:

$('.my-dropdown').live('click', function()
 total_tems = $(this).find('option').length;
);

share|improve this answer

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

add a comment
 | 

Ok, i had a few problems because i was inside a

$('.my-dropdown').live('click', function() 
);

I had multiples inside my page that's why i used a class.

My drop down was filled automatically by a ajax request when i clicked it, so i only had the element $(this)

so...

I had to do:

$('.my-dropdown').live('click', function()
 total_tems = $(this).find('option').length;
);

share|improve this answer

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

$('.my-dropdown').live('click', function() 
);

$('.my-dropdown').live('click', function()
 total_tems = $(this).find('option').length;
);

share|improve this answer

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

answered Feb 14 '12 at 10:49

workdreamerworkdreamer

2,47011 gold badge3030 silver badges3535 bronze badges

5

The best form is this

$('#example option').length

share|improve this answer

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This code-only (low-value) solution was provided 4 years earlier by Sadikhasan. The use of length was posted by Karim79 9 years earlier. This answer can safely be purged from the page as it is completely redundant.
  
  – mickmackusa
  Jun 24 at 7:39
  

  
  
  
  

add a comment
 | 

5

The best form is this

$('#example option').length

share|improve this answer

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This code-only (low-value) solution was provided 4 years earlier by Sadikhasan. The use of length was posted by Karim79 9 years earlier. This answer can safely be purged from the page as it is completely redundant.
  
  – mickmackusa
  Jun 24 at 7:39
  

  
  
  
  

add a comment
 | 

The best form is this

$('#example option').length

share|improve this answer

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

$('#example option').length

share|improve this answer

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

answered Feb 19 '18 at 15:23

Ricardo López GarcíaRicardo López García

5811 silver badge55 bronze badges

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