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Create a separate log file for each iteration in a for loop
Logging data on device and retrieving the logtrim big log fileWhy not use java.util.logging?twistd.py log to both stdout and fileSeparate logs for each process using multiprocessing?fopen and fprintf in C not working as intended?save and sprintf in loop not printingSave docker-compose logs to a fileMatlab's diary + job schedulerhow to run multiple text file in matlab and get separate output file?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I just want to make a script which runs multiple files and stores their outputs in separate log files.
So I wrote the code by using diary
to generate the output, but the diary
function is only 1 log file and the output is updating in the same log file for remaining iterations. In my testconfig_1
file, I have at present only print as the content.
Then I tried to use the fopen
method, with this I am getting multiple log files but I don't understand how I can put that data into the log file which I have created through fopen
after each run.
% with diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n' , x);
test = [instring num2str(x)];
run(test);
diary testconfig_(x).log;
end
% without diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n', x);
test = [instring num2str(x)];
run(test);
fid = fopen(sprintf('testconfig_%d.log',x),'w');
end
I wanted to get testconfig_1.log
, testconfig_2.log
, testconfig_3.log
and I wanted to print in_testconfig_1
, in_testconfig_2
, in_testconfig_3
respectively
matlab logging fopen
add a comment |
I just want to make a script which runs multiple files and stores their outputs in separate log files.
So I wrote the code by using diary
to generate the output, but the diary
function is only 1 log file and the output is updating in the same log file for remaining iterations. In my testconfig_1
file, I have at present only print as the content.
Then I tried to use the fopen
method, with this I am getting multiple log files but I don't understand how I can put that data into the log file which I have created through fopen
after each run.
% with diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n' , x);
test = [instring num2str(x)];
run(test);
diary testconfig_(x).log;
end
% without diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n', x);
test = [instring num2str(x)];
run(test);
fid = fopen(sprintf('testconfig_%d.log',x),'w');
end
I wanted to get testconfig_1.log
, testconfig_2.log
, testconfig_3.log
and I wanted to print in_testconfig_1
, in_testconfig_2
, in_testconfig_3
respectively
matlab logging fopen
Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
2
That makes sense from looking at the docs. Trydiary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25
add a comment |
I just want to make a script which runs multiple files and stores their outputs in separate log files.
So I wrote the code by using diary
to generate the output, but the diary
function is only 1 log file and the output is updating in the same log file for remaining iterations. In my testconfig_1
file, I have at present only print as the content.
Then I tried to use the fopen
method, with this I am getting multiple log files but I don't understand how I can put that data into the log file which I have created through fopen
after each run.
% with diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n' , x);
test = [instring num2str(x)];
run(test);
diary testconfig_(x).log;
end
% without diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n', x);
test = [instring num2str(x)];
run(test);
fid = fopen(sprintf('testconfig_%d.log',x),'w');
end
I wanted to get testconfig_1.log
, testconfig_2.log
, testconfig_3.log
and I wanted to print in_testconfig_1
, in_testconfig_2
, in_testconfig_3
respectively
matlab logging fopen
I just want to make a script which runs multiple files and stores their outputs in separate log files.
So I wrote the code by using diary
to generate the output, but the diary
function is only 1 log file and the output is updating in the same log file for remaining iterations. In my testconfig_1
file, I have at present only print as the content.
Then I tried to use the fopen
method, with this I am getting multiple log files but I don't understand how I can put that data into the log file which I have created through fopen
after each run.
% with diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n' , x);
test = [instring num2str(x)];
run(test);
diary testconfig_(x).log;
end
% without diary method
clear all;
diary on;
instring ='testconfig_';
for x = 1:3
fprintf ('Simulation on testconfig_%d n', x);
test = [instring num2str(x)];
run(test);
fid = fopen(sprintf('testconfig_%d.log',x),'w');
end
I wanted to get testconfig_1.log
, testconfig_2.log
, testconfig_3.log
and I wanted to print in_testconfig_1
, in_testconfig_2
, in_testconfig_3
respectively
matlab logging fopen
matlab logging fopen
edited Mar 28 at 10:23
Wolfie
18.2k7 gold badges18 silver badges46 bronze badges
18.2k7 gold badges18 silver badges46 bronze badges
asked Mar 28 at 7:23
fuwadfuwad
184 bronze badges
184 bronze badges
Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
2
That makes sense from looking at the docs. Trydiary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25
add a comment |
Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
2
That makes sense from looking at the docs. Trydiary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25
Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
2
2
That makes sense from looking at the docs. Try
diary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
That makes sense from looking at the docs. Try
diary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25
add a comment |
1 Answer
1
active
oldest
votes
You are using command syntax to call the diary
function.
% Command syntax
diary filename.log
% Equivalent function syntax
diary( 'filename.log' );
Notice that, when using command syntax, all arguments are treated as strings, despite not having any quote marks!
So when you do diary testconfig_(x).log
, the equivalent is
diary( 'diary testconfig_(x).log' );
All of your logs have the same filename, because x
is never evaluated as the loop variable, it's always just part of a string!
You are trying to create the strings with the loop variable in the name, for this you cannot use command syntax.
Instead, use function syntax like this:
filename = sprintf( 'diary testconfig_%d.log', x );
diary( filename ); % treat the filename variable as a variable, not a string
You don't have to declare the intermediate filename
variable, and there are other ways to create the filename
string, but I hope this demonstrates the issue.
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggesteddiary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create thefilename
string. If this helps answer your question, please consider marking it as accepted.
– Wolfie
Mar 28 at 11:01
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are using command syntax to call the diary
function.
% Command syntax
diary filename.log
% Equivalent function syntax
diary( 'filename.log' );
Notice that, when using command syntax, all arguments are treated as strings, despite not having any quote marks!
So when you do diary testconfig_(x).log
, the equivalent is
diary( 'diary testconfig_(x).log' );
All of your logs have the same filename, because x
is never evaluated as the loop variable, it's always just part of a string!
You are trying to create the strings with the loop variable in the name, for this you cannot use command syntax.
Instead, use function syntax like this:
filename = sprintf( 'diary testconfig_%d.log', x );
diary( filename ); % treat the filename variable as a variable, not a string
You don't have to declare the intermediate filename
variable, and there are other ways to create the filename
string, but I hope this demonstrates the issue.
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggesteddiary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create thefilename
string. If this helps answer your question, please consider marking it as accepted.
– Wolfie
Mar 28 at 11:01
add a comment |
You are using command syntax to call the diary
function.
% Command syntax
diary filename.log
% Equivalent function syntax
diary( 'filename.log' );
Notice that, when using command syntax, all arguments are treated as strings, despite not having any quote marks!
So when you do diary testconfig_(x).log
, the equivalent is
diary( 'diary testconfig_(x).log' );
All of your logs have the same filename, because x
is never evaluated as the loop variable, it's always just part of a string!
You are trying to create the strings with the loop variable in the name, for this you cannot use command syntax.
Instead, use function syntax like this:
filename = sprintf( 'diary testconfig_%d.log', x );
diary( filename ); % treat the filename variable as a variable, not a string
You don't have to declare the intermediate filename
variable, and there are other ways to create the filename
string, but I hope this demonstrates the issue.
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggesteddiary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create thefilename
string. If this helps answer your question, please consider marking it as accepted.
– Wolfie
Mar 28 at 11:01
add a comment |
You are using command syntax to call the diary
function.
% Command syntax
diary filename.log
% Equivalent function syntax
diary( 'filename.log' );
Notice that, when using command syntax, all arguments are treated as strings, despite not having any quote marks!
So when you do diary testconfig_(x).log
, the equivalent is
diary( 'diary testconfig_(x).log' );
All of your logs have the same filename, because x
is never evaluated as the loop variable, it's always just part of a string!
You are trying to create the strings with the loop variable in the name, for this you cannot use command syntax.
Instead, use function syntax like this:
filename = sprintf( 'diary testconfig_%d.log', x );
diary( filename ); % treat the filename variable as a variable, not a string
You don't have to declare the intermediate filename
variable, and there are other ways to create the filename
string, but I hope this demonstrates the issue.
You are using command syntax to call the diary
function.
% Command syntax
diary filename.log
% Equivalent function syntax
diary( 'filename.log' );
Notice that, when using command syntax, all arguments are treated as strings, despite not having any quote marks!
So when you do diary testconfig_(x).log
, the equivalent is
diary( 'diary testconfig_(x).log' );
All of your logs have the same filename, because x
is never evaluated as the loop variable, it's always just part of a string!
You are trying to create the strings with the loop variable in the name, for this you cannot use command syntax.
Instead, use function syntax like this:
filename = sprintf( 'diary testconfig_%d.log', x );
diary( filename ); % treat the filename variable as a variable, not a string
You don't have to declare the intermediate filename
variable, and there are other ways to create the filename
string, but I hope this demonstrates the issue.
answered Mar 28 at 10:29
WolfieWolfie
18.2k7 gold badges18 silver badges46 bronze badges
18.2k7 gold badges18 silver badges46 bronze badges
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggesteddiary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create thefilename
string. If this helps answer your question, please consider marking it as accepted.
– Wolfie
Mar 28 at 11:01
add a comment |
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggesteddiary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create thefilename
string. If this helps answer your question, please consider marking it as accepted.
– Wolfie
Mar 28 at 11:01
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
in for loop if we add diary (['testconfig_' num2str(x) '.log']) then also it is generating that many number of log file and also copying the contents of the output
– fuwad
Mar 28 at 10:42
Yes,
diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggested diary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create the filename
string. If this helps answer your question, please consider marking it as accepted.– Wolfie
Mar 28 at 11:01
Yes,
diary(['testconfig_' num2str(x) '.log'])
is exactly the same as my suggested diary( sprintf( 'diary testconfig_%d.log', x ) )
. As I said in the answer, there are other ways to create the filename
string. If this helps answer your question, please consider marking it as accepted.– Wolfie
Mar 28 at 11:01
add a comment |
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Have a look at the Write data to text file example from the help. Let us know, when you encounter further problems.
– HansHirse
Mar 28 at 7:30
What's the name of the one file the diary creates?
– UnbearableLightness
Mar 28 at 9:29
it is creating testconfig_(x).log
– fuwad
Mar 28 at 9:35
2
That makes sense from looking at the docs. Try
diary (['testconfig_' num2str(x) '.log'])
– UnbearableLightness
Mar 28 at 10:12
the above inputs is working thanks for your necessary time
– fuwad
Mar 28 at 10:25