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Use dictionary value to parse a string in python


How do I merge two dictionaries in a single expression?Calling an external command from PythonWhat are metaclasses in Python?How do I parse a string to a float or int?Does Python have a ternary conditional operator?How do I sort a dictionary by value?Add new keys to a dictionary?Check if a given key already exists in a dictionaryIterating over dictionaries using 'for' loopsDoes Python have a string 'contains' substring method?






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I'm trying to parse a string at a specified position which is pulled from a dictionary. I've only been working with python for a couple months and I can't figure out how to pull in the value correctly.



I've tried finding answers within posts about dictionaries, but I'm not seeing this specific question.



#pull in mods, excel file, and sheets needed

sourceIdDict=

for x in range(10):
source=str(insheet2.cell(x,0))
numBgn=insheet2.cell(x,4)
sourceIdDict[source]=numBgn

for count in range(500):
crs=str(insheet1.cell(count,0))
src=str(insheet1.cell(count,1))
yrtr=str(insheet1.cell(count,2))
tseg=str(insheet1.cell(count,3))
uSeg=str(insheet1.cell(count,4))
level=crs[sourceIdDict.get(src)]

#if condition met: write to output file

#close file


The last line seems to be the problem. I keep getting TypeError: string indices must be integers. I don't know why it isn't reading it as an integer, even when I use crsBgn=int(insheet2.cell(x,4)). source is the same info as src.



The other variables are string because they could have leading zeros, which I don't want dropped when it's written into excel.










share|improve this question




























  • Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

    – feliks
    Mar 28 at 22:03











  • You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

    – geckos
    Mar 28 at 22:06











  • You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

    – geckos
    Mar 28 at 22:08











  • @feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

    – anythingButThat
    Mar 29 at 18:25











  • @geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

    – anythingButThat
    Mar 29 at 18:28

















0

















I'm trying to parse a string at a specified position which is pulled from a dictionary. I've only been working with python for a couple months and I can't figure out how to pull in the value correctly.



I've tried finding answers within posts about dictionaries, but I'm not seeing this specific question.



#pull in mods, excel file, and sheets needed

sourceIdDict=

for x in range(10):
source=str(insheet2.cell(x,0))
numBgn=insheet2.cell(x,4)
sourceIdDict[source]=numBgn

for count in range(500):
crs=str(insheet1.cell(count,0))
src=str(insheet1.cell(count,1))
yrtr=str(insheet1.cell(count,2))
tseg=str(insheet1.cell(count,3))
uSeg=str(insheet1.cell(count,4))
level=crs[sourceIdDict.get(src)]

#if condition met: write to output file

#close file


The last line seems to be the problem. I keep getting TypeError: string indices must be integers. I don't know why it isn't reading it as an integer, even when I use crsBgn=int(insheet2.cell(x,4)). source is the same info as src.



The other variables are string because they could have leading zeros, which I don't want dropped when it's written into excel.










share|improve this question




























  • Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

    – feliks
    Mar 28 at 22:03











  • You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

    – geckos
    Mar 28 at 22:06











  • You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

    – geckos
    Mar 28 at 22:08











  • @feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

    – anythingButThat
    Mar 29 at 18:25











  • @geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

    – anythingButThat
    Mar 29 at 18:28













0












0








0








I'm trying to parse a string at a specified position which is pulled from a dictionary. I've only been working with python for a couple months and I can't figure out how to pull in the value correctly.



I've tried finding answers within posts about dictionaries, but I'm not seeing this specific question.



#pull in mods, excel file, and sheets needed

sourceIdDict=

for x in range(10):
source=str(insheet2.cell(x,0))
numBgn=insheet2.cell(x,4)
sourceIdDict[source]=numBgn

for count in range(500):
crs=str(insheet1.cell(count,0))
src=str(insheet1.cell(count,1))
yrtr=str(insheet1.cell(count,2))
tseg=str(insheet1.cell(count,3))
uSeg=str(insheet1.cell(count,4))
level=crs[sourceIdDict.get(src)]

#if condition met: write to output file

#close file


The last line seems to be the problem. I keep getting TypeError: string indices must be integers. I don't know why it isn't reading it as an integer, even when I use crsBgn=int(insheet2.cell(x,4)). source is the same info as src.



The other variables are string because they could have leading zeros, which I don't want dropped when it's written into excel.










share|improve this question

















I'm trying to parse a string at a specified position which is pulled from a dictionary. I've only been working with python for a couple months and I can't figure out how to pull in the value correctly.



I've tried finding answers within posts about dictionaries, but I'm not seeing this specific question.



#pull in mods, excel file, and sheets needed

sourceIdDict=

for x in range(10):
source=str(insheet2.cell(x,0))
numBgn=insheet2.cell(x,4)
sourceIdDict[source]=numBgn

for count in range(500):
crs=str(insheet1.cell(count,0))
src=str(insheet1.cell(count,1))
yrtr=str(insheet1.cell(count,2))
tseg=str(insheet1.cell(count,3))
uSeg=str(insheet1.cell(count,4))
level=crs[sourceIdDict.get(src)]

#if condition met: write to output file

#close file


The last line seems to be the problem. I keep getting TypeError: string indices must be integers. I don't know why it isn't reading it as an integer, even when I use crsBgn=int(insheet2.cell(x,4)). source is the same info as src.



The other variables are string because they could have leading zeros, which I don't want dropped when it's written into excel.







python parsing dictionary






share|improve this question
















share|improve this question













share|improve this question




share|improve this question








edited Mar 28 at 22:37









Aman Ojha

32 bronze badges




32 bronze badges










asked Mar 28 at 21:59









anythingButThatanythingButThat

11 bronze badge




11 bronze badge















  • Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

    – feliks
    Mar 28 at 22:03











  • You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

    – geckos
    Mar 28 at 22:06











  • You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

    – geckos
    Mar 28 at 22:08











  • @feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

    – anythingButThat
    Mar 29 at 18:25











  • @geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

    – anythingButThat
    Mar 29 at 18:28

















  • Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

    – feliks
    Mar 28 at 22:03











  • You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

    – geckos
    Mar 28 at 22:06











  • You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

    – geckos
    Mar 28 at 22:08











  • @feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

    – anythingButThat
    Mar 29 at 18:25











  • @geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

    – anythingButThat
    Mar 29 at 18:28
















Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

– feliks
Mar 28 at 22:03





Does type casting work? I.e. converting sourceIdDict.get(src) to int(sourceIdDict.get(src))?

– feliks
Mar 28 at 22:03













You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

– geckos
Mar 28 at 22:06





You may be getting a non-integer from the dict or a None if the key isn't present, it depends on the input. I think you should replace the last line of first for by sourceIdDict[source]=int(numBgn)

– geckos
Mar 28 at 22:06













You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

– geckos
Mar 28 at 22:08





You may get TypeErrors if numBgn can't be parsed, surround it by try/catch and handle it accordingly

– geckos
Mar 28 at 22:08













@feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

– anythingButThat
Mar 29 at 18:25





@feliks No, then the error changes to TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

– anythingButThat
Mar 29 at 18:25













@geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

– anythingButThat
Mar 29 at 18:28





@geckos That gives TypeError: int() argument must be a string, a bytes-like object or a number, not 'Cell'

– anythingButThat
Mar 29 at 18:28












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