Coded UI for WinForms - find main window programmaticallyUnit Tests in Visual Studio 2010Running Coded UI tests with Resharper/NUnit will not locate Silverlight componentsNot able to recognize MSAA controlsVS2013 coded ui test fails at playback when trying to click on sub menu itemsCodedUI exception: UITestControlNotFoundException: Addional Details: TechnologyName: 'MSAA' ControlType: 'MenuItem' Name: 'All'Why isn't the Mouse.DoubleClick functioning properly when the Coded UI test is executed via MTM?Coded UI test click throws hidden control exception in windows 10 but works on windows 7coded user interface test not same behavior on different PCFinding TextBox inside of UserControlCoded UI is identifying the control but not performing any action
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Coded UI for WinForms - find main window programmatically
Unit Tests in Visual Studio 2010Running Coded UI tests with Resharper/NUnit will not locate Silverlight componentsNot able to recognize MSAA controlsVS2013 coded ui test fails at playback when trying to click on sub menu itemsCodedUI exception: UITestControlNotFoundException: Addional Details: TechnologyName: 'MSAA' ControlType: 'MenuItem' Name: 'All'Why isn't the Mouse.DoubleClick functioning properly when the Coded UI test is executed via MTM?Coded UI test click throws hidden control exception in windows 10 but works on windows 7coded user interface test not same behavior on different PCFinding TextBox inside of UserControlCoded UI is identifying the control but not performing any action
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I am working on a coded ui project for a win forms application. I would like to get the main window of the application under test programmatically.
What I tried is:
WinWindow mainWindow = new WinWindow();
mainWindow.TechnologyName = "MSAA";
main.Window.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.Name, "Soft under test", PropertyExpressionOperator.Contains));
mainWindow.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.ClassName, "WindowsForms10.Window", PropertyExpressionOperator.Contains));
mainWindow.SearchConfigurations.Remove(SearchConfiguration.VisibleOnly);
mainWindow.SearchConfigurations.Add(SearchConfiguration.AlwaysSearch);
This fails with:
The playback failed to find the control with the given search properties. Additional Details:
TechnologyName: 'MSAA'
Name: 'Soft under test'
ClassName: 'WindowsForms10.Window'
---> System.Runtime.InteropServices.COMException: Error HRESULT E_FAIL has been returned from a call to a COM component.
What is the correct way to get the window?
winforms coded-ui-tests
asked Mar 24 at 12:22
CristisSCristisS
7241622
add a comment |
I am working on a coded ui project for a win forms application. I would like to get the main window of the application under test programmatically.
What I tried is:
WinWindow mainWindow = new WinWindow();
mainWindow.TechnologyName = "MSAA";
main.Window.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.Name, "Soft under test", PropertyExpressionOperator.Contains));
mainWindow.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.ClassName, "WindowsForms10.Window", PropertyExpressionOperator.Contains));
mainWindow.SearchConfigurations.Remove(SearchConfiguration.VisibleOnly);
mainWindow.SearchConfigurations.Add(SearchConfiguration.AlwaysSearch);
This fails with:
The playback failed to find the control with the given search properties. Additional Details:
TechnologyName: 'MSAA'
Name: 'Soft under test'
ClassName: 'WindowsForms10.Window'
---> System.Runtime.InteropServices.COMException: Error HRESULT E_FAIL has been returned from a call to a COM component.
What is the correct way to get the window?
winforms coded-ui-tests
asked Mar 24 at 12:22
CristisSCristisS
7241622
1
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12
add a comment |
I am working on a coded ui project for a win forms application. I would like to get the main window of the application under test programmatically.
What I tried is:
WinWindow mainWindow = new WinWindow();
mainWindow.TechnologyName = "MSAA";
main.Window.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.Name, "Soft under test", PropertyExpressionOperator.Contains));
mainWindow.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.ClassName, "WindowsForms10.Window", PropertyExpressionOperator.Contains));
mainWindow.SearchConfigurations.Remove(SearchConfiguration.VisibleOnly);
mainWindow.SearchConfigurations.Add(SearchConfiguration.AlwaysSearch);
This fails with:
The playback failed to find the control with the given search properties. Additional Details:
TechnologyName: 'MSAA'
Name: 'Soft under test'
ClassName: 'WindowsForms10.Window'
---> System.Runtime.InteropServices.COMException: Error HRESULT E_FAIL has been returned from a call to a COM component.
What is the correct way to get the window?
winforms coded-ui-tests
asked Mar 24 at 12:22
CristisSCristisS
7241622
I am working on a coded ui project for a win forms application. I would like to get the main window of the application under test programmatically.
What I tried is:
WinWindow mainWindow = new WinWindow();
mainWindow.TechnologyName = "MSAA";
main.Window.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.Name, "Soft under test", PropertyExpressionOperator.Contains));
mainWindow.SearchProperties.Add(new PropertyExpression(WinWindow.PropertyNames.ClassName, "WindowsForms10.Window", PropertyExpressionOperator.Contains));
mainWindow.SearchConfigurations.Remove(SearchConfiguration.VisibleOnly);
mainWindow.SearchConfigurations.Add(SearchConfiguration.AlwaysSearch);
This fails with:
The playback failed to find the control with the given search properties. Additional Details:
TechnologyName: 'MSAA'
Name: 'Soft under test'
ClassName: 'WindowsForms10.Window'
---> System.Runtime.InteropServices.COMException: Error HRESULT E_FAIL has been returned from a call to a COM component.
What is the correct way to get the window?
winforms coded-ui-tests
winforms coded-ui-tests
asked Mar 24 at 12:22
CristisSCristisS
7241622
asked Mar 24 at 12:22
CristisSCristisS
7241622
asked Mar 24 at 12:22
CristisSCristisS
7241622
asked Mar 24 at 12:22
CristisSCristisS
7241622
asked Mar 24 at 12:22
CristisSCristisS
7241622
7241622
1
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12
add a comment |
1
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12
1
1
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12
add a comment |
1 Answer
1
active
oldest
votes
Not sure if this question is still relevant, but here is the code I use to get the window:
this.TechnologyName = "MSAA";
this.SearchProperties.Add(UITestControl.PropertyNames.Name, "MyProgram");
this.SearchProperties.Add(UITestControl.PropertyNames.ControlType, "Window");
this.SearchProperties.Add("ControlName", "TopScreen");
this.SearchConfigurations.Add(SearchConfiguration.ExpandWhileSearching);
Perhaps, you need ExpandWhileSearching property for it to find the screen.
answered May 24 at 13:57
Ivan BIvan B
438
add a comment |
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oldest
votes
Not sure if this question is still relevant, but here is the code I use to get the window:
this.TechnologyName = "MSAA";
this.SearchProperties.Add(UITestControl.PropertyNames.Name, "MyProgram");
this.SearchProperties.Add(UITestControl.PropertyNames.ControlType, "Window");
this.SearchProperties.Add("ControlName", "TopScreen");
this.SearchConfigurations.Add(SearchConfiguration.ExpandWhileSearching);
Perhaps, you need ExpandWhileSearching property for it to find the screen.
answered May 24 at 13:57
Ivan BIvan B
438
add a comment |
Not sure if this question is still relevant, but here is the code I use to get the window:
this.TechnologyName = "MSAA";
this.SearchProperties.Add(UITestControl.PropertyNames.Name, "MyProgram");
this.SearchProperties.Add(UITestControl.PropertyNames.ControlType, "Window");
this.SearchProperties.Add("ControlName", "TopScreen");
this.SearchConfigurations.Add(SearchConfiguration.ExpandWhileSearching);
Perhaps, you need ExpandWhileSearching property for it to find the screen.
answered May 24 at 13:57
Ivan BIvan B
438
add a comment |
Not sure if this question is still relevant, but here is the code I use to get the window:
this.TechnologyName = "MSAA";
this.SearchProperties.Add(UITestControl.PropertyNames.Name, "MyProgram");
this.SearchProperties.Add(UITestControl.PropertyNames.ControlType, "Window");
this.SearchProperties.Add("ControlName", "TopScreen");
this.SearchConfigurations.Add(SearchConfiguration.ExpandWhileSearching);
Perhaps, you need ExpandWhileSearching property for it to find the screen.
answered May 24 at 13:57
Ivan BIvan B
438
Not sure if this question is still relevant, but here is the code I use to get the window:
this.TechnologyName = "MSAA";
this.SearchProperties.Add(UITestControl.PropertyNames.Name, "MyProgram");
this.SearchProperties.Add(UITestControl.PropertyNames.ControlType, "Window");
this.SearchProperties.Add("ControlName", "TopScreen");
this.SearchConfigurations.Add(SearchConfiguration.ExpandWhileSearching);
Perhaps, you need ExpandWhileSearching property for it to find the screen.
answered May 24 at 13:57
Ivan BIvan B
438
answered May 24 at 13:57
Ivan BIvan B
438
answered May 24 at 13:57
Ivan BIvan B
438
answered May 24 at 13:57
Ivan BIvan B
438
438
add a comment |
add a comment |
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1
Let the Coded UI record and generate tool show you. Make a recording, possibly into a sandbox project, and then copy the useful bits.
– AdrianHHH
Mar 24 at 14:35
Also, performance wise, try using the least amount of search properties to find the control you are looking for. The coded ui test recorder lets you do that.
– PixelPlex
Mar 25 at 8:12