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how to bind multiple audio file as one file in python?


How to join two wav files using python?How do I check whether a file exists without exceptions?Calling an external command in PythonWhat are metaclasses in Python?How do I copy a file in Python?How can I safely create a nested directory?Does Python have a ternary conditional operator?How to get the current time in PythonHow can I make a time delay in Python?How do I list all files of a directory?Does Python have a string 'contains' substring method?






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0















In my system i have to list all the wav files from one folder and then i have to bind that files as one file. I have the code to bind two files but i have 8 or more sound file i have to bind those file. Anybody can you help me? Stackoverflow solution have merge only two audio file. I have to merge lot of audio file from the folder. I don't know how many audio file will come into that folder.



this code is bind two files:



 print(glob.glob('upload/updated_audios/*.wav'))
file_data = glob.glob('upload/convertedAudio/*.wav')
outfile = "upload/output_files/output.wav"

data = []
for infile in file_data:
w = wave.open(infile, 'rb')
data.append([w.getparams(), w.readframes(w.getnframes())])
w.close()

output = wave.open(outfile, 'wb')
output.setparams(data[0][0])
output.writeframes(data[0][1])
output.writeframes(data[1][1])
output.close()









share|improve this question
























  • how about this

    – Nullman
    Mar 24 at 12:24











  • this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

    – Majutharan Majutharan
    Mar 24 at 12:27











  • Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

    – JohanL
    Mar 24 at 12:29











  • @MajutharanMajutharan Some of the answers there could work for any number of files.

    – connectyourcharger
    Mar 24 at 12:29












  • @connectyourcharger I'm using django framework so i put that tag.

    – Majutharan Majutharan
    Mar 24 at 12:31

















0















In my system i have to list all the wav files from one folder and then i have to bind that files as one file. I have the code to bind two files but i have 8 or more sound file i have to bind those file. Anybody can you help me? Stackoverflow solution have merge only two audio file. I have to merge lot of audio file from the folder. I don't know how many audio file will come into that folder.



this code is bind two files:



 print(glob.glob('upload/updated_audios/*.wav'))
file_data = glob.glob('upload/convertedAudio/*.wav')
outfile = "upload/output_files/output.wav"

data = []
for infile in file_data:
w = wave.open(infile, 'rb')
data.append([w.getparams(), w.readframes(w.getnframes())])
w.close()

output = wave.open(outfile, 'wb')
output.setparams(data[0][0])
output.writeframes(data[0][1])
output.writeframes(data[1][1])
output.close()









share|improve this question
























  • how about this

    – Nullman
    Mar 24 at 12:24











  • this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

    – Majutharan Majutharan
    Mar 24 at 12:27











  • Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

    – JohanL
    Mar 24 at 12:29











  • @MajutharanMajutharan Some of the answers there could work for any number of files.

    – connectyourcharger
    Mar 24 at 12:29












  • @connectyourcharger I'm using django framework so i put that tag.

    – Majutharan Majutharan
    Mar 24 at 12:31













0












0








0


1






In my system i have to list all the wav files from one folder and then i have to bind that files as one file. I have the code to bind two files but i have 8 or more sound file i have to bind those file. Anybody can you help me? Stackoverflow solution have merge only two audio file. I have to merge lot of audio file from the folder. I don't know how many audio file will come into that folder.



this code is bind two files:



 print(glob.glob('upload/updated_audios/*.wav'))
file_data = glob.glob('upload/convertedAudio/*.wav')
outfile = "upload/output_files/output.wav"

data = []
for infile in file_data:
w = wave.open(infile, 'rb')
data.append([w.getparams(), w.readframes(w.getnframes())])
w.close()

output = wave.open(outfile, 'wb')
output.setparams(data[0][0])
output.writeframes(data[0][1])
output.writeframes(data[1][1])
output.close()









share|improve this question
















In my system i have to list all the wav files from one folder and then i have to bind that files as one file. I have the code to bind two files but i have 8 or more sound file i have to bind those file. Anybody can you help me? Stackoverflow solution have merge only two audio file. I have to merge lot of audio file from the folder. I don't know how many audio file will come into that folder.



this code is bind two files:



 print(glob.glob('upload/updated_audios/*.wav'))
file_data = glob.glob('upload/convertedAudio/*.wav')
outfile = "upload/output_files/output.wav"

data = []
for infile in file_data:
w = wave.open(infile, 'rb')
data.append([w.getparams(), w.readframes(w.getnframes())])
w.close()

output = wave.open(outfile, 'wb')
output.setparams(data[0][0])
output.writeframes(data[0][1])
output.writeframes(data[1][1])
output.close()






python wav






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 24 at 12:33







Majutharan Majutharan

















asked Mar 24 at 12:22









Majutharan MajutharanMajutharan Majutharan

189112




189112












  • how about this

    – Nullman
    Mar 24 at 12:24











  • this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

    – Majutharan Majutharan
    Mar 24 at 12:27











  • Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

    – JohanL
    Mar 24 at 12:29











  • @MajutharanMajutharan Some of the answers there could work for any number of files.

    – connectyourcharger
    Mar 24 at 12:29












  • @connectyourcharger I'm using django framework so i put that tag.

    – Majutharan Majutharan
    Mar 24 at 12:31

















  • how about this

    – Nullman
    Mar 24 at 12:24











  • this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

    – Majutharan Majutharan
    Mar 24 at 12:27











  • Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

    – JohanL
    Mar 24 at 12:29











  • @MajutharanMajutharan Some of the answers there could work for any number of files.

    – connectyourcharger
    Mar 24 at 12:29












  • @connectyourcharger I'm using django framework so i put that tag.

    – Majutharan Majutharan
    Mar 24 at 12:31
















how about this

– Nullman
Mar 24 at 12:24





how about this

– Nullman
Mar 24 at 12:24













this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

– Majutharan Majutharan
Mar 24 at 12:27





this code is to merge two audio file. I have to merge lot of audio file.so can you give an idea to that?

– Majutharan Majutharan
Mar 24 at 12:27













Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

– JohanL
Mar 24 at 12:29





Merge the new file, consisting of two files, with the next file in the library. That will mean you have a file consisting of three files bound together. This new file can bind the next, and so on...

– JohanL
Mar 24 at 12:29













@MajutharanMajutharan Some of the answers there could work for any number of files.

– connectyourcharger
Mar 24 at 12:29






@MajutharanMajutharan Some of the answers there could work for any number of files.

– connectyourcharger
Mar 24 at 12:29














@connectyourcharger I'm using django framework so i put that tag.

– Majutharan Majutharan
Mar 24 at 12:31





@connectyourcharger I'm using django framework so i put that tag.

– Majutharan Majutharan
Mar 24 at 12:31












1 Answer
1






active

oldest

votes


















0














file_data = glob.glob('upload/convertedAudio/*.wav')
outfile = "upload/output_files/output.wav"

with wave.open(outfile, 'wb') as wav_out:
for wav_path in file_data:
with wave.open(wav_path, 'rb') as wav_in:
if not wav_out.getnframes():
wav_out.setparams(wav_in.getparams())
wav_out.writeframes(wav_in.readframes(wav_in.getnframes()))


this code is working but i can't merge orderly. this answer already in stackoverflow question. but that question is different so this answer is most suitable for this question.



note: order mean ascending and descending.






share|improve this answer























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    file_data = glob.glob('upload/convertedAudio/*.wav')
    outfile = "upload/output_files/output.wav"

    with wave.open(outfile, 'wb') as wav_out:
    for wav_path in file_data:
    with wave.open(wav_path, 'rb') as wav_in:
    if not wav_out.getnframes():
    wav_out.setparams(wav_in.getparams())
    wav_out.writeframes(wav_in.readframes(wav_in.getnframes()))


    this code is working but i can't merge orderly. this answer already in stackoverflow question. but that question is different so this answer is most suitable for this question.



    note: order mean ascending and descending.






    share|improve this answer



























      0














      file_data = glob.glob('upload/convertedAudio/*.wav')
      outfile = "upload/output_files/output.wav"

      with wave.open(outfile, 'wb') as wav_out:
      for wav_path in file_data:
      with wave.open(wav_path, 'rb') as wav_in:
      if not wav_out.getnframes():
      wav_out.setparams(wav_in.getparams())
      wav_out.writeframes(wav_in.readframes(wav_in.getnframes()))


      this code is working but i can't merge orderly. this answer already in stackoverflow question. but that question is different so this answer is most suitable for this question.



      note: order mean ascending and descending.






      share|improve this answer

























        0












        0








        0







        file_data = glob.glob('upload/convertedAudio/*.wav')
        outfile = "upload/output_files/output.wav"

        with wave.open(outfile, 'wb') as wav_out:
        for wav_path in file_data:
        with wave.open(wav_path, 'rb') as wav_in:
        if not wav_out.getnframes():
        wav_out.setparams(wav_in.getparams())
        wav_out.writeframes(wav_in.readframes(wav_in.getnframes()))


        this code is working but i can't merge orderly. this answer already in stackoverflow question. but that question is different so this answer is most suitable for this question.



        note: order mean ascending and descending.






        share|improve this answer













        file_data = glob.glob('upload/convertedAudio/*.wav')
        outfile = "upload/output_files/output.wav"

        with wave.open(outfile, 'wb') as wav_out:
        for wav_path in file_data:
        with wave.open(wav_path, 'rb') as wav_in:
        if not wav_out.getnframes():
        wav_out.setparams(wav_in.getparams())
        wav_out.writeframes(wav_in.readframes(wav_in.getnframes()))


        this code is working but i can't merge orderly. this answer already in stackoverflow question. but that question is different so this answer is most suitable for this question.



        note: order mean ascending and descending.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 24 at 12:47









        Majutharan MajutharanMajutharan Majutharan

        189112




        189112





























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