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plotting circular density using curve.circular
Side-by-side plots with ggplot2Plot two graphs in same plot in RShading a kernel density plot between two points.How to create a density plot in matplotlib?How to overlay density plots in R?R: Using MLE to do a CFA by handHow to compute the inverse of a close to singular matrix in R?Circular density plot using ggplot2Probability over a circular regionConducting MLE for multivariate case (bivariate normal) in R
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I need to plot the circular density defined in function (f2) in the following R code
library(circular)
mu=c(1,1.166) # true values of the mean vector of bivariate normal variables
var.1 =1.096# sigma.1.squared for first normal variable
var.2=1#sigma.2.squared of second normal variable
cov.1.2=-0.31 # covariance between the two normal variables
var.cov<-matrix(c(var.1,cov.1.2,cov.1.2,var.2),nrow=2,ncol=2,byrow=T) #variance covariance matrix of the bivariate normal random variables
f2=function(x)
u=cbind(cos(x),sin(x))
a=drop((u)%*%solve(var.cov)%*%t(u))
b=drop((u)%*%solve(var.cov)%*%(mu))
c=drop(-0.5*t(mu)%*%solve(var.cov)%*%mu)
d=drop(b/sqrt(a))
aa=(cos(x))*(1/(2*pi*a*sqrt(det(var.cov))))*exp(c)*(1+((d*pnorm(d))/dnorm(d)))
return(aa)
curve.circular(f2,from=0,to=2*pi,n=101)
the problem is that I get error messages:
Error in lines.circular(x, y, ...) : object 'll' not found
In addition: Warning message:
In sqrt(a) : NaNs produced
I do not know how to deal with that error
r
add a comment |
I need to plot the circular density defined in function (f2) in the following R code
library(circular)
mu=c(1,1.166) # true values of the mean vector of bivariate normal variables
var.1 =1.096# sigma.1.squared for first normal variable
var.2=1#sigma.2.squared of second normal variable
cov.1.2=-0.31 # covariance between the two normal variables
var.cov<-matrix(c(var.1,cov.1.2,cov.1.2,var.2),nrow=2,ncol=2,byrow=T) #variance covariance matrix of the bivariate normal random variables
f2=function(x)
u=cbind(cos(x),sin(x))
a=drop((u)%*%solve(var.cov)%*%t(u))
b=drop((u)%*%solve(var.cov)%*%(mu))
c=drop(-0.5*t(mu)%*%solve(var.cov)%*%mu)
d=drop(b/sqrt(a))
aa=(cos(x))*(1/(2*pi*a*sqrt(det(var.cov))))*exp(c)*(1+((d*pnorm(d))/dnorm(d)))
return(aa)
curve.circular(f2,from=0,to=2*pi,n=101)
the problem is that I get error messages:
Error in lines.circular(x, y, ...) : object 'll' not found
In addition: Warning message:
In sqrt(a) : NaNs produced
I do not know how to deal with that error
r
I'm not familiar withlibrary(circular)
. But if we addaa <- aa[,1:2]
beforereturn(aa)
, your function will work untilaa <- aa[,1:50]
after that it will fail. Try to usebrowser()
inside your function to check if it behaves as you expected.
– A. Suliman
Mar 24 at 12:42
add a comment |
I need to plot the circular density defined in function (f2) in the following R code
library(circular)
mu=c(1,1.166) # true values of the mean vector of bivariate normal variables
var.1 =1.096# sigma.1.squared for first normal variable
var.2=1#sigma.2.squared of second normal variable
cov.1.2=-0.31 # covariance between the two normal variables
var.cov<-matrix(c(var.1,cov.1.2,cov.1.2,var.2),nrow=2,ncol=2,byrow=T) #variance covariance matrix of the bivariate normal random variables
f2=function(x)
u=cbind(cos(x),sin(x))
a=drop((u)%*%solve(var.cov)%*%t(u))
b=drop((u)%*%solve(var.cov)%*%(mu))
c=drop(-0.5*t(mu)%*%solve(var.cov)%*%mu)
d=drop(b/sqrt(a))
aa=(cos(x))*(1/(2*pi*a*sqrt(det(var.cov))))*exp(c)*(1+((d*pnorm(d))/dnorm(d)))
return(aa)
curve.circular(f2,from=0,to=2*pi,n=101)
the problem is that I get error messages:
Error in lines.circular(x, y, ...) : object 'll' not found
In addition: Warning message:
In sqrt(a) : NaNs produced
I do not know how to deal with that error
r
I need to plot the circular density defined in function (f2) in the following R code
library(circular)
mu=c(1,1.166) # true values of the mean vector of bivariate normal variables
var.1 =1.096# sigma.1.squared for first normal variable
var.2=1#sigma.2.squared of second normal variable
cov.1.2=-0.31 # covariance between the two normal variables
var.cov<-matrix(c(var.1,cov.1.2,cov.1.2,var.2),nrow=2,ncol=2,byrow=T) #variance covariance matrix of the bivariate normal random variables
f2=function(x)
u=cbind(cos(x),sin(x))
a=drop((u)%*%solve(var.cov)%*%t(u))
b=drop((u)%*%solve(var.cov)%*%(mu))
c=drop(-0.5*t(mu)%*%solve(var.cov)%*%mu)
d=drop(b/sqrt(a))
aa=(cos(x))*(1/(2*pi*a*sqrt(det(var.cov))))*exp(c)*(1+((d*pnorm(d))/dnorm(d)))
return(aa)
curve.circular(f2,from=0,to=2*pi,n=101)
the problem is that I get error messages:
Error in lines.circular(x, y, ...) : object 'll' not found
In addition: Warning message:
In sqrt(a) : NaNs produced
I do not know how to deal with that error
r
r
edited Mar 24 at 12:42
A. Suliman
6,62341225
6,62341225
asked Mar 24 at 11:42
Amani Abu BakrAmani Abu Bakr
13
13
I'm not familiar withlibrary(circular)
. But if we addaa <- aa[,1:2]
beforereturn(aa)
, your function will work untilaa <- aa[,1:50]
after that it will fail. Try to usebrowser()
inside your function to check if it behaves as you expected.
– A. Suliman
Mar 24 at 12:42
add a comment |
I'm not familiar withlibrary(circular)
. But if we addaa <- aa[,1:2]
beforereturn(aa)
, your function will work untilaa <- aa[,1:50]
after that it will fail. Try to usebrowser()
inside your function to check if it behaves as you expected.
– A. Suliman
Mar 24 at 12:42
I'm not familiar with
library(circular)
. But if we add aa <- aa[,1:2]
before return(aa)
, your function will work until aa <- aa[,1:50]
after that it will fail. Try to use browser()
inside your function to check if it behaves as you expected.– A. Suliman
Mar 24 at 12:42
I'm not familiar with
library(circular)
. But if we add aa <- aa[,1:2]
before return(aa)
, your function will work until aa <- aa[,1:50]
after that it will fail. Try to use browser()
inside your function to check if it behaves as you expected.– A. Suliman
Mar 24 at 12:42
add a comment |
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I'm not familiar with
library(circular)
. But if we addaa <- aa[,1:2]
beforereturn(aa)
, your function will work untilaa <- aa[,1:50]
after that it will fail. Try to usebrowser()
inside your function to check if it behaves as you expected.– A. Suliman
Mar 24 at 12:42